/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 As the population ages, there is... [FREE SOLUTION] | 91Ó°ÊÓ

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As the population ages, there is increasing concern about accident-related injuries to the elderly. The article "4ge and Gender Differences in Single- Step Recovery from a Forward Fall" (J. of Gerontology, 1999: M44-M50) reported on an experiment in which the maximum lean angle-the farthest a subject is able to lean and still recover in one step-was determined for both a sample of younger females \((21-29\) years) and a sample of older females (67-8l years). The following observations are consistent with summary data given in the article: YF: \(29,34,33,27,28,32,31,34,32,27\) OF: \(18,15,23,13,12\) Does the data suggest that true average maximum lean angle for older females is more than 10 degrees smaller than it is for younger females? State and test the relevant hypotheses at significance level .10.

Short Answer

Expert verified
The data suggest that the average maximum lean angle for older females is more than 10 degrees smaller than for younger females.

Step by step solution

01

Define Hypotheses

We want to check if the average maximum lean angle for older females (OF) is more than 10 degrees smaller than that of younger females (YF). This translates to the hypothesis: - Null hypothesis (H_0): \( \mu_{YF} - \mu_{OF} \leq 10 \)- Alternative hypothesis (H_a): \( \mu_{YF} - \mu_{OF} > 10 \)
02

Calculate Sample Means

Calculate the sample means for both groups:- Younger Females (YF) sample mean: \( \bar{YF} = \frac{1}{10}(29 + 34 + 33 + 27 + 28 + 32 + 31 + 34 + 32 + 27) = 30.7 \)- Older Females (OF) sample mean:\( \bar{OF} = \frac{1}{5}(18 + 15 + 23 + 13 + 12) = 16.2 \)
03

Determine Sample Variances

Calculate the sample variances for both groups:- Younger Females (YF) sample variance:\( s_{YF}^2 = \frac{1}{9}\sum_{i=1}^{10}(x_i - \bar{YF})^2 = 8.233 \)- Older Females (OF) sample variance:\( s_{OF}^2 = \frac{1}{4}\sum_{i=1}^{5}(y_i - \bar{OF})^2 = 15.7 \)
04

Calculate Standard Error

Calculate the standard error of the difference between two means:\[ SE = \sqrt{\frac{s_{YF}^2}{n_{YF}} + \frac{s_{OF}^2}{n_{OF}}} = \sqrt{\frac{8.233}{10} + \frac{15.7}{5}} = 1.759 \]
05

Calculate the Test Statistic

Calculate the test statistic for the hypothesis: \[ t = \frac{(\bar{YF} - \bar{OF}) - 10}{SE} = \frac{(30.7 - 16.2) - 10}{1.759} = 2.605 \]
06

Determine Degrees of Freedom and Critical Value

Calculate the degrees of freedom using the formula for unequal variances:\[ df = \frac{(s_{YF}^2/n_{YF} + s_{OF}^2/n_{OF})^2}{\frac{(s_{YF}^2/n_{YF})^2}{n_{YF}-1} + \frac{(s_{OF}^2/n_{OF})^2}{n_{OF}-1}} \approx 8 \]Using a t-distribution table, a one-tailed test at a significance level of 0.10 with 8 degrees of freedom, the critical value is approximately 1.397.
07

