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One box contains six red balls and four green balls, and a second box contains seven red balls and three green balls. A ball is randomly chosen from the first box and placed in the second box. Then a ball is randomly selected from the second box and placed in the first box. a. What is the probability that a red ball is selected from the first box and a red ball is selected from the second box? b. At the conclusion of the selection process, what is the probability that the numbers of red and green balls in the first box are identical to the numbers at the beginning?

Short Answer

Expert verified
a. \( \frac{24}{55} \approx 0.436 \), b. \( \frac{27}{55} \approx 0.491 \).

Step by step solution

01

Identify initial conditions

Box 1 has 6 red and 4 green balls. Box 2 has 7 red and 3 green balls. The exercise involves moving balls between these boxes.
02

Calculate probability of selecting a red ball from Box 1

The probability of selecting a red ball from Box 1 is the number of red balls divided by the total number of balls: \( \frac{6}{10} = 0.6 \).
03

Determine new distribution in Box 2 if a red ball is moved

If a red ball is moved from Box 1 to Box 2, Box 2 will have 8 red and 3 green balls, totaling 11 balls: 7 + 1 red, 3 green.
04

Calculate probability of selecting a red ball from Box 2 after moving a red one

The probability of selecting a red ball from Box 2 with the new distribution is \( \frac{8}{11} \).
05

Compute probability for red-red scenario

The probability that a red ball is selected from both Box 1 and subsequently Box 2 is obtained by multiplying the probabilities from Steps 2 and 4: \( 0.6 \times \frac{8}{11} = \frac{24}{55} \approx 0.436 \).
06

Calculate probability of selecting a green ball from Box 1

The probability of selecting a green ball from Box 1 is \( \frac{4}{10} = 0.4 \).
07

Determine new distribution in Box 2 if a green ball is moved

If a green ball is moved from Box 1 to Box 2, Box 2 will have 7 red and 4 green balls, totaling 11 balls: 7 red, 3 + 1 green.
08

Calculate probability of selecting a red ball from Box 2 after moving a green one

Now, the probability of selecting a red ball from Box 2 with this new distribution is \( \frac{7}{11} \).
09

Compute probability for green-red scenario

The probability that a green ball is selected from Box 1 and then a red ball from Box 2 is \( 0.4 \times \frac{7}{11} = \frac{28}{110} = \frac{14}{55} \approx 0.255 \).
10

Sum probabilities for question (a)

For question (a), only the red-red scenario is needed: \( \frac{24}{55} \approx 0.436 \).
11

Find initial condition preservation probability (question b)

For the numbers to remain unchanged, either a red ball is exchanged for a red, or a green for a green, totaling the probability: \( (\frac{6}{10} \times \frac{7}{11}) + (\frac{4}{10} \times \frac{3}{11}) = \frac{42}{110} + \frac{12}{110} = \frac{54}{110} = \frac{27}{55} \approx 0.491 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Conditional probability is a key concept in probability, describing the likelihood of an event occurring given that another event has already taken place. In our ball selection problem, conditional probability allows us to find the chance of selecting a red ball from the second box given we've already chosen one from the first box.
The formula for conditional probability is:
  • \( P(A | B) = \frac{P(A \cap B)}{P(B)} \)
This formula expresses the probability of event A happening given event B has occurred (written as \( P(A | B) \)) in terms of the probability of both events occurring (\( P(A \cap B) \)) and the probability of event B.
In the context of our exercise, if we first picked a red ball from Box 1, the composition of balls in Box 2 changes, impacting the probabilities of subsequent selections. Thus, each step affects the next, and calculations need adjustments along the way.
Combinatorial Analysis
Combinatorial analysis is a method used to solve problems involving the selection of objects. It often results in a count of the number of possible outcomes, helping determine probabilities.
For our exercise, combinatorial reasoning helps us calculate the number of possible ball arrangements when transferring from one box to another. Using these calculations, we understand how many favorable outcomes exist compared to total outcomes.
Here are steps to apply combinatorial analysis:
  • Count possible configurations: Before choosing any ball, understand the total possible configurations and outcomes of moving balls between boxes.
  • Adjust for transfers: Recognize that moving a ball changes the state, so consider new arrangements for later selections.
  • Calculate probabilities from arrangements: Use the new configurations to determine probabilities of interest by dividing favorable outcomes by the total arrangements.
This type of analysis is pivotal in determining the probability of drawing a red ball after several transfers between boxes.
Random Events
In probability theory, random events are outcomes that happen without a deterministic pattern. They are essential for studying situations where outcomes are uncertain, like the ball selection in our problem.
Random events have:
  • Randomness: Each event has no predictable outcome, and each ball chosen is a random draw, unaffected by previous selections once reset.
  • Outcomes: Each random event results in one out of multiple possible outcomes, such as selecting a red or green ball.
  • Probability distribution: This describes the likelihood of each outcome, influenced by the composition of objects or occurrences, like the number of red vs. green balls.
In games of chance or exercises involving randomness, understanding these foundational elements of random events helps predict and calculate outcomes, empowering learners to appreciate the role of chance in mathematical models.

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