/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 For each of the following assert... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

For each of the following assertions, state whether it is a legitimate statistical hypothesis and why: a. \(H: \sigma>100\) b. \(H: \tilde{x}=45\) c. \(H: s \leq .20\) d. \(H: \sigma_{1} / \sigma_{2}<1\) e. \(H: \bar{X}-\bar{Y}=5\) f. \(H: \lambda \leq .01\), where \(\lambda\) is the parameter of an exponential distribution used to model component lifetime

Short Answer

Expert verified
Legitimate hypotheses: a, d, f. Non-legitimate hypotheses: b, c, e.

Step by step solution

01

Understanding Hypotheses

A statistical hypothesis is a statement about a population parameter that we can test using statistical methods. A legitimate hypothesis should be in terms of population parameters, not sample statistics.
02

Evaluating Hypothesis a

The assertion \(H: \sigma > 100\) refers to \(\sigma\), which is the standard deviation of a population. Since it involves a population parameter, it is a legitimate hypothesis.
03

Evaluating Hypothesis b

The assertion \(H: \tilde{x} = 45\) uses \(\tilde{x}\), which is a sample statistic (sample median). Hypotheses must refer to population parameters, so this is not a legitimate hypothesis.
04

Evaluating Hypothesis c

The assertion \(H: s \leq 0.20\) uses \(s\), the sample standard deviation. Hypotheses should be about population parameters; thus, this is not a legitimate hypothesis.
05

Evaluating Hypothesis d

The assertion \(H: \sigma_{1} / \sigma_{2} < 1\) involves the comparison of two population standard deviations, \(\sigma_{1}\) and \(\sigma_{2}\). Since it refers to population parameters, it is a legitimate hypothesis.
06

Evaluating Hypothesis e

The assertion \(H: \bar{X} - \bar{Y} = 5\) involves sample means \(\bar{X}\) and \(\bar{Y}\). As these are sample statistics, not population parameters, this is not a legitimate hypothesis.
07

Evaluating Hypothesis f

The assertion \(H: \lambda \leq 0.01\) involves \(\lambda\), a parameter of the exponential distribution of a population. Since it's a population parameter, it is a legitimate hypothesis.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Parameters
Population parameters are key aspects in statistics that describe characteristics of a whole population. These parameters often include mean, median, variance, or standard deviation, but can also cover aspects like proportions or rates. Unlike sample statistics, which summarize data from a sample, population parameters provide a complete and accurate description of the entire group under study.
  • Examples include the population mean (\(\mu\)), population standard deviation (\(\sigma\)), and parameters like \(\lambda\) in an exponential distribution.
  • Because population parameters are constants, they do not change unless the entire population changes.
When performing statistical analyses, we often use sample data to make inferences about these parameters because it's usually impractical to measure the entire population. Understanding the difference between population parameters and sample statistics is crucial in hypothesis testing, as hypotheses need to be stated in terms of population parameters to be considered legitimate.
Hypothesis Testing
Hypothesis testing is a fundamental part of statistics that allows us to make informed decisions about population parameters. The process involves making an initial assumption (the null hypothesis) and then using sample data to determine the plausibility of that assumption.
  • The null hypothesis (\(H_0\)) is a statement of no effect or no difference, often stating that a population parameter equals a certain value.
  • The alternative hypothesis (\(H_a\)) is what you want to prove, suggesting that there is an effect or a difference.
By examining sample statistics, researchers can estimate the probability of observing their data if the null hypothesis is true. If this probability is too low, the null hypothesis is rejected in favor of the alternative hypothesis.
Sample Statistics
Sample statistics are metrics that describe a sample drawn from a larger population. These are used to estimate population parameters and to conduct hypothesis tests. Common sample statistics include the sample mean (\(\bar{x}\)), sample standard deviation (\(s\)), and sample median (\(\tilde{x}\)).
  • Sample statistics are variable and can change from one sample to another because they are calculated from a subset of the population.
  • They provide the basis for estimating the population parameters and testing hypotheses about those parameters.
It's essential to distinguish between sample statistics and population parameters for accurate hypothesis testing and ensuring that statistical methods are being applied correctly.
Legitimate Hypothesis
To establish a legitimate hypothesis in statistics, it must be expressed in terms of population parameters. This distinction is vital because hypotheses about population characteristics can be tested and validated using statistical inference, whereas those about sample statistics cannot.
  • A legitimate hypothesis should be clear, stating expected behavior or characteristics of population parameters such as the mean (\(\mu\)) or standard deviation (\(\sigma\)).
  • Hypotheses that refer to sample statistics (\(\bar{x}\), \(s\), etc.) are not considered legitimate since they refer only to the sample at hand, not the population.
Ensuring that a hypothesis is legitimate means it can be properly tested using statistical methods, thus providing valuable insights into the population it describes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. The article "Properties of Waste Silk Short Fiber/Cellulose Green Composite Films" ( \(J\). of Composite Materials, 2012: 123-127) reported that for a sample of 10 specimens with \(2 \%\) fiber content, the sample mean tensile strength (MPa) was \(51.3\) and the sample standard deviation was 1.2. Suppose the true average strength for \(0 \%\) fibers (pure cellulose) is known to be \(48 \mathrm{MPa}\). Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value?

A sample of \(n\) sludge specimens is selected and the \(\mathrm{pH}\) of each one is determined. The one-sample \(t\) test will then be used to see if there is compelling evidence for concluding that true average \(\mathrm{pH}\) is less than 7.0. What conclusion is appropriate in each of the following situations? a. \(n=6, t=-2.3, \alpha=.05\) b. \(n=15, t=-3.1, \alpha=.01\) c. \(n=12, t=-1.3, \alpha=.05\) d. \(n=6, t=.7, \alpha=.05\) e. \(n=6, \bar{x}=6.68, s / \sqrt{n}=.0820\)

A \(95 \%\) CI for true average amount of warpage \((\mathrm{mm})\) of laminate sheets under specified conditions was calculated as \((1.81,1.95)\), based on a sample size of \(n=15\) and the assumption that amount of warpage is normally distributed. a. Suppose you want to test \(H_{0}^{*} \cdot \mu=2\) versus \(H_{a}^{*}: \mu \neq\) 2 using \(\alpha=.05\). What conclusion would be appropriate, and why? b. If you wanted to use a significance level of \(.01\) for the test in (a), what conclusion would be appropriate?

Reconsider the paint-drying problem discussed in Example 8.5. The hypotheses were \(H_{0}: \mu=75\) versus \(H_{\mathrm{a}}: \mu<75\), with \(\sigma\) assumed to have value 9.0. Consider the alternative value \(\mu=74\), which in the context of the problem would presumably not be a practically significant departure from \(H_{0}\) - a. For a level \(.01\) test, compute \(\beta\) at this alternative for sample sizes \(n=100,900\), and 2500 . b. If the observed value of \(\bar{X}\) is \(\bar{x}=74\), what can you say about the resulting \(P\)-value when \(n=2500\) ? Is the data statistically significant at any of the standard values of \(\alpha\) ? c. Would you really want to use a sample size of 2500 along with a level .01 test (disregarding the cost of such an experiment)? Explain.

The paint used to make lines on roads must reflect enough light to be clearly visible at night. Let \(\mu\) denote the true average reflectometer reading for a new type of paint under consideration. A test of \(H_{0}: \mu=20\) versus \(H_{a}: \mu>20\) will be based on a random sample of size \(n\) from a normal population distribution. What conclusion is appropriate in each of the following situations? a. \(n=15, t=3.2, \alpha=.05\) b. \(n=9, t=1.8, \alpha=.01\) c. \(n=24, t=-.2\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.