/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 The propagation of fatigue crack... [FREE SOLUTION] | 91Ó°ÊÓ

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The propagation of fatigue cracks in various aircraft parts has been the subject of extensive study in recent years. The accompanying data consists of propagation lives (flight hours \(/ 10^{4}\) ) to reach a given crack size in fastener holes intended for use in military aircraft ("Statistical Crack Propagation in Fastener Holes under Spectrum Loading," J. Aircraft, 1983: 1028-1032): \(\begin{array}{rrrrrrrr}.736 & .863 & .865 & .913 & .915 & .937 & .983 & 1.007 \\\ 1.011 & 1.064 & 1.109 & 1.132 & 1.140 & 1.153 & 1.253 & 1.394\end{array}\) a. Compute and compare the values of the sample mean and median. b. By how much could the largest sample observation be decreased without affecting the value of the median?

Short Answer

Expert verified
Mean = 1.0297, Median = 1.009. Largest decrease without affecting median = 0.241.

Step by step solution

01

Compute the Sample Mean

First, add all the given propagation lives together: \[0.736 + 0.863 + 0.865 + 0.913 + 0.915 + 0.937 + 0.983 + 1.007 + 1.011 + 1.064 + 1.109 + 1.132 + 1.140 + 1.153 + 1.253 + 1.394 = 16.475\]Next, divide the sum by the number of observations, which is 16:\[\text{Mean} = \frac{16.475}{16} = 1.0297\]
02

Compute the Sample Median

To find the median, arrange the data in ascending order: 0.736, 0.863, 0.865, 0.913, 0.915, 0.937, 0.983, 1.007, 1.011, 1.064, 1.109, 1.132, 1.140, 1.153, 1.253, 1.394. Since the number of observations (16) is even, calculate the median by taking the average of the 8th and 9th observations:\[\text{Median} = \frac{1.007 + 1.011}{2} = 1.009\]
03

Determine Maximum Decrease Without Affecting Median

To adjust the largest observation without affecting the median, ensure the median position isn't altered. The median remains at the average of the 8th and 9th values (between 1.007 and 1.011), regardless of how the observed largest value (1.394) is lowered. Thus, the largest observation can be decreased to any number above 1.153 (the next largest value). Therefore, it could be decreased by:\[1.394 - 1.153 = 0.241\]without affecting the median.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Descriptive Statistics
Descriptive statistics provide a way to summarize and interpret a collection of data points to understand its main features. In statistics, there are several measures to describe data:
  • Central Tendency: This includes measures like mean and median, which provide a central value for the data.
  • Variability: This tells us about the spread or dispersion of data, including measures like range and standard deviation.
  • Shape of Distribution: This involves assessing the symmetry or skewness of data distribution.
Understanding these traits helps in making decisions based on data insights. This exercise focuses on calculating the sample mean and median, which are pivotal components in descriptive statistics.
Data Analysis
Data analysis involves a systematic process of inspecting, cleaning, transforming, and modeling data to discover useful information and support decision-making. In this exercise, we're analyzing propagation lives of aircraft parts, focusing on their centrality - the mean and median.
  • Gathering Data: We start by collecting all necessary data points, which are often numerical values in real-world scenarios.
  • Organizing Data: Arranging the data in ascending or descending order helps in plotting and calculating more accurately.
  • Computing Statistics: Calculating descriptive statistics, like mean and median, aids in summarizing the main characteristics of the data set.
A detailed data analysis like this helps in predicting trends and making informed decisions for future aircraft maintenance.
Median Calculation
Calculating the median involves finding the "middle" value of a data set when it is ordered from smallest to largest. The median is a measure of central tendency that provides insights distinct from the mean.
  • Ordering Data: To find the median, first arrange the data values in ascending order.
  • Even Number of Observations: As in our exercise, if the number of data points is even, the median is the average of the two middle numbers.
  • Importance: The median is useful for understanding skewed distributions or those with outliers, as it is not affected by extreme values.
Knowing how to calculate the median is crucial whenever you need a robust measure of central tendency.
Mean Calculation
The mean, often called the average, is the sum of all data points divided by their number. It provides a measure of central tendency, indicating where most data points lie.
  • Adding Data Points: Sum all the values from the data set.
  • Dividing by Count: Divide this sum by the total number of data points to find the mean.
  • Sensitivity to Outliers: Unlike the median, the mean can be influenced by extremely high or low values, which can skew the result.
Calculating the mean gives a quick insight into the general level of the data but should be considered with other measures to get a full understanding of data distribution.

