/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Consider the following summary d... [FREE SOLUTION] | 91Ó°ÊÓ

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Consider the following summary data on the modulus of elasticity \(\left(\times 10^{6} \mathrm{psi}\right)\) for lumber of three different grades (in close agreement with values in the article "Bending Strength and Stiffness of Second-Growth Douglas-Fir Dimension Lumber" (Forest Products J., 1991: 35-43), except that the sample sizes there were larger): $$ \begin{array}{cccc} \text { Grade } & \boldsymbol{J} & \overline{\boldsymbol{x}}_{\boldsymbol{i}} & \boldsymbol{s}_{\boldsymbol{i}} \\ \hline 1 & 10 & 1.63 & .27 \\ 2 & 10 & 1.56 & .24 \\ 3 & 10 & 1.42 & .26 \end{array} $$ Use this data and a significance level of \(.01\) to test the null hypothesis of no difference in mean modulus of elasticity for the three grades.

Short Answer

Expert verified
No significant difference was found in mean elasticity among grades.

Step by step solution

01

State the Hypotheses

Identify the null and alternative hypotheses. The null hypothesis \( H_0 \) is that there is no difference in the mean modulus of elasticity among the three grades. Mathematically, \( H_0: \mu_1 = \mu_2 = \mu_3 \). The alternative hypothesis \( H_a \) is that at least one mean is different. Mathematically, \( H_a: \text{at least one } \mu_i \text{ is different}.\)
02

Choose the Test and Significance Level

We use a one-way ANOVA test to determine if there are any statistically significant differences between the means. The chosen significance level is \( \alpha = 0.01 \).
03

Calculate the ANOVA Test Statistic

For ANOVA, calculate the sum of squares between groups (SSB), sum of squares within groups (SSW), and total sum of squares (SST). Then determine the test statistic, F-ratio, which is the variance between the groups divided by the variance within the groups. The required formulas and computations are:\[SSB = \sum J_i(\overline{x}_i - \overline{x})^2, \quad SSW = \sum (J_i - 1)s_i^2, \overline{x} = \frac{\sum J_i \overline{x}_i}{\sum J_i}, \quad F = \frac{SSB / (k-1)}{SSW / (N-k)},\]where \( k \) is the number of groups and \( N \) is the total number of observations.Compute means and sums: \( \overline{x} = \frac{(10)(1.63) + (10)(1.56) + (10)(1.42)}{30} = 1.53 \).\( SSB = 10(1.63 - 1.53)^2 + 10(1.56 - 1.53)^2 + 10(1.42 - 1.53)^2 = 0.059 \).\( SSW = (10-1)(0.27^2) + (10-1)(0.24^2) + (10-1)(0.26^2) = 0.183 \).\( F = \frac{0.059 / 2}{0.183 / 27} = 4.34 \).
04

Determine the Critical Value

Consult the F-distribution table with \( df_1 = k-1 = 2 \) and \( df_2 = N-k = 27 \), look for the critical value \( F_{critical} \) at \( \alpha = 0.01 \). Here, \( F_{critical} \approx 5.49 \).
05

Compare F-Ratio to Critical Value

Compare the calculated \( F \)-ratio of 4.34 with the critical value 5.49. Since 4.34 < 5.49, we do not reject the null hypothesis.
06

Conclusion and Interpretation

Because the test statistic does not exceed the critical value, we fail to reject the null hypothesis at the \( 0.01 \) significance level. There is not enough statistical evidence to suggest that there is a difference in the mean modulus of elasticity among the three grades of lumber.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In hypothesis testing, the null hypothesis, denoted as \( H_0 \), is a statement that is assumed to be true unless there is evidence to reject it. It's like saying, "There's nothing new or different happening here." This forms the baseline that we compare our data against. For the exercise at hand, the null hypothesis states that there is no difference in the mean modulus of elasticity for the three grades of lumber. In mathematical terms, this is expressed as \( \mu_1 = \mu_2 = \mu_3 \). This means we assume all the sample groups have the same mean and any observed variations are due to random chance.
\( H_0 \) is a vital part of the ANOVA test because it gives us a clear statement to test against with our data. If our calculations show a significant enough difference, we have grounds to reject \( H_0 \). But if not, \( H_0 \) stands strong.
Alternative Hypothesis
The alternative hypothesis, represented as \( H_a \), is the statement that we contemplate if there is enough evidence to contradict the null hypothesis. In this exercise's context, \( H_a \) is that there is at least one difference in the mean modulus of elasticity among the three grades of lumber. Unlike the null hypothesis, the alternative hypothesis is what researchers hope to find evidence for, showing that there's an "effect" or "difference".
Mathematically, \( H_a \) can be written as "at least one \( \mu_i \) is different." This indicates that while the null hypothesis assumes all means are equal, the alternative suggests there is an exception, which could be significant. Therefore, whenever the ANOVA test results suggest rejecting \( H_0 \), it gives credence to \( H_a \), implying significant differences.
Significance Level
The significance level, denoted as \( \alpha \), is a threshold set by the researcher for deciding when to reject the null hypothesis. It essentially measures how confident we need to be before concluding that there's an effect or difference observed. In this exercise, the significance level is set at \( \alpha = 0.01 \).
A significance level of 0.01 means there is a 1% risk of concluding that a difference exists when there actually is none. It's a way to control the Type I error rate, which is the probability of incorrectly rejecting the null hypothesis. The lower the \( \alpha \), the stricter we are in making claims against the null hypothesis, meaning stronger evidence is needed to reject it.
In the framework of ANOVA, comparing the test statistic (like F-ratio) to the critical value derived at this alpha helps decide the validity of \( H_0 \).
Modulus of Elasticity
The modulus of elasticity is a measure of a material's ability to resist changes in length when under lengthwise tension or compression. It essentially gauges the stiffness of the material. In lumber, like the problem presented, it helps assess how rigid or flexible a piece might be under load.
This property is crucial, particularly in construction and material engineering, as it directly impacts how a material will perform in structures. Higher modulus values indicate stiffer materials, which deform less under stress. Understanding these values among different grades aids in selecting the appropriate materials for varying applications, ensuring safety and suitability.
In this exercise, evaluating the mean modulus of elasticity across lumber grades helps determine if the stiffness characteristics are consistent or divergent, an important factor in structural use cases.

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Most popular questions from this chapter

Although tea is the world's most widely consumed beverage after water, little is known about its nutritional value. Folacin is the only B vitamin present in any significant amount in tea, and recent advances in assay methods have made accurate determination of folacin content feasible. Consider the accompanying data on folacin content for randomly selected specimens of the four leading brands of green tea. $$ \begin{array}{cccccccc} \text { Brand } & \multicolumn{8}{c}{\text { Observations }} \\ \hline 1 & 7.9 & 6.2 & 6.6 & 8.6 & 8.9 & 10.1 & 9.6 \\ 2 & 5.7 & 7.5 & 9.8 & 6.1 & 8.4 & & \\ 3 & 6.8 & 7.5 & 5.0 & 7.4 & 5.3 & 6.1 & \\ 4 & 6.4 & 7.1 & 7.9 & 4.5 & 5.0 & 4.0 & \\ \hline \end{array} $$ (Data is based on "Folacin Content of Tea," J. Amer: Dietetic Assoc., 1983: 627-632.) Does this data suggest that true average folacin content is the same for all brands? a. Carry out a test using \(\alpha=.05\) via the \(P\)-value method. b. Assess the plausibility of any assumptions required for your analysis in part (a). c. Perform a multiple comparisons analysis to identify significant differences among brands.

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