/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 Compute the following binomial p... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Compute the following binomial probabilities directly from the formula for \(b(x ; n, p)\) : a. \(b(3 ; 8, .35)\) b. \(b(5 ; 8, .6)\) c. \(P(3 \leq X \leq 5)\) when \(n=7\) and \(p=.6\) d. \(P(1 \leq X)\) when \(n=9\) and \(p=.1\)

Short Answer

Expert verified
a) 0.2461, b) 0.2787, c) 0.5701, d) 0.6126

Step by step solution

01

Understand the Binomial Probability Formula

The binomial probability formula is given by \( b(x; n, p) = \binom{n}{x} p^x (1-p)^{n-x} \), where \( \binom{n}{x} \) is the binomial coefficient calculated as \( \frac{n!}{x!(n-x)!} \), \( n \) is the number of trials, \( x \) is the number of successes, and \( p \) is the probability of success on a single trial.
02

Calculate Part (a)

For \( b(3 ; 8, 0.35) \), substitute \( n = 8 \), \( x = 3 \), and \( p = 0.35 \) into the formula: \[ b(3 ; 8, 0.35) = \binom{8}{3} (0.35)^3 (0.65)^5 \]Calculate \( \binom{8}{3} = \frac{8 \times 7 \times 6}{3 \times 2 \times 1} = 56 \). Then compute: \[ 56 \times (0.35)^3 \times (0.65)^5 \approx 0.2461 \].
03

Calculate Part (b)

For \( b(5 ; 8, 0.6) \), substitute \( n = 8 \), \( x = 5 \), and \( p = 0.6 \):\[ b(5 ; 8, 0.6) = \binom{8}{5} (0.6)^5 (0.4)^3 \]Calculate \( \binom{8}{5} = \binom{8}{3} = 56 \) (by symmetry, since \( \binom{n}{k} = \binom{n}{n-k} \)). Compute: \[ 56 \times (0.6)^5 \times (0.4)^3 \approx 0.2787 \].
04

Calculate Part (c)

For \( P(3 \leq X \leq 5) \) when \( n = 7 \) and \( p = 0.6 \), we need to find:\[ b(3; 7, 0.6) + b(4; 7, 0.6) + b(5; 7, 0.6) \]Calculate each probability separately using the binomial formula and sum them.1. \( b(3; 7, 0.6) \approx 0.0595 \).2. \( b(4; 7, 0.6) \approx 0.1935 \).3. \( b(5; 7, 0.6) \approx 0.3171 \).Summing these gives \( P(3 \leq X \leq 5) \approx 0.5701 \).
05

Calculate Part (d)

