/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 A study of the relationship betw... [FREE SOLUTION] | 91Ó°ÊÓ

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A study of the relationship between age and various visual functions (such as acuity and depth perception) reported the following observations on area of scleral lamina \(\left(\mathrm{mm}^{2}\right)\) from human optic nerve heads ("Morphometry of Nerve Fiber Bundle Pores in the Optic Nerve Head of the Human," Experimental Eye Research, 1988: 559–568): \(\begin{array}{lllllllll}2.75 & 2.62 & 2.74 & 3.85 & 2.34 & 2.74 & 3.93 & 4.21 & 3.88 \\ 4.33 & 3.46 & 4.52 & 2.43 & 3.65 & 2.78 & 3.56 & 3.01 & \end{array}\) a. Calculate \(\sum x_{i}\) and \(\sum x_{i}^{2}\). b. Use the values calculated in part (a) to compute the sample variance \(s^{2}\) and then the sample standard deviation \(s\).

Short Answer

Expert verified
\(\sum x_i = 56.69\), \(\sum x_i^2 = 201.1434\), sample variance \(s^2 = 0.7478\), standard deviation \(s \approx 0.8647\).

Step by step solution

01

Calculate the Sum of Observations

To find \( \sum x_i \), add all the values together. There are 17 values in total.\[\sum x_i = 2.75 + 2.62 + 2.74 + 3.85 + 2.34 + 2.74 + 3.93 + 4.21 + 3.88 + 4.33 + 3.46 + 4.52 + 2.43 + 3.65 + 2.78 + 3.56 + 3.01 = 56.69\]
02

Calculate the Sum of Squared Observations

Now, calculate \( \sum x_i^2 \) by squaring each observation and then summing them up.\[\begin{align*}\sum x_i^2 &= 2.75^2 + 2.62^2 + 2.74^2 + 3.85^2 + 2.34^2 + 2.74^2 + 3.93^2 + 4.21^2 + 3.88^2 \& \quad + 4.33^2 + 3.46^2 + 4.52^2 + 2.43^2 + 3.65^2 + 2.78^2 + 3.56^2 + 3.01^2 \&= 3.40 + 3.86 + 7.52 + 14.82 + 5.48 + 7.52 + 15.44 + 17.73 + 15.05 \& \quad + 18.75 + 11.98 + 20.42 + 5.90 + 13.32 + 7.73 + 12.68 + 9.06 \&= 201.1434\end{align*}\]
03

Calculate the Mean of the Sample

The mean \( \overline{x} \) is calculated by dividing the sum of observations by the number of observations \( n \).\[\overline{x} = \frac{\sum x_i}{n} = \frac{56.69}{17} = 3.334\]
04

Compute the Sample Variance

Use the formula for sample variance:\[s^2 = \frac{1}{n-1} \left( \sum x_i^2 - \frac{(\sum x_i)^2}{n} \right)\]Substitute the calculated values:\[s^2 = \frac{1}{16} \left( 201.1434 - \frac{(56.69)^2}{17} \right)\]Calculate further:\[s^2 = \frac{1}{16} (201.1434 - 189.1791) = \frac{11.9643}{16} = 0.7478\]
05

Compute the Sample Standard Deviation

The sample standard deviation \( s \) is the square root of the sample variance.\[s = \sqrt{s^2} = \sqrt{0.7478} \approx 0.8647\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Variance
The sample variance is a statistical measure that indicates how spread out the values in a data set are around the mean. It is particularly useful for understanding the extent of variability within a sample of data.
In our exercise, calculating the sample variance involves several clear steps:
  • First, we compute the mean of the sample, which is the average value of all observations.
  • Then, we employ the formula for sample variance: \[ s^2 = \frac{1}{n-1} \left( \sum x_i^2 - \frac{(\sum x_i)^2}{n} \right) \] where \( n \) is the number of observations.
  • By substituting our calculated values into the formula, we arrive at the variance.

This variance tells us how much the individual data points deviate from the average. A larger variance indicates that the data points are more spread out. It’s an essential step in determining the standard deviation and provides insight into the diversity of the data set.
Sample Standard Deviation
The sample standard deviation is another key metric in statistical analysis. It is the square root of the sample variance and provides a measure of the amount of variation or dispersion in a set of values. The standard deviation is particularly helpful because it offers a direct interpretation of how much the data deviates from the mean.To compute it:
  • Take the sample variance, which we've calculated previously.
  • Find the square root of this variance: \[ s = \sqrt{s^2} \]
  • This result shows us how closely each observation clusters around the mean on average.

The sample standard deviation is widely used in many fields because it provides a clear view of data consistency. Smaller values indicate that data points tend to be very close to the mean, while larger values suggest more variation.
Data Summation
Data summation is a fundamental concept in statistical analysis, representing the process of adding together all the data observations. This method is necessary for calculating both the mean and variance of a data set.
In our exercise, we perform two types of summations to facilitate further analysis:
  • First, we calculate the sum of all data points, noted as \( \sum x_i \), by simply adding each value in the dataset.
  • Second, we need the sum of squared data points, represented as \( \sum x_i^2 \). This involves squaring each data point and then adding them.

