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The article "A Thin-Film Oxygen Uptake Test for the Evaluation of Automotive Crankcase Lubricants" (Lubric. Engr., 1984: 75-83) reported the following data on oxidationinduction time (min) for various commercial oils: \(\begin{array}{rrrrrrrrrrr}87 & 103 & 130 & 160 & 180 & 195 & 132 & 145 & 211 & 105 & 145 \\ 153 & 152 & 138 & 87 & 99 & 93 & 119 & 129 & & & \end{array}\) a. Calculate the sample variance and standard deviation. b. If the observations were reexpressed in hours, what would be the resulting values of the sample variance and sample standard deviation? Answer without actually performing the reexpression.

Short Answer

Expert verified
Variance (min): \(1147.13\), SD (min): \(33.87\); Variance (hours): \(0.318\), SD (hours): \(0.565\).

Step by step solution

01

Calculate the Sample Mean

First, sum up all the given oxidation induction times. The data points are: \(87, 103, 130, 160, 180, 195, 132, 145, 211, 105, 145, 153, 152, 138, 87, 99, 93, 119, 129\). The sum of these values is \(2368\). The number of observations is \(19\). The sample mean \(\bar{x}\) is calculated as \(\bar{x} = \frac{2368}{19} \approx 124.63\).
02

Compute the Squared Differences

Calculate the squared difference between each observation and the sample mean. For example, the first observation \(87\) minus the mean \(124.63\) gives a difference of \(-37.63\). Squaring this gives \(1415.36\). Repeat this process for all data points.
03

Sum the Squared Differences

Add up all the squared differences you calculated in Step 2. The sum of the squared differences is \(20648.37\).
04

Calculate the Sample Variance

Divide the sum of squared differences by \(n-1\) (where \(n\) is the number of observations) to find the sample variance. \(n = 19\), so \(n-1 = 18\). The sample variance \(s^2\) is \(\frac{20648.37}{18} \approx 1147.13\).
05

Calculate the Sample Standard Deviation

The sample standard deviation \(s\) is the square root of the variance. So, \(s = \sqrt{1147.13} \approx 33.87\).
06

Convert to Hours - Understanding the Effect

If we convert the data from minutes to hours, each value is divided by \(60\). The variance is the square of differences, thus it will be affected by the square of the conversion factor. Therefore, the variance in hours will be \(\frac{1}{3600}\) times the variance in minutes. The standard deviation will be \(\frac{1}{60}\) times the standard deviation in minutes. Hence, variance in hours = \(\frac{1147.13}{3600} \approx 0.318\), and standard deviation in hours = \(\frac{33.87}{60} \approx 0.565\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
Standard deviation is a measure of how spread out numbers in a set are. It tells you how much each data point differs from the mean (average). A smaller standard deviation means the data points are closer to the mean, while a larger standard deviation means they are more spread out.

To calculate the standard deviation, first determine the sample variance, which is the average of the squared differences between each data point and the mean. Then, take the square root of this variance to get the standard deviation.

In our example with oxidation induction times, we calculated the sample variance to be approximately 1147.13. The sample standard deviation, therefore, is the square root of 1147.13, which equals 33.87. The higher this number, the more variability there is in the data on oxidation induction times around the mean.
Data Conversion
Data conversion is the adjustment of numerical values from one unit to another, though the inherent data remains the same. It plays an important role when comparing or analyzing data across different units. The original dataset in minutes was converted into hours. This process influences both the sample variance and the standard deviation.

When converting, a factor is applied to the entire dataset. For instance, converting minutes to hours involves dividing each value by 60. However, since variance and standard deviation involve squared terms, the scaling factor must be squared for variance. This means variance in hours is the original variance divided by 3600 (since 60 squared is 3600), and for standard deviation, we simply divide by 60.

It's crucial to remember that while the numerical values change with conversion, the relative variability or spread in data remains consistent, preserving the dataset's relationships.
Mean Calculation
The mean, often referred to as the average, is a central tendency measure that summarizes the data. It gives a good idea of what a typical value in the dataset might be.

To calculate the mean:
  • Add up all the data points. In the given example, summing all oxidation times results in 2368 minutes.
  • Divide the total by the number of observations. Here, there are 19 values, so the mean oxidation time is 124.63 minutes.

The mean serves as a baseline from which deviations are measured when determining variance and standard deviation. It also serves as a comparative metric when converting data into other units like hours or seconds.

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