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Lengths of bus routes for any particular transit system will typically vary from one route to another. The article "Planning of City Bus Routes" (J. of the Institution of Engineers, 1995: 211-215) gives the following information on lengths \((\mathrm{km})\) for one particular system: $$ \begin{array}{lccccc} \text { Length } & 6-<8 & 8-<10 & 10-<12 & 12-<14 & 14-16 \\ \text { Frequency } & 6 & 23 & 30 & 35 & 32 \\ \text { Length } & 16-<18 & 18-<20 & 20-<22 & 22-<24 & 24<26 \\ \text { Frequency } & 48 & 42 & 40 & 28 & 27 \\ \text { Length } & 26-<28 & 28-<30 & 30-<35 & 35-<40 & 40-<5 \\ \text { Frequency } & 26 & 14 & 27 & 11 & 2 \end{array} $$ a. Draw a histogram corresponding to these frequencies. b. What proportion of these route lengths are less than 20 ? What proportion of these routes have lengths of at least 30 ? c. Roughly what is the value of the 90 th percentile of the route length distribution? d. Roughly what is the median route length?

Short Answer

Expert verified
a) Plot a histogram. b) Less than 20 km: 0.426, at least 30 km: 0.188. c) 90th percentile: roughly 22 km. d) Median: roughly 16-18 km.

Step by step solution

01

Understanding the Data

The dataset represents bus route lengths in kilometers and their respective frequencies in different length intervals. The aim is to perform tasks like plotting a histogram, calculating proportions, and finding percentile and median values.
02

Plotting the Histogram

Using the given data, plot a histogram where each bar represents a length interval, and the height of each bar represents the corresponding frequency. The x-axis will contain the route length intervals, and the y-axis will show the frequency of each interval.
03

Finding the Proportion for Part (b)

1. To find the proportion of routes less than 20 km, sum the frequencies for the intervals 6-8, 8-10, 10-12, 12-14, 14-16, 16-18, and 18-20. 2. To find the proportion of routes at least 30 km, sum the frequencies for the intervals 30-35, 35-40, and 40-45. 3. Divide each total by the sum of all frequencies to get the respective proportions.
04

Calculating the 90th Percentile

First, determine the cumulative frequency distribution. The 90th percentile position is given by 0.9 times the sum of all frequencies. Identify the interval corresponding to this position and approximate the 90th percentile length based on cumulative frequencies.
05

Finding the Median

The median corresponds to the 50th percentile position, which is 0.5 times the total frequency. Using the cumulative frequency distribution, locate the interval where the median lies and approximate the route length that corresponds to this cumulative frequency position.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Histogram
A histogram is a type of bar graph that represents the frequency distribution of a dataset. In our exercise, each bar in the histogram corresponds to a range of bus route lengths, such as 6-8 km or 8-10 km.
The height of each bar shows how many routes fall within that specific length interval.
To plot a histogram:
  • Place the route length intervals on the x-axis.
  • On the y-axis, indicate the frequency of each interval.
  • Draw bars for each interval where the height is proportional to the frequency.
This visual representation helps in quickly identifying which length ranges are most common, making it easier to analyze the distribution of bus route lengths.
Percentiles
Percentiles are values below which a certain percentage of data falls and are key in understanding the spread of a dataset. For instance, the 90th percentile shows us the length below which 90% of the bus routes lie.
To find a percentile:
  • First, calculate the cumulative frequency for the dataset.
  • Identify the position of the desired percentile by multiplying the total number of routes by the percentile's decimal value (e.g., 0.9 for the 90th percentile).
  • Find the length interval where this cumulative frequency position falls.
  • Estimate the length by determining within the interval how far into the percentile we are.
Percentiles help in assessing the data spread, identifying outliers, and making decisions based on distribution patterns.
Median
The median is a measure of central tendency that represents the middle value in a dataset when the values are arranged in order. For bus route lengths, the median tells us the length at which half of the routes are shorter, and half are longer.
To find the median:
  • Calculate the total number of observations.
  • Determine the median position, which is 0.5 times the total frequency.
  • Use the cumulative frequency to locate which interval contains the median route length.
  • Approximate the length within this interval where the 50% position lies.
The median provides a clear picture of the typical length of a bus route, less influenced by outliers compared to the mean.
Frequency Distribution
Frequency distribution is a tabular summary showing the number of observations (frequencies) within specific intervals (bins). In the context of our exercise, it tabulates how the bus routes are distributed across various length intervals (e.g., 6-8 km, 8-10 km, etc.).
To interpret frequency distribution:
  • Identify the intervals with the highest frequencies to understand where most data points lie.
  • Consider the shape of the distribution to see if it is skewed or symmetrical.
  • Analyze the breadth (or spread) of intervals to understand variability in route lengths.
Frequency distributions provide essential insights into the data's overall pattern and are foundational in graphical representations like histograms.