Make a Decision

Compare the calculated test statistic to the critical value:- Calculated \( t \) = 2.605- Critical value = 1.397Since the test statistic is greater than the critical value, we reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Two-Sample t-Test
The two-sample t-test is a statistical method used to determine if there are significant differences between the means of two independent groups. In our example, we compare the maximum lean angles between younger and older females. The primary goal is to see if the average maximum lean angle for older females is more than 10 degrees smaller than that of younger females. The two independent samples in this context are the group of younger females and the group of older females. The test assumes that the data is normally distributed in both groups and that the variances in both populations are equal. This test is useful in scenarios where we want to compare two different groups on the same measure, offering insight into whether observed differences are statistically significant rather than just due to random chance.
Significance Level
The significance level, denoted by alpha (\(\alpha\)), is a crucial component in hypothesis testing. It represents the probability of rejecting the null hypothesis when it is actually true. In simple terms, it is the risk level of making a Type I error, which occurs when we incorrectly conclude that there is an effect when there is none. For our exercise, a significance level of 0.10 has been chosen. This means there's a 10% risk of concluding that the true mean difference is greater than 10 degrees when it might not be. In most research scenarios, the level is chosen prior to analyzing the data, guiding the decision on whether to accept or reject the null hypothesis. A smaller significance level would indicate a more stringent criterion for accepting a result as significant.
Sample Variance
Sample variance is a measure of the dispersion or spread of sample data points. It quantifies how much the individual data points in a sample deviate from the sample mean. Calculating sample variance assists in understanding the variability within the samples. In the exercise, the sample variance for younger females (\(s_{YF}^2\)) was calculated to be 8.233, while for older females (\(s_{OF}^2\)), it was found to be 15.7. These variances are used to calculate the standard error, which is crucial for the subsequent t-test. Knowing the variance helps us understand how much variability is inherent in the data, which influences the reliability of the sample means used in the hypothesis test.
Test Statistic
The test statistic is a standardized value that results from using a statistical test to evaluate a hypothesis. It breaks down the difference between the observed sample means and the hypothesized population mean difference into units of standard error. In this exercise, the t-test statistic calculated was 2.605. This value is compared against a critical value from the t-distribution table. If the test statistic exceeds the critical value, the null hypothesis is rejected. Here, since 2.605 is greater than the critical value of 1.397, it leads us to reject the null hypothesis, indicating that the mean maximum lean angle for older females is indeed more than 10 degrees smaller than that for younger females. Understanding the test statistic helps translate raw data into interpretable results.

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Most popular questions from this chapter

Quantitative noninvasive techniques are needed for routinely assessing symptoms of peripheral neuropathies, such as carpal tunnel syndrome (CTS). The article "A Gap Detection Tactility Test for Sensory Deficits Associated with Carpal Tunnel Syndrome" (Ergonomics, 1995: 2588-2601) reported on a test that involved sensing a tiny gap in an otherwise smooth surface by probing with a finger; this functionally resembles many work-related tactile activities, such as detecting scratches or surface defects. When finger probing was not allowed, the sample average gap detection threshold for \(m=8\) normal subjects was \(1.71 \mathrm{~mm}\), and the sample standard deviation was \(.53\); for \(n=10\) CTS subjects, the sample mean and sample standard deviation were \(2.53\) and \(.87\), respectively. Does this data suggest that the true average gap detection threshold for CTS subjects exceeds that for normal subjects? State and test the relevant hypotheses using a significance level of .01.

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An article in the November 1983 Consumer Reports compared various types of batteries. The average lifetimes of Duracell Alkaline AA batteries and Eveready Energizer Alkaline AA batteries were given as 4.1 hours and \(4.5\) hours, respectively. Suppose these are the population average lifetimes. a. Let \(\bar{X}\) be the sample average lifetime of 100 Duracell batteries and \(\bar{Y}\) be the sample average lifetime of 100 Eveready batteries. What is the mean value of \(\bar{X}-\bar{Y}\) (i.e., where is the distribution of \(\bar{X}-\bar{Y}\) centered)? How does your answer depend on the specified sample sizes? b. Suppose the population standard deviations of lifetime are \(1.8\) hours for Duracell batteries and \(2.0\) hours for Eveready batteries. With the sample sizes given in part (a), what is the variance of the statistic \(\bar{X}-\bar{Y}\), and what is its standard deviation? c. For the sample sizes given in part (a), draw a picture of the approximate distribution curve of \(\bar{X}-\bar{Y}\) (include a measurement scale on the horizontal axis). Would the shape of the curve necessarily be the same for sample sizes of 10 batteries of each type? Explain.

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