/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 70 If \(X\) has an exponential dist... [FREE SOLUTION] | 91Ó°ÊÓ

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If \(X\) has an exponential distribution with parameter \(\lambda\), derive a general expression for the \((100 p)\) th percentile of the distribution. Then specialize to obtain the median.

Short Answer

Expert verified
The 50th percentile (median) is \(\frac{\ln(2)}{\lambda}\).

Step by step solution

01

Understanding Exponential Distribution

The exponential distribution is defined by its probability density function (pdf), which is given by: \(f(x; \lambda) = \lambda e^{-\lambda x}\) for \(x \geq 0\), where \(\lambda > 0\) is the rate parameter. It is important to understand the distribution before proceeding to find the percentile.
02

Defining the Cumulative Distribution Function (CDF)

The cumulative distribution function (CDF) for an exponential distribution is given by \(F(x) = 1 - e^{-\lambda x}\). The CDF gives the probability that a random variable \(X\) is less than or equal to \(x\).
03

Setting the Percentile Function

We need to find the \((100p)\)th percentile, which is the value \(x_p\) such that the probability of \(X \leq x_p\) is \(p\). Therefore, we set \(F(x_p) = p\). Substituting the CDF of the exponential distribution in, we have \(1 - e^{-\lambda x_p} = p\).
04

Solving for the Percentile

Rearrange the equation \(1 - e^{-\lambda x_p} = p\) to solve for \(x_p\). We get \(e^{-\lambda x_p} = 1 - p\). Taking the natural logarithm on both sides, we obtain \(-\lambda x_p = \ln(1 - p)\). Finally, solve for \(x_p\) to get \(x_p = -\frac{\ln(1 - p)}{\lambda}\).
05

Finding the Median

The median of a distribution is the 50th percentile, which corresponds to \(p = 0.5\). Substitute \(p = 0.5\) into the expression for \(x_p\) to find the median. Hence, \(x_{0.5} = -\frac{\ln(1 - 0.5)}{\lambda} = -\frac{\ln(0.5)}{\lambda} = \frac{\ln(2)}{\lambda}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Percentile Calculation
In the realm of the exponential distribution, finding percentiles is a crucial task. A percentile tells us the value below which a given percentage of observations fall. When dealing with the exponential distribution characterized by the parameter \( \lambda \), the \((100p)\)th percentile can be located using the cumulative distribution function (CDF).
To find the \((100p)\)th percentile, denoted as \( x_p \), we solve the equation given by the CDF \( F(x) = 1 - e^{-\lambda x} \) for \( F(x_p) = p \). This equation equates to \( 1 - e^{-\lambda x_p} = p \).
By rearranging this equation to solve for \( x_p \), we find \[ x_p = -\frac{\ln(1 - p)}{\lambda} \].
This formula allows us to determine specific percentile values in any exponential distribution, customizing our insights based on chosen probabilities.
Probability Density Function
The probability density function (PDF) forms the backbone of understanding any distribution, including the exponential distribution. The PDF provides insights into the likelihood of a random variable taking on a specific value.
For the exponential distribution, the PDF is expressed as \( f(x; \lambda) = \lambda e^{-\lambda x} \) for \( x \geq 0 \), where \( \lambda > 0 \) is the rate parameter.
This rate parameter, \( \lambda \), influences the slope of the distribution. Here are some key properties of the exponential PDF:
  • The PDF is always positive or zero since \( e^{-\lambda x} \) is never negative.
  • The exponential curve declines as \( x \) increases, reflecting a property known as the "memoryless" characteristic, which implies that the distribution does not recall the past.
  • The area under the curve of the PDF equals 1, representing the total probability.
Understanding the PDF helps one grasp how probabilities are distributed across possible values of the random variable.
Cumulative Distribution Function
The cumulative distribution function (CDF) of the exponential distribution complements the PDF by illustrating the probability that a random variable is less than or equal to a given value \( x \). The CDF is expressed as:
\( F(x) = 1 - e^{-\lambda x} \).
This function conveys several intuitive aspects:
  • As \( x \) increases, \( F(x) \) increases, mirroring the increasing probability of observing a value less than or equal to \( x \).
  • When \( x = 0 \), \( F(0) = 0 \). This means the smallest possible value has no probability accumulated.
  • As \( x \) approaches infinity, \( F(x) \) approaches 1, indicating that the total probability is 1.
The exponential CDF provides an easy way to perform percentile calculations and analyze the distribution's behavior over a range.
Median of Exponential Distribution
The median serves as a central measure of a distribution, dividing the probability into two equal halves. For the exponential distribution, finding the median involves determining the 50th percentile. Given the derived formula for percentiles, \( x_p = -\frac{\ln(1 - p)}{\lambda} \), we set \( p = 0.5 \) to find the median.
This gives us:
\[ x_{0.5} = -\frac{\ln(1 - 0.5)}{\lambda} = \frac{\ln(2)}{\lambda} \].
The median thus expresses the point where half the observations fall below and half above this value. It is a useful statistical measure since it reflects the distribution's central tendency without being skewed by outliers, unlike the mean.

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