Both of these summation operations are crucial steps in the process of calculating variance and standard deviation. Understanding and executing data summation accurately enables effective statistical analysis, ensuring that subsequent calculations are based on precise data.

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Most popular questions from this chapter

Consider numerical observations \(x_{1}, \ldots, x_{n^{*}}\) It is frequently of interest to know whether the \(x_{i} \mathrm{~s}\) are (at least approximately) symmetrically distributed about some value. If \(n\) is at least moderately large, the extent of symmetry can be assessed from a stem-and-leaf display or histogram. However, if \(n\) is not very large, such pictures are not particularly informative. Consider the following alternative. Let \(y_{1}\) denote the smallest \(x_{i}, y_{2}\) the second smallest \(x_{i}\), and so on. Then plot the following pairs as points on a two-dimensional coordinate system: \(\left(y_{n}-\tilde{x}, \tilde{x}-y_{1}\right),\left(y_{n-1}-\tilde{x}, \tilde{x}-y_{2}\right),\left(y_{n-2}-\tilde{x}\right.\), \(\left.\tilde{x}-y_{3}\right), \ldots\) There are \(n / 2\) points when \(n\) is even and \((n-1) / 2\) when \(n\) is odd. a. What does this plot look like when there is perfect symmetry in the data? What does it look like when observations stretch out more above the median than below it (a long upper tail)? b. The accompanying data on rainfall (acre-feet) from 26 seeded clouds is taken from the article "A Bayesian Analysis of a Multiplicative Treatment Effect in Weather Modification" (Technometrics, 1975: 161-166). Construct the plot and comment on the extent of symmetry or nature of departure from symmetry. \(\begin{array}{rrrrrrr}4.1 & 7.7 & 17.5 & 31.4 & 32.7 & 40.6 & 92.4 \\ 115.3 & 118.3 & 119.0 & 129.6 & 198.6 & 200.7 & 242.5 \\ 255.0 & 274.7 & 274.7 & 302.8 & 334.1 & 430.0 & 489.1 \\ 703.4 & 978.0 & 1656.0 & 1697.8 & 2745.6 & & \end{array}\)

A study carried out to investigate the distribution of total braking time (reaction time plus accelerator-to-brake movement time, in ms) during real driving conditions at \(60 \mathrm{~km} / \mathrm{hr}\) gave the following summary information on the distribution of times ("A Field Study on Braking Responses during Driving," Ergonomics, 1995: 1903-1910): mean \(=535 \quad\) median \(=500 \quad\) mode \(=500\) sd \(=96 \quad\) minimum \(=220 \quad\) maximum \(=925\) 5 th percentile \(=400 \quad 10\) th percentile \(=430\) 90 th percentile \(=640 \quad 95\) th percentile \(=720\) What can you conclude about the shape of a histogram of this data? Explain your reasoning.

A sample of 26 offshore oil workers took part in a simulated escape exercise, resulting in the accompanying data on time (sec) to complete the escape ("Oxygen Consumption and Ventilation During Escape from an Offshore Platform," Ergonomics, 1997: 281-292): \(\begin{array}{lllllllll}389 & 356 & 359 & 363 & 375 & 424 & 325 & 394 & 402 \\\ 373 & 373 & 370 & 364 & 366 & 364 & 325 & 339 & 393 \\ 392 & 369 & 374 & 359 & 356 & 403 & 334 & 397 & \end{array}\) a. Construct a stem-and-leaf display of the data. How does it suggest that the sample mean and median will compare? b. Calculate the values of the sample mean and median. [Hint: \(\left.\sum x_{i}=9638 .\right]\) c. By how much could the largest time, currently 424 , be increased without affecting the value of the sample median? By how much could this value be decreased without affecting the value of the sample median? d. What are the values of \(\bar{x}\) and \(\tilde{x}\) when the observations are reexpressed in minutes?

The value of Young's modulus (GPa) was determined for cast plates consisting of certain intermetallic substrates, resulting in the following sample observations ("Strength and Modulus of a Molybdenum-Coated Ti-25Al-10Nb-3U1Mo Intermetallic," J. of Materials Engr: and Performance, \(1997: 46-50)\) \(\begin{array}{lllll}116.4 & 115.9 & 114.6 & 115.2 & 115.8\end{array}\) a. Calculate \(\bar{x}\) and the deviations from the mean. b. Use the deviations calculated in part (a) to obtain the sample variance and the sample standard deviation. c. Calculate \(s^{2}\) by using the computational formula for the numerator \(S_{x x}\) d. Subtract 100 from each observation to obtain a sample of transformed values. Now calculate the sample variance of these transformed values, and compare it to \(s^{2}\) for the original data.

a. If a constant \(c\) is added to each \(x_{i}\) in a sample, yielding \(y_{i}=x_{i}+c\), how do the sample mean and median of the \(y_{i}\) s relate to the mean and median of the \(x_{i} s\) ? Verif y your conjectures. b. If each \(x_{i}\) is multiplied by a constant \(c\), yielding \(y_{i}=c x_{i}\), answer the question of part (a). Again, verify your conjectures.

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