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Extensive experience with fans of a certain type used in diesel engines has suggested that the exponential distribution provides a good model for time until failure. Suppose the mean time until failure is 25,000 hours. What is the probability that a. A randomly selected fan will last at least 20,000 hours? At most 30,000 hours? Between 20,000 and 30,000 hours? b. The lifetime of a fan exceeds the mean value by more than 2 standard deviations? More than 3 standard deviations?

Short Answer

Expert verified
a. P(T≥20,000) = 0.4493, P(T≤30,000) = 0.695, P(20,000≤T≤30,000) = 0.2457. b. P(T>75,000) = 0.1353, P(T>100,000) = 0.0498.

Step by step solution

01

Define the Probability Distribution

The problem states that the time until failure is modeled by an exponential distribution. This can be mathematically expressed as \( f(t; \lambda) = \lambda e^{-\lambda t} \), where \( \lambda \) is the rate parameter. The mean of an exponential distribution is given by \( \frac{1}{\lambda} \). Here, the mean is 25,000 hours, so \( \lambda = \frac{1}{25000} \).
02

Compute Standard Deviation

The standard deviation for an exponential distribution is the same as its mean, so the standard deviation here is also 25,000 hours.
03

Find P(T ≥ 20,000)

For an exponential distribution, the cumulative distribution function is \( F(t) = 1 - e^{-\lambda t} \). The probability that a randomly selected fan lasts at least 20,000 hours is given by \( P(T \geq 20000) = 1 - F(20000) \). So, \( P(T \geq 20000) = e^{-\lambda \times 20000} = e^{-\frac{20000}{25000}} \).
04

Calculate P(T ≤ 30,000)

Using the cumulative distribution function, the probability that a fan lasts at most 30,000 hours is \( P(T \leq 30000) = F(30000) = 1 - e^{-\lambda \times 30000} = 1 - e^{-\frac{30000}{25000}} \).
05

Determine P(20,000 ≤ T ≤ 30,000)

This probability is calculated by subtracting \( P(T \leq 20000) \) from \( P(T \leq 30000) \). Thus, \( P(20000 \leq T \leq 30000) = F(30000) - F(20000) = (1 - e^{-\frac{30000}{25000}}) - (1 - e^{-\frac{20000}{25000}}) \).
06

Calculate P(T > μ + 2σ)

For \( T > \mu + 2\sigma \), substitute \( \mu = 25000 \) and \( \sigma = 25000 \) into \( T > 25000 + 2 \times 25000 = 75000 \). Thus, \( P(T > 75000) = e^{-\lambda \times 75000} = e^{-\frac{75000}{25000}} \).
07

Calculate P(T > μ + 3σ)

Similarly, for \( T > \mu + 3\sigma \), substitute \( \mu = 25000 \) and \( \sigma = 25000 \) into \( T > 25000 + 3 \times 25000 = 100000 \). Thus, \( P(T > 100000) = e^{-\lambda \times 100000} = e^{-\frac{100000}{25000}} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability and Statistics
Exponential distribution is a key concept in probability and statistics, particularly handy for modeling the time between events in processes that are memoryless. When we talk about something like the time until failure of a machine part, the exponential distribution can often provide a neat fit.
It is characterized by its constant hazard rate, denoted as \( \lambda \), and can be described using the probability density function (PDF) \( f(t; \lambda) = \lambda e^{-\lambda t} \). Here, \( \lambda \) is a rate parameter that essentially dictates how quickly failures are expected to occur.

This leads us to another tool called the cumulative distribution function (CDF), represented as \( F(t) = 1 - e^{-\lambda t} \).
  • To find the probability that an event occurs within a certain time frame, you use the CDF.
  • For example, if you want to know the probability that a fan fails within 30,000 hours, you compute \( F(30000) \).
Understanding these functions is crucial. They offer insights into the likelihood of different outcomes in a given time period, helping you to make informed decisions about reliability and risk.
Time Until Failure Analysis
Time until failure analysis is pivotal in industries where equipment reliability is paramount. This analysis uses statistical methods to predict when a piece of equipment might fail, based on previous data and a clear understanding of the processes involved.
By utilizing the exponential distribution, analysts can simplify this task. The memoryless property is particularly significant, as it means that the probability of failure in the next instant is the same regardless of how long the component has already functioned.

This simplifies calculations, such as finding the probability that a fan lasts more than a certain number of hours.
  • The idea is that even though a machine has run for 20,000 hours, the likelihood of it running between 20,000 and 30,000 more hours is calculated fresh, using the exponential distribution model.
  • In our context, calculating probabilities such as \( P(T \geq 20000) \) or \( P(20000 \leq T \leq 30000) \) becomes straightforward, making it easier to perform maintenance planning and life cycle cost analysis.
These calculations prepare industries to mitigate risks by forecasting possible future failures and employing proactive maintenance strategies.
Standard Deviation Calculation
In statistical terms, standard deviation offers a measure of the amount of variation or dispersion in a set of values. When working with an exponential distribution, one of the simplifying characteristics is that the standard deviation is equal to the mean.
In our exercise, the mean time until failure is 25,000 hours, which directly tells us that the standard deviation is also 25,000 hours.

This information is especially useful when calculating the probability of extreme events.
  • For example, in situations where you're analysing whether a fan's life exceeds the mean by more than two or three standard deviations, they translate into specific time frames.
  • Precisely, \( T > \mu + 2\sigma \) calculates as more than 75,000 hours and \( T > \mu + 3\sigma \) as more than 100,000 hours.
Such calculations make it straightforward to assess risk and assure that the equipment is functioning well within expected parameters. They also shape how companies plan for potential disruptions, ensuring parts are replaced or serviced at optimal times.

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