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Automobiles arrive at a vehicle equipment inspection station according to a Poisson process with rate \(\alpha=10\) per hour. Suppose that with probability \(.5\) an arriving vehicle will have no equipment violations. a. What is the probability that exactly ten arrive during the hour and all ten have no violations?

Short Answer

Expert verified
The probability is approximately 0.000122.

Step by step solution

01

Understanding the Poisson process

The exercise states that automobiles arrive according to a Poisson process with a rate of \( \alpha = 10 \) arrivals per hour. A Poisson process describes the probability of a number of events (arrivals) occurring within a fixed interval of time.
02

Poisson Probability Formula

The formula for the probability of observing \( k \) events in a Poisson process is given by: \[ P(X = k) = \frac{ \lambda^k e^{-\lambda} }{ k! } \] where \( \lambda \) is the average rate (10 cars per hour), \( k \) is the number of events (cars) we are interested in, and \( e \) is the base of the natural logarithm.
03

Calculate probability of exactly 10 arrivals

We need to calculate the probability of exactly 10 cars arriving in an hour. Using the Poisson formula, we substitute \( \lambda = 10 \) and \( k = 10 \): \[ P(X = 10) = \frac{ 10^{10} e^{-10} }{ 10! } \] Calculate this to get: \[ P(X = 10) \approx 0.1251 \] (approximately).
04

Probability of no equipment violations

With probability 0.5, an arriving vehicle will have no equipment violations. Since we want all 10 vehicles to have no violations, we use the formula for binomial probability: \[ P(Y = 10) = 0.5^{10} \] Calculate this to get: \[ P(Y = 10) \approx 0.0009766 \] (approximately).
05

Combine Poisson and Binomial Probabilities

To find the probability that exactly 10 cars arrive and all 10 have no violations, multiply the probability of exactly 10 arrivals by the probability that all 10 have no violations: \[ P(\text{10 arrivals, no violations}) = P(X = 10) \times P(Y = 10) \] This gives: \[ 0.1251 \times 0.0009766 \approx 0.000122 \]
06

Final Result

The probability that exactly 10 vehicles arrive in an hour and all of them have no equipment violations is approximately \(0.000122\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is the mathematical framework that allows us to model and analyze random events. It is the foundation for understanding likelihood, uncertainty, and predictability in various contexts, including the one described in our exercise. In this context, we are dealing with a static type of random process known as the Poisson process.

A Poisson process is particularly useful for modeling events that occur independently over a fixed period or in a specified space. This model assumes that events occur with a certain average rate which is constant over time. Here, the average rate \( \alpha \) is 10 automobile arrivals per hour. This means, over a long period, we would expect about ten cars per hour at the inspection station.

Understanding the properties and behavior of events in a Poisson process is essential in probability theory. It teaches us about the likelihood of a given number of events happening within a specified timeframe, which is vital for decision-making and logistical planning. Mastery of probability theory also paves the way for more complex statistical methods and applications.
Binomial Probability
Binomial probability is another key concept used in this exercise, helping to calculate the probability of a fixed number of successes in a set of independent trials. In this context, we define a "success" as a vehicle arriving with no equipment violations. The probability of such a "success" is given as 0.5 per vehicle.

The binomial probability formula is particularly fitting when the outcome of each trial (in our case, each vehicle) is binary, hence the name 'binomial.' It is expressed as:
  • \( P(Y = k) = \binom{n}{k}p^k(1-p)^{n-k} \)
In our example, \(n\) is the number of trials (vehicles), which is 10, \(p\) is the probability of no violations (0.5), and \(k\) is the number of desired "successes," also 10 in this particular problem.

Thus, the specific calculation employs \( p = 0.5 \) and cubic exponents to find the likelihood of all 10 cars passing with no violations, resulting in \( P(Y=10) = 0.5^{10} \). This is a simple demonstration of the binomial distribution at work, illustrating how it estimates the probability of clustered events (all success) happening together.
Statistical Analysis
Statistical analysis involves using concepts and formulas like those in probability theory and binomial probability to interpret and understand data events. In our exercise, statistical analysis integrates Poisson and binomial probabilities to solve the problem comprehensively.

The compound use of both probabilities is cleverly deployed by multiplying the independently calculated probability of exactly 10 car arrivals, by the probability that all 10 have no violations. This multiplication accounts for both the randomness in the arrival process and the independent success criteria per car, thus giving us the final probability of \( 0.000122 \).

Such analyses are crucial in various fields, ranging from quality control and logistics to finance and environmental science. By using statistical methods, decision makers can quantify and strategize around events that might impact operations. Assessing the likelihood of possible outcomes, based on existing conditions or historical data, helps in tailoring responses to expected patterns and preparing for uncertain events.

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Most popular questions from this chapter

Three couples and two single individuals have been invited to an investment seminar and have agreed to attend. Suppose the probability that any particular couple or individual arrives late is .4 (a couple will travel together in the same vehicle, so either both people will be on time or else both will arrive late). Assume that different couples and individuals are on time or late independently of one another. Let \(X=\) the number of people who arrive late for the seminar. a. Determine the probability mass function of \(X\). b. Obtain the cumulative distribution function of \(X\), and use it to calculate \(P(2 \leq X \leq 6)\).

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