/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 Damage to grapes from bird preda... [FREE SOLUTION] | 91Ó°ÊÓ

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Damage to grapes from bird predation is a serious problem for grape growers. The article "Experimental Method to Investigate and Monitor Bird Behavior and Damage to Vineyards" (Amer. \(J\). of Enology and Viticulture, 2004: 288-291) reported on an experiment involving a bird-feeder table, time-lapse video, and artificial foods. Information was collected for two different bird species at both the experimental location and at a natural vineyard setting. Consider the following data on time \((\mathrm{sec})\) spent on a single visit to the location. $$ \begin{array}{llrrc} \text { Species } & \text { Location } & n & \bar{x} & \text { SE mean } \\ \hline \text { Blackbirds } & \text { Exptl } & 65 & 13.4 & 2.05 \\ \text { Blackbirds } & \text { Natural } & 50 & 9.7 & 1.76 \\ \text { Silvereyes } & \text { Exptl } & 34 & 49.4 & 4.78 \\ \text { Silvereyes } & \text { Natural } & 46 & 38.4 & 5.06 \\ \hline \end{array} $$ a. Calculate an upper confidence bound for the true average time that blackbirds spend on a single visit at the experimental location. b. Does it appear that true average time spent by blackbirds at the experimental location exceeds the true average time birds of this type spend at the natural location? Carry out a test of appropriate hypotheses. c. Estimate the difference between the true average time blackbirds spend at the natural location and true average time that silvereyes spend at the natural location, and do so in a way that conveys information about reliability and precision. [Note: The sample medians reported in the article all seemed significantly smaller than the means, suggesting substantial population distribution skewness. The authors actually used the distribution-free test procedure presented in Section 2 of Chapter 15.]

Short Answer

Expert verified
a. 16.8 seconds; b. Insufficient evidence; c. Difference is between 18.1 and 39.3 seconds.

Step by step solution

01

Understanding the Context

The exercise presents data on the time birds spend on a single visit to a location for two species: Blackbirds and Silvereyes. For each species, the time is recorded at an experimental location and a natural vineyard. The goal is to calculate confidence bounds and test hypotheses about their time differences.
02

Calculate Upper Confidence Bound for Blackbirds at Experimental Location

The formula for a one-sided upper confidence bound is \( \bar{x} + t_{\alpha,n-1} \cdot \text{SE mean} \). For Blackbirds at the experimental location: \( \bar{x} = 13.4 \), \( \text{SE mean} = 2.05 \), and \( n = 65 \). Using a t-table with \( \alpha = 0.05 \) and \( n-1 = 64 \) degrees of freedom, find \( t_{0.05,64} \) which is approximately 1.669. The upper confidence bound is: \[ 13.4 + 1.669 \times 2.05 = 16.818 \].
03

Set Up Hypotheses for Time at Experimental vs Natural Locations

Formulate the hypotheses: - Null Hypothesis \( H_0: \mu_1 = \mu_2 \) (true average times are equal).- Alternative Hypothesis \( H_1: \mu_1 > \mu_2 \) (time at experimental is greater).
04

Perform Hypothesis Test for Blackbirds

Calculate the test statistic using the formula for comparing two means: \[ t = \frac{\bar{x}_1 - \bar{x}_2}{\sqrt{(\text{SE mean}_1)^2 + (\text{SE mean}_2)^2}} \]Substitute: \( \bar{x}_1 = 13.4 \), \( \text{SE mean}_1 = 2.05 \), \( \bar{x}_2 = 9.7 \), and \( \text{SE mean}_2 = 1.76 \). \[ t = \frac{13.4 - 9.7}{\sqrt{(2.05)^2 + (1.76)^2}} = \frac{3.7}{2.703} \approx 1.37 \]. Compare \( t \approx 1.37 \) with \( t_{0.05,64} \approx 1.669 \). Since 1.37 < 1.669, we do not reject \( H_0 \).
05

