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Let \(X=\) the number of nonzero digits in a randomly selected zip code. What are the possible values of \(X\) ? Give three possible outcomes and their associated \(X\) values.

Short Answer

Expert verified
Possible values of \(X\) are 0, 1, 2, 3, 4, or 5.

Step by step solution

01

Understanding the Problem

A zip code is composed of 5 digits. Each digit can be one of the numbers 0-9. Nonzero digits are any digit except 0. We need to determine how many nonzero digits can be present in a zip code.
02

Identifying Possible Values for X

Since a zip code has 5 digits, and each digit can be either 0 or a nonzero digit (1 to 9), the possible number of nonzero digits in any given zip code, denoted as \(X\), can range from 0 to 5.
03

Example 1: Zero Nonzero Digits

Consider the zip code 00000. In this case, there are no digits other than zero. Thus, \(X = 0\).
04

Example 2: Three Nonzero Digits

Consider the zip code 12009. This zip code has the digits 1, 2, and 9 as nonzero, totaling 3 nonzero digits. Thus, \(X = 3\).
05

Example 3: Five Nonzero Digits

Consider the zip code 98765. This zip code has all of its digits as nonzero, totaling 5 nonzero digits. Thus, \(X = 5\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Distributions
In the context of our zip code example, a probability distribution is a function that describes the likelihood of each possible number of nonzero digits, represented by \(X\), occurring in a randomly selected zip code. In simpler terms, it's about understanding how likely it is to find a zip code with 0, 1, 2, 3, 4, or 5 nonzero digits.

To construct a probability distribution for \(X\), we would need to look at all possible zip code combinations and calculate the probability of each possible value of \(X\). The fundamental requirements for a probability distribution are that the probabilities must be non-negative and sum up to 1.
  • Each zip code is a combination of 5 digits where each digit can be between 0 and 9.
  • The probability distribution might change depending on assumptions like whether each digit is equally likely.
  • In our scenario, if each digit selection is independent, each digit has a 10% chance of being 0—impacting the overall distribution of \(X\).
Understanding this helps us make informed decisions or predictions about random samples, like estimating how often zip codes with an unusual pattern (like all zeros) might appear.
Random Experiments
A random experiment is any situation where we have some form of uncertainty about the outcome. Pulling a zip code at random, as discussed in our exercise, is an example of a random experiment. Here are some key aspects:

- **Outcome**: Each different zip code, such as 00000 or 12345, represents a unique outcome of our experiment.
- **Sample Space**: This includes all 100,000 possible combinations of 5 digits (00000 to 99999).
- **Event**: An event could be several outcomes combined. For instance, the event "\(X = 3\)" includes all zip codes that have exactly three nonzero digits, like 12009 or 00134.
  • Random experiments help us analyze and make predictions about the likelihood of each event.
  • They are essential for understanding how we model real-world situations in probability and statistics.
  • Each random outcome helps us measure and subsequently calculate the probabilities involved in the possible values of \(X\).
By applying these concepts, we better comprehend the likelihood of various numbers of nonzero digits in zip codes.
Combinatorics
Combinatorics is a field of mathematics that deals with counting, arranging, and finding patterns. It's used in our exercise to determine the number of ways nonzero digits can appear in zip codes.

With zip codes consisting of five digits, we explore:
  • How many ways can we arrange zero to five nonzero digits in these positions?
  • Combinatorial calculations help illustrate, for example, the number of zip codes with exactly three nonzero digits.
  • For example, selecting positions for nonzero digits can be managed using combinations.
  • If there are \(k\) positions to fill with nonzero digits out 5, we use the binomial coefficient \(\binom{5}{k}\) to calculate possible arrangements for selecting these positions.
  • We then multiply by the number of ways to fill these positions with nonzero digits (1-9).
Combinatorics provides the tools to systematically and efficiently count these possibilities, bridging the gap between possible events and their probabilities.

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Most popular questions from this chapter

Customers at a gas station pay with a credit card \((A)\), debit card \((B)\), or cash \((C)\). Assume that successive customers make independent choices, with \(P(A)=.5, P(B)=.2\), and \(P(C)=.3 .\) a. Among the next 100 customers, what are the mean and variance of the number who pay with a debit card? Explain your reasoning. b. Answer part (a) for the number among the 100 who don't pay with cash.

A company that produces fine crystal knows from experience that \(10 \%\) of its goblets have cosmetic flaws and must be classified as "seconds." a. Among six randomly selected goblets, how likely is it that only one is a second? b. Among six randomly selected goblets, what is the probability that at least two are seconds? c. If goblets are examined one by one, what is the probability that at most five must be selected to find four that are not seconds?

A toll bridge charges \(\$ 1.00\) for passenger cars and \(\$ 2.50\) for other vehicles. Suppose that during daytime hours, \(60 \%\) of all vehicles are passenger cars. If 25 vehicles cross the bridge during a particular daytime period, what is the resulting expected toll revenue?

A friend recently planned a camping trip. He had two flashlights, one that required a single 6-V battery and another that used two size-D batteries. He had previously packed two 6-V and four size-D batteries in his camper. Suppose the probability that any particular battery works is \(p\) and that batteries work or fail independently of one another. Our friend wants to take just one flashlight. For what values of \(p\) should he take the 6-V flashlight?

An article in the Los Angeles Times (Dec. 3, 1993) reports that 1 in 200 people carry the defective gene that causes inherited colon cancer. In a sample of 1000 individuals, what is the approximate distribution of the number who carry this gene? Use this distribution to calculate the approximate probability that a. Between 5 and 8 (inclusive) carry the gene. b. At least 8 carry the gene.

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