/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 Let \(y=\) sales at a fast-food ... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(y=\) sales at a fast-food outlet (1000s of \(\$$ ), \)x_{1}=\( number of competing outlets within a 1 -mile radius, \)x_{2}=\( population within a l-mile radius (1000s of people), and \)x_{3}\( be an indicator variable that equals 1 if the outlet has a drive-up window and 0 otherwise. Suppose that the true regression model is $$ Y=10.00-1.2 x_{1}+6.8 x_{2}+15.3 x_{3}+\epsilon $$ a. What is the mean value of sales when the number of competing outlets is 2 , there are 8000 people within a 1 -mile radius, and the outlet has a drive-up window? b. What is the mean value of sales for an outlet without a drive-up window that has three competing outlets and 5000 people within a I-mile radius? c. Interpret \)\beta_{3}$.

Short Answer

Expert verified
a. Mean sales: $77,300. b. Mean sales: $40,400. c. \(\beta_3\) adds $15,300 in sales with a drive-up window.

Step by step solution

01

Identify Model Parameters

The regression model is given by: \[ Y = 10.00 - 1.2 x_1 + 6.8 x_2 + 15.3 x_3 + \epsilon \] where \( x_1 \) is the number of competing outlets, \( x_2 \) is the population in thousands, and \( x_3 \) is the drive-up window indicator. We want to find the mean sales when given specific values for \( x_1, x_2, \) and \( x_3 \).
02

Calculate Mean Sales for Situation A

To find the mean value of sales when there are 2 competing outlets, a population of 8000, and a drive-up window: - \( x_1 = 2 \)- \( x_2 = 8000 \) people, which is \( 8 \) in thousands- \( x_3 = 1 \) because there is a drive-up window.Substitute these values into the regression equation:\[ Y = 10.00 - 1.2(2) + 6.8(8) + 15.3(1) \]Simplifying this, we get:\[ Y = 10.00 - 2.4 + 54.4 + 15.3 = 77.3 \] (in thousands of dollars)
03

Calculate Mean Sales for Situation B

Find the mean value of sales for an outlet without a drive-up window, with three competing outlets, and 5000 people.- \( x_1 = 3 \)- \( x_2 = 5000 \) people, which is \( 5 \) in thousands- \( x_3 = 0 \) since there is no drive-up window.Substitute these into the model:\[ Y = 10.00 - 1.2(3) + 6.8(5) + 15.3(0) \]This simplifies to:\[ Y = 10.00 - 3.6 + 34.0 = 40.4 \] (in thousands of dollars)
04

Interpret Coefficient \( \beta_3 \)

The coefficient \( \beta_3 = 15.3 \) indicates the additional increase in mean sales (in thousands of dollars) when the outlet has a drive-up window compared to one that does not, assuming all other factors remain constant. The presence of a drive-up window is expected to increase sales by $15,300.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Indicator Variable
In regression analysis, an indicator variable, also known as a dummy variable, is a numerical tool used to represent categorical data. It helps translate qualitative attributes into a numerical format for analysis in a regression model.
In the context of our exercise, the indicator variable, denoted as \(x_3\), takes on the value of 1 when the fast-food outlet has a drive-up window and 0 otherwise. This binary representation allows the model to recognize and incorporate the qualitative feature of whether an outlet has a drive-up window.
This approach enables precise impact analysis of such categorical variables on the dependent variable, in this case, sales.
Regression Model
A regression model is a statistical method used to describe the relationship between a dependent variable and one or more independent variables. It helps us predict the outcome variable based on the known values of other variables.
In our scenario, the regression model is expressed as \( Y = 10.00 - 1.2 x_1 + 6.8 x_2 + 15.3 x_3 + \epsilon \). Here, the model serves to predict sales, \( Y \), considering variables like the number of competing outlets \( x_1 \), population \( x_2 \), and if the outlet has a drive-up window \( x_3 \).
The model coefficients illustrate how much \( Y \) is expected to change with a one-unit change in the independent variables, providing a quantitative insight into the market dynamics of the fast-food outlet.
Sales Prediction
Sales prediction involves using the regression model to anticipate future sales figures based on current or hypothetical values of predictor variables.
For instance, in our exercise, we can calculate anticipated sales if a fast-food outlet has two competing outlets, a surrounding population of 8,000, and a drive-up window. We substitute \( x_1 = 2 \), \( x_2 = 8 \) (because it's in thousands), and \( x_3 = 1 \) into the model, leading to a predicted mean sales value of \( 77.3 \) (in thousands of dollars).
This method not only forecasts potential sales figures for planning and strategy but also aids in evaluating different business scenarios, such as changes in competition or location demographics.
Mean Value Interpretation
Interpreting the mean value in regression involves understanding the expected value of the dependent variable given specific values of the independent variables.
The mean value, in our example, refers to typical sales figures under certain conditions, like different competition levels, population sizes, and the presence or absence of drive-up windows.
Analyzing the coefficient \( \beta_3 \), which is 15.3, highlights the mean difference in sales for outlets with drive-up windows versus those without, under identical circumstances otherwise. Here, it implies an addition of \( 15,300 \) dollars to sales if an outlet includes a drive-up window.

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Most popular questions from this chapter

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