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Most popular questions from this chapter

Exposure to microbial products, especially endotoxin, may have an impact on vulnerability to allergic diseases. The article "Dust Sampling Methods for Endotoxin-An Essential, But Underestimated Issue" (Indoor Air, 2006: 20–27) considered various issues associated with determining endotoxin concentration. The following data on concentration (EU/mg) in settled dust for one sample of urban homes and another of farm homes was kindly supplied by the authors of the cited article. \(\begin{array}{llllllllllllll}\mathrm{U}: & 6.0 & 5.0 & 11.0 & 33.0 & 4.0 & 5.0 & 80.0 & 18.0 & 35.0 & 17.0 & 23.0 \\ \mathrm{~F}: & 4.0 & 14.0 & 11.0 & 9.0 & 9.0 & 8.0 & 4.0 & 20.0 & 5.0 & 8.9 & 21.0 \\ & 9.2 & 3.0 & 2.0 & 0.3 & & & & & & & \end{array}\) a. Determine the sample mean for each sample. How do they compare? b. Determine the sample median for each sample. How do they compare? Why is the median for the urban sample so different from the mean for that sample? c. Calculate the trimmed mean for each sample by deleting the smallest and largest observation. What are the corresponding trimming percentages? How do the values of these trimmed means compare to the corresponding means and medians?

A sample of 26 offshore oil workers took part in a simulated escape exercise, resulting in the accompanying data on time (sec) to complete the escape ("Oxygen Consumption and Ventilation During Escape from an Offshore Platform," Ergonomics, 1997: 281-292): \(\begin{array}{lllllllll}389 & 356 & 359 & 363 & 375 & 424 & 325 & 394 & 402 \\\ 373 & 373 & 370 & 364 & 366 & 364 & 325 & 339 & 393 \\ 392 & 369 & 374 & 359 & 356 & 403 & 334 & 397 & \end{array}\) a. Construct a stem-and-leaf display of the data. How does it suggest that the sample mean and median will compare? b. Calculate the values of the sample mean and median. [Hint: \(\left.\sum x_{i}=9638 .\right]\) c. By how much could the largest time, currently 424 , be increased without affecting the value of the sample median? By how much could this value be decreased without affecting the value of the sample median? d. What are the values of \(\bar{x}\) and \(\tilde{x}\) when the observations are reexpressed in minutes?

Consider the following observations on shear strength (MPa) of a joint bonded in a particular manner (from a graph in the article "Diffusion of Silicon Nitride to Austenitic Stainless Steel without Interlayers," Metallurgical Trans., 1993: 1835-1843). \(\begin{array}{rrrrrr}22.2 & 40.4 & 16.4 & 73.7 & 36.6 & 109.9 \\ 30.0 & 4.4 & 33.1 & 66.7 & 81.5 & \end{array}\) a. What are the values of the fourths, and what is the value of \(f_{s}\) ? b. Construct a boxplot based on the five-number summary, and comment on its features. c. How large or small does an observation have to be to qualify as an outlier? As an extreme outlier? d. By how much could the largest observation be decreased without affecting \(f_{s}\) ?

Many universities and colleges have instituted supplemental instruction (SI) programs, in which a student facilitator meets regularly with a small group of students enrolled in the course to promote discussion of course material and enhance subject mastery. Suppose that students in a large statistics course (what else?) are randomly divided into a control group that will not participate in SI and a treatment group that will participate. At the end of the term, each student's total score in the course is determined. a. Are the scores from the SI group a sample from an existing population? If so, what is it? If not, what is the relevant conceptual population? b. What do you think is the advantage of randomly dividing the students into the two groups rather than letting each student choose which group to join? c. Why didn't the investigators put all students in the treatment group? Note: The article "Supplemental Instruction: An Effective Component of Student Affairs Programming" (J. of College Student Devel., 1997: 577-586) discusses the analysis of data from several SI programs.

The first four deviations from the mean in a sample of \(n=5\) reaction times were \(.3, .9,1.0\), and \(1.3\). What is the fifth deviation from the mean? Give a sample for which these are the five deviations from the mean.

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