Estimate Difference and Confidence Interval Between Blackbirds and Silvereyes

Calculate the difference in means: \( \bar{x}_{\text{Silvereyes, Natural}} - \bar{x}_{\text{Blackbirds, Natural}} = 38.4 - 9.7 = 28.7 \). Calculate the standard error for the difference:\[ \sqrt{(5.06)^2 + (1.76)^2} = \sqrt{25.6036 + 3.0976} = 5.336 \].Use this to form a confidence interval for the difference:\( \bar{x}_{diff} \pm t_{0.025, df} \times SE \), where \( df \) is approximated using a method like Welch-Satterthwaite. Simplifying we use \( t_{0.025, \infty} \approx 1.96 \), the difference is:\[ 28.7 \pm 1.96 \times 5.336 = (18.1, 39.3) \].
06

Interpret Results

The upper confidence bound for Blackbirds at the experimental location is approximately 16.8 seconds. The hypothesis test suggests insufficient evidence that the average visit time at the experimental location is greater than the natural one. The estimated difference in time between Silvereyes and Blackbirds at the natural location is between 18.1 and 39.3 seconds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
Confidence intervals are statistical tools used to estimate the range within which a population parameter is expected to fall with a specified level of confidence. In biological research, they are particularly helpful for interpreting experimental data. Let's explore how confidence intervals were used in this exercise.

In the study involving grapevines and birds, the goal was to estimate how much time birds spend at certain locations. For instance, researchers wanted to find the upper confidence bound for the time Blackbirds spent at the experimental site. This means estimating the maximum time they'd spend per visit, with a high level of certainty.
  • Given the average time (\( \bar{x} = 13.4 \) seconds) and the standard error of the mean (\( SE = 2.05 \) seconds), the confidence interval gives a range around this estimate.
  • A one-sided confidence interval was calculated using a t-table for a 95% confidence level, resulting in an upper bound.
Confidence intervals provide a balance between certainty and variability, helping researchers find reliable boundaries for their data observations.
Hypothesis Testing
Hypothesis testing is a critical tool in statistics, especially in biological research, as it helps determine if there is a significant difference between different data sets. In this exercise, hypothesis testing was used to compare the time Blackbirds spent at an experimental location versus a natural one. Let's delve into how this is achieved.

To begin, researchers set up two competing hypotheses:
  • The null hypothesis (\( H_0 \)) assumes that the average time spent by Blackbirds at both the experimental and natural sites is the same.
  • The alternative hypothesis (\( H_1 \)) proposes that the average time differs, specifically that birds spend more time at the experimental location.
The next step involved calculating a test statistic to objectively measure the difference between means. This involved using the formula:\[ t = \frac{\bar{x}_1 - \bar{x}_2}{\sqrt{(SE_1)^2 + (SE_2)^2}} \]After performing these calculations, the test statistic was compared to a critical value from the t-distribution table. If the test statistic exceeded this threshold, the null hypothesis would be rejected in favor of the alternative.

However, the calculations in this exercise indicated that there was insufficient evidence to claim a time difference, showing the strength of hypothesis testing in decision-making processes within experimental designs.
Experimental Design
Experimental design in biological research is essential for structuring studies to obtain valid and reliable results. This exercise presents a well-planned experiment aimed at measuring the time two bird species spend in different settings. Understanding the principles of experimental design can greatly enhance the validity of your outcomes.

Core components include:
  • A clear definition of variables: Variables such as time spent and the setting (experimental vs. natural) were clearly designated for this study.
  • A controlled environment: Using a bird-feeder table and time-lapse video ensured consistent conditions for data collection.
  • Appropriate sample sizes: With varying numbers of observations for each species and setting, the design allowed for reliable statistical comparisons.
The design aimed to minimize bias and enhance precision in data collection. In this research, having clear objectives and an established methodology was vital. Similarly, the choice of statistical methods, including confidence intervals and hypothesis tests, was aligned with the experimental goals.

Overall, thoughtful experimental design leads to more credible and interpretable results, offering greater insights into the behaviors under study.

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