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Most popular questions from this chapter

a. If a constant \(c\) is added to each \(x_{i}\) in a sample, yielding \(y_{i}=x_{i}+c\), how do the sample mean and median of the \(y_{i}\) s relate to the mean and median of the \(x_{i} s\) ? Verif y your conjectures. b. If each \(x_{i}\) is multiplied by a constant \(c\), yielding \(y_{i}=c x_{i}\), answer the question of part (a). Again, verify your conjectures.

Let \(\bar{x}_{n}\) and \(s_{n}^{2}\) denote the sample mean and variance for the sample \(x_{1}, \ldots, x_{n}\) and let \(\bar{x}_{n+1}\) and \(s_{n+1}^{2}\) denote these quantities when an additional observation \(x_{n+1}\) is added to the sample. a. Show how \(\bar{x}_{n+1}\) can be computed from \(\bar{x}_{n}\) and \(x_{n+1}\). b. Show that $$ n s_{n+1}^{2}=(n-1) s_{n}^{2}+\frac{n}{n+1}\left(x_{n+1}-\bar{x}_{n}\right)^{2} $$ so that \(s_{n+1}^{2}\) can be computed from \(x_{n+1}, \bar{x}_{n}\), and \(s_{n}^{2}\) c. Suppose that a sample of 15 strands of drapery yarn has resulted in a sample mean thread elongation of \(12.58 \mathrm{~mm}\) and a sample standard deviation of \(.512 \mathrm{~mm}\). A 16 th strand results in an elongation value of \(11.8\). What are the values of the sample mean and sample standard deviation for all 16 elongation observations?

A Pareto diagram is a variation of a histogram for categorical data resulting from a quality control study. Each category represents a different type of product nonconformity or production problem. The categories are ordered so that the one with the largest frequency appears on the far left, then the category with the second largest frequency, and so on. Suppose the following information on nonconformities in circuit packs is obtained: failed component, 126; incorrect component, 210; insufficient solder, 67 ; excess solder, 54 ; missing component, 131. Construct a Pareto diagram.

a. Let \(a\) and \(b\) be constants and let \(y_{i}=a x_{i}+b\) for \(i=1\), \(2, \ldots, n\). What are the relationships between \(\bar{x}\) and \(\bar{y}\) and between \(s_{x}^{2}\) and \(s_{y}^{2}\) ? b. A sample of temperatures for initiating a certain chemical reaction yielded a sample average \(\left({ }^{\circ} \mathrm{C}\right)\) of \(87.3\) and a sample standard deviation of \(1.04\). What are the sample average and standard deviation measured in \({ }^{\circ} \mathrm{F}\) ?

Calculate and interpret the values of the sample median, sample mean, and sample standard deviation for the following observations on fracture strength (MPa, read from a graph in "Heat-Resistant Active Brazing of Silicon Nitride: Mechanical Evaluation of Braze Joints," Welding J., August, 1997): \(\begin{array}{llllllllll}87 & 93 & 96 & 98 & 105 & 114 & 128 & 131 & 142 & 168\end{array}\)

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