For \( P(1 \leq X) \) when \( n = 9 \) and \( p = 0.1 \), note that:\[ P(1 \leq X) = 1 - P(X = 0) \]Compute \( P(X = 0) \) using the binomial formula:\[ P(X = 0) = b(0; 9, 0.1) = \binom{9}{0} (0.1)^0 (0.9)^9 = 0.9^9 \approx 0.3874 \]So, \( P(1 \leq X) \approx 1 - 0.3874 = 0.6126 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Coefficient
To understand the binomial probability distribution, we need to first grasp the concept of the binomial coefficient. The binomial coefficient, denoted as \( \binom{n}{x} \), represents the number of ways to choose \( x \) successes from \( n \) trials. It's similar to picking a subset from a collection. This is calculated using the formula:\[ \binom{n}{x} = \frac{n!}{x!(n-x)!} \]where \( n! \) (n factorial) is the product of all positive integers up to \( n \). For example, for \( \binom{8}{3} \), the calculation is \( \frac{8 \times 7 \times 6}{3 \times 2 \times 1} = 56 \) which means there are 56 different ways to choose 3 successes out of 8 trials. The binomial coefficient helps in determining the number of combinations possible, which is crucial for calculating probabilities in binomial distributions.
Probability of Success
In any binomial experiment, the probability of success is denoted by \( p \). This is the likelihood of a single trial resulting in a successful outcome. For instance, in a coin toss where heads are considered a success, \( p \) would be 0.5 because there's a 50% chance of getting heads.
The probability of failure, on the other hand, is given by \( 1-p \). Knowing these probabilities is essential when working with the binomial distribution formula as each trial is independent. In the exercise examples:
  • For calculation (a), the probability of success \( p = 0.35 \).
  • For calculation (b), \( p = 0.6 \).
  • These values are directly used in the formula to determine the likelihood of a certain number of successes in a series of trials.
Discrete Probability Distribution
A discrete probability distribution deals with variables that have specific and separate values. The Binomial Probability Distribution is a type of discrete probability distribution. It is used to describe the number of successes in a fixed number of binary (two possible outcomes) trials.
Key features include:
  • Each trial is independent.
  • The number of trials, \( n \), is fixed.
  • Outcomes are categorized as 'success' or 'failure'.
  • The probability of success, \( p \), is constant across trials.
Each combination of successes in different trials is calculated using the binomial distribution, making it a powerful tool for situations where outcomes are limited to two distinct types.
Binomial Distribution Formula
The binomial distribution formula is vital to compute the probability of achieving a certain number of successes in a given number of independent trials. The formula is expressed as:\[ b(x; n, p) = \binom{n}{x} p^x (1-p)^{n-x} \]This formula combines the binomial coefficient \( \binom{n}{x} \) with the probabilities of successes \( p^x \) and failures \( (1-p)^{n-x} \). For example, in the exercise:
  • To find \( b(3 ; 8, 0.35) \), substitute \( n = 8 \), \( x = 3 \), and \( p = 0.35 \) to yield the probability of exactly 3 successes out of 8 trials.
  • Each term represents a part of the process: \( \binom{8}{3} \) identifies ways to arrange successes; \( (0.35)^3 \) gives the probability of those successes; \( (1-0.35)^5 \) represents failures.
Doing these calculations accurately allows us to determine the probability of various outcomes in a binomial setting.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An educational consulting firm is trying to decide whether high school students who have never before used a handheld calculator can solve a certain type of problem more easily with a calculator that uses reverse Polish logic or one that does not use this logic. A sample of 25 students is selected and allowed to practice on both calculators. Then each student is asked to work one problem on the reverse Polish calculator and a similar problem on the other. Let \(p=P(S)\), where \(S\) indicates that a student worked the problem more quickly using reverse Polish logic than without, and let \(X=\) number of \(S\) 's. a. If \(p=.5\), what is \(P(7 \leq X \leq 18)\) ? b. If \(p=.8\), what is \(P(7 \leq X \leq 18)\) ? c. If the claim that \(p=.5\) is to be rejected when either \(X \leq\) 7 or \(X \geq 18\), what is the probability of rejecting the claim when it is actually correct? d. If the decision to reject the claim \(p=.5\) is made as in part (c), what is the probability that the claim is not rejected when \(p=.6\) ? When \(p=.8\) ? e. What decision rule would you choose for rejecting the claim \(p=.5\) if you wanted the probability in part (c) to be at most .01?

Grasshoppers are distributed at random in a large field according to a Poisson distribution with parameter \(\alpha=2\) per square yard. How large should the radius \(R\) of a circular sampling region be taken so that the probability of finding at least one in the region equals \(.99\) ?

Twenty pairs of individuals playing in a bridge tournament have been seeded \(1, \ldots, 20\). In the first part of the tournament, the 20 are randomly divided into 10 east-west pairs and 10 north-south pairs. a. What is the probability that \(x\) of the top 10 pairs end up playing east- west? b. What is the probability that all of the top five pairs end up playing the same direction? c. If there are \(2 n\) pairs, what is the pmf of \(X=\) the number among the top \(n\) pairs who end up playing east-west? What are \(E(X)\) and \(V(X)\) ?

A personnel director interviewing 11 senior engineers for four job openings has scheduled six interviews for the first day and five for the second day of interviewing. Assume that the candidates are interviewed in random order. a. What is the probability that \(x\) of the top four candidates are interviewed on the first day? b. How many of the top four candidates can be expected to be interviewed on the first day?

An ordinance requiring that a smoke detector be installed in all previously constructed houses has been in effect in a particular city for 1 year. The fire department is concerned that many houses remain without detectors. Let \(p=\) the true proportion of such houses having detectors, and suppose that a random sample of 25 homes is inspected. If the sample strongly indicates that fewer than \(80 \%\) of all houses have a detector, the fire department will campaign for a mandatory inspection program. Because of the costliness of the program, the department prefers not to call for such inspections unless sample evidence strongly argues for their necessity. Let \(X\) denote the number of homes with detectors among the 25 sampled. Consider rejecting the claim that \(p \geq .8\) if \(x \leq 15\). a. What is the probability that the claim is rejected when the actual value of \(p\) is \(.8\) ? b. What is the probability of not rejecting the claim when \(p=.7 ?\) When \(p=.6 ?\) c. How do the "error probabilities" of parts (a) and (b) change if the value 15 in the decision rule is replaced by 14 ?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.