/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 would not conclude that more tha... [FREE SOLUTION] | 91Ó°ÊÓ

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would not conclude that more than \(50 \%\) do? 49\. A plan for an executive travelers' club has been developed by an airline on the premise that \(5 \%\) of its current customers would qualify for membership. A random sample of 500 customers yielded 40 who would qualify. a. Using this data, test at level .01 the null hypothesis that the company's premise is correct against the alternative that it is not correct. b. What is the probability that when the test of part (a) is used, the company's premise will be judged correct when in fact \(10 \%\) of all current customers qualify?

Short Answer

Expert verified
a. Fail to reject null, not enough evidence against 5%. b. Probability is approximately 0.244.

Step by step solution

01

Define Hypotheses

We need to test the null hypothesis (\[ H_0: p = 0.05 \]) against the alternative hypothesis (\[ H_a: p eq 0.05 \]), where \( p \) is the proportion of customers who qualify for membership.
02

Determine Test Statistic

Using the sample proportion (\( \hat{p} = \frac{40}{500} = 0.08 \)) and assuming \( H_0 \) is true, calculate the test statistic using: \[z = \frac{\hat{p} - p}{\sqrt{\frac{p(1-p)}{n}}}\]Substituting, we have:\[z = \frac{0.08 - 0.05}{\sqrt{\frac{0.05(0.95)}{500}}} \approx 2.206\]
03

Determine Critical Value and Decision Rule

For a two-tailed test at the 0.01 significance level, the critical values are approximately \( z = \pm 2.576 \). Reject \( H_0 \) if \( z \) is less than \( -2.576 \) or greater than \( 2.576 \).
04

Make a Decision

The calculated \( z \approx 2.206 \) is within the range of \(-2.576\) to \(2.576\), so we fail to reject the null hypothesis. Thus, we conclude that there is not enough evidence to claim the proportion differs from 5%.
05

Calculate Type II Error (Power), Part b

If 10% qualify, calculate the probability that \( H_0 \) is not rejected even when \( H_a \) is true:\[z = \frac{0.08 - 0.10}{\sqrt{\frac{0.10(0.90)}{500}}} \approx -0.707\]Find the probability that \( z \) is between \(-2.576\) and \(2.576\) for \( n = 500 \). Using the standard normal distribution, \( P(Z > -2.576) \approx 0.995 \) and \( P(Z < 2.576) \approx 0.995 \), hence the probability (power) is roughly \(0.995 - 0.239 = 0.756\).Thus, the probability of Type II error is \(1 - 0.756 = 0.244\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
The null hypothesis, often denoted as \( H_0 \), is a foundational concept in hypothesis testing. It represents the default or initial claim that there is no effect or no difference. In this particular case, the null hypothesis suggests that the proportion of customers qualifying for the executive travelers' club is exactly \(5 \%\). This hypothesis is tested using sample data to determine whether there is enough evidence to reject it. When we assume the null hypothesis is true, we're basically saying everything is just as expected. To test this, statisticians collect data and perform calculations, such as the test statistic, to see how likely the observed data would be if \( H_0 \) were true.
A crucial aspect of the null hypothesis is that it can be directly tested; however, it cannot be "proven true," only "failed to be rejected." This implies if our test results don't show significant evidence against it, we continue to assume it is true.
Alternative Hypothesis
The alternative hypothesis, denoted as \( H_a \), is the statement we consider when we reject the null hypothesis. It is what you would conclude if there's enough evidence against \( H_0 \). In our scenario, the alternative hypothesis suggests that the proportion is not equal to \(5\%\) \( (p eq 0.05) \). This hypothesis serves as the counterpart to the null hypothesis and represents what we suspect is true. When we conduct hypothesis tests, we essentially gather evidence to either reject or fail to reject \( H_0 \), indirectly providing support for \( H_a \) when \( H_0 \) is rejected.
It's important to design tests carefully, considering both the null and alternative hypotheses because they frame the entire investigation. A critical point of hypothesis testing is to avoid bias—meaning the test should not mistakenly support \( H_a \) if \( H_0 \) is indeed the true state of nature.
Type II Error
A Type II error occurs when we fail to reject a null hypothesis that is false. In simple words, it’s when the test concludes that there is no effect or no difference, but in reality, there is one. This error is denoted as \( \beta \) (beta). Consider our example of the airline membership; a Type II error would mean concluding that the customer proportion is \(5\%\) when actually it is \(10\%\). In this case, we'd miss recognizing the real scenario.
Whether or not this type of error is problematic depends on context and consequences. Reducing Type II errors requires careful planning, such as increasing sample size or adjusting the chosen significance level. Researchers aim to balance the risk of Type II errors with Type I errors (false positives), ensuring more accurate study results. It's crucial to understand that reducing the chance of one type of error generally increases the likelihood of the other, emphasizing the need for tailored study designs.
Significance Level
The significance level, represented by \( \alpha \), is a threshold used to decide whether a statistical result is significant. It's often set at \(0.01\), \(0.05\), or \(0.10\), with the most common being \(0.05\). For our airline scenario, a significance level of \(0.01\) means there is a \(1\%\) risk of rejecting the null hypothesis if it’s actually true (Type I error). This threshold helps define the critical value for which results are compared. If the calculated test statistic is more extreme than the critical value, we conclude that the result is statistically significant and reject \( H_0 \).
Adjusting the significance level impacts the rigour of the test. Lower levels decrease the chance of Type I errors but can increase Type II errors and vice versa. Selecting the right \(\alpha\) requires a nuanced approach, balancing false positives and negatives relative to what is considered practically meaningful for the specific context.

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