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A study of sterility in the fruit fly ("Mybrid Dysgenesis in Drosophila melanogaster: The Biolazy of Female and Male Sterility," Genetics, 1979: 161-174) reports the following data on the number of ovaries developed for each female fly in a sample of size 1388 . One model for unilateral sterility states that each ovary develops with some probability \(p\) independently of the other rvary. Test the fit of this model using \(x^{2}\). \begin{tabular}{l|ccc} \(x=\) Number of & & & \\ Ovaries Developed & 0 & 1 & 2 \\ \hline Ohserved Count & 1212 & 118 & 58 \end{tabular}

Short Answer

Expert verified
The model does not fit well; reject the unilateral sterility model.

Step by step solution

01

Define the Hypotheses

We are testing the fit of the unilateral sterility model. Under the null hypothesis, each ovary develops independently with probability \( p \). The alternative hypothesis is that the development does not follow this model.
02

Calculate Expected Counts

We first need the probability \( p \) that an ovary develops. From the total count: \( 2 \times 1388 = 2776 \) ovaries, of which \( 2 \times 58 + 118 = 234 \) developed. Thus, \( \hat{p} = \frac{234}{2776} \). The expected counts for 0, 1, and 2 developed ovaries can then be calculated as follows: for 0 ovaries, it is \((1 - \hat{p})^2 \times 1388\); for 1 ovary, it is \(2 \times \hat{p} \times (1 - \hat{p}) \times 1388\); for 2 ovaries, it is \(\hat{p}^2 \times 1388\).
03

Compute Expected Probabilities and Counts

First calculate \( \hat{p} = \frac{234}{2776} \approx 0.0843 \). Using this, calculate expected probabilities as follows: \((1 - \hat{p})^2 \approx 0.8389\), \(2 \cdot \hat{p} \cdot (1 - \hat{p}) \approx 0.1543\), and \(\hat{p}^2 \approx 0.0071\). Multiply these probabilities by 1388 to get expected counts: for 0 ovaries: \(1163.58\), for 1 ovary: \(214.1\), for 2 ovaries: \(9.8\).
04

Chi-Squared Test Calculation

Use the formula \[ \chi^2 = \sum \frac{(O_i - E_i)^2}{E_i} \] where \( O_i \) is the observed count and \( E_i \) is the expected count for each category. Compute for the three categories: \( \chi^2 = \frac{(1212 - 1163.58)^2}{1163.58} + \frac{(118 - 214.1)^2}{214.1} + \frac{(58 - 9.8)^2}{9.8} \).
05

Compare with Critical Value

With 2 degrees of freedom (number of categories - 1), compare the calculated \( \chi^2 \) value to the critical value from the chi-squared distribution table at a typical significance level (\( \alpha = 0.05 \)). If the calculated \( \chi^2 \) is greater than the critical value, reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unilateral Sterility
Unilateral sterility is a biological model used to describe the development of certain traits in organisms, such as fruit flies. In the context of this study, unilateral sterility refers to the situation where each ovary develops independently. This means that the presence of one developed ovary does not influence the other. This concept assumes that the probability of development is the same for each ovary, and this probability is denoted by the parameter \( p \).

In experiments involving Drosophila melanogaster, scientists assess whether this independence of ovary development holds true. If the model of unilateral sterility is correct, we would observe a certain distribution of developed and undeveloped ovaries that fits the model's predictions. This allows researchers to use statistical methods to test the accuracy of the model by comparing observed outcomes with expected outcomes.
Hypothesis Testing
When studying unilateral sterility in Drosophila melanogaster, hypothesis testing helps determine if the observed data fits the proposed model. Generally, hypothesis testing follows a structured process to provide clarity in decision-making.

First, define the null hypothesis (\( H_0 \)) and the alternative hypothesis (\( H_a \)). Here, the null hypothesis suggests that ovary development occurs independently with a probability \( p \) as proposed by the unilateral sterility model. Consequently, the alternative hypothesis contends that the development does not fit this model.
  • The null hypothesis assumes a specific distribution follows the model.
  • The alternative suggests variance from the predicted distribution.

Next, calculate a test statistic using the given data. Compare this test statistic against a critical value derived from statistical tables to determine whether to reject the null hypothesis. If the data falls significantly below or above the predicted range, we reject the null hypothesis, indicating a poor fit of the model.
Expected Counts
Expected counts are crucial in statistical tests, particularly the chi-squared test. These counts predict how frequently each outcome should occur under the null hypothesis. By comparing observed counts to expected counts, we assess how well the data conforms to theoretical expectations.

To calculate expected counts in this exercise, obtain the probability \( \hat{p} \) of an ovary developing. This involves dividing the total number of developed ovaries by the total possible number of ovaries. Once \( \hat{p} \) is determined, find the expected probabilities for the development of 0, 1, or 2 ovaries.

Use the binomial distribution to compute these probabilities:
  • For 0 developed ovaries: \((1 - \hat{p})^2\).
  • For 1 developed ovary: \(2 \times \hat{p} \times (1 - \hat{p})\).
  • For 2 developed ovaries: \(\hat{p}^2\).

Multiply these probabilities by the total sample size to get the expected counts. These expected counts are then used to calculate the chi-squared statistic, directly influencing hypothesis testing.
Drosophila melanogaster
Drosophila melanogaster, commonly known as the fruit fly, is a species extensively used in genetic research. Known for its simple genetic makeup and short breeding cycles, it serves as an ideal organism for studying inheritance patterns, including sterility. Scientists have long been fascinated by these small flies due to their practicality in observing genetic phenomena.

The fruit fly's genome was one of the first to be entirely mapped, which has made it a cornerstone in the field of genetics. This organism provides insights into the mechanisms of heredity and genetic mutations.
  • Drosophila melanogaster is model for genetic and developmental biology studies.
  • Experiments on this species help in understanding wider biological processes applicable to other organisms.

Understanding unilateral sterility in Drosophila melanogaster contributes to our knowledge of genetic independence and the effects of genetic variation.

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Most popular questions from this chapter

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