/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 85 Let \(X\) have a standard beta d... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(X\) have a standard beta density with parameters \(\alpha\) and \(\beta\). a. Verify the formula for \(E(X)\) given in the section. b. Compute \(E\left[(1-X)^{m}\right]\). If \(X\) represents the proportion of a substance consisting of a particular ingredient, what is the expected proportion that does not consist of this ingredient?

Short Answer

Expert verified
The expected proportion not consisting of the ingredient is \(\frac{\beta}{\alpha + \beta}\).

Step by step solution

01

Recall the Expectation Formula

For a random variable, the expectation or mean of a beta-distributed variable \(X\) with parameters \(\alpha\) and \(\beta\) is given by the formula: \[ E(X) = \frac{\alpha}{\alpha + \beta}. \]
02

Verify the Expectation Formula for Beta Distribution

To verify this, we use the definition of expectation for continuous random variables: \( E(X) = \int_0^1 x f(x) \, dx \), where \( f(x) \) is the beta probability density function: \[ f(x) = \frac{x^{\alpha-1} (1-x)^{\beta-1}}{B(\alpha, \beta)} \] with \( B(\alpha, \beta) \) being the beta function. Substitute the beta PDF into the expectation formula and verify that it simplifies to the given formula for \( E(X) \).
03

Compute the Expectation of \((1-X)^m\)

To compute \( E\left[(1-X)^{m}\right] \), use the integral: \[ E\left[(1-X)^{m}\right] = \int_0^1 (1-x)^{m} \cdot \frac{x^{\alpha-1}(1-x)^{\beta-1}}{B(\alpha, \beta)} \, dx. \] Simplifying this integral gives us: \[ \frac{B(\alpha, \beta + m)}{B(\alpha, \beta)} = \frac{\Gamma(\alpha)\Gamma(\beta + m)\Gamma(\alpha + \beta)}{\Gamma(\alpha + \beta + m)\Gamma(\beta)}. \]
04

Interpret the Expectation for Non-Consisting Proportion

If \(X\) represents the proportion of a substance that includes a particular ingredient, then \(1-X\) represents the proportion that does not contain it. Thus, the expected proportion that does not consist of this ingredient is \(E(1-X)\), which is \(1 - E(X)\). It follows directly that: \[ E(1-X) = \frac{\beta}{\alpha + \beta}. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expectation Formula
The expectation formula provides the average or mean value of a given random variable. In the context of the beta distribution, the expectation (or mean) of a beta-distributed random variable \(X\) with parameters \(\alpha\) and \(\beta\) is calculated using the simple formula:- \[ E(X) = \frac{\alpha}{\alpha + \beta}. \]This formula highlights how the mean of a beta distribution depends on both parameters \(\alpha\) and \(\beta\). When \(\alpha\) is much larger than \(\beta\), \(E(X)\) is closer to 1, indicating a greater proportion of the substance, whereas, if \(\beta\) is larger, the mean shifts closer to 0, indicating less of that substance.

Recall, this formula is derived by setting up the integral \(E(X) = \int_0^1 x f(x) \, dx\), where \(f(x)\) is the beta probability density function (PDF). By using properties of the beta function and continuous random variables, one finds the expectation formula specific to the beta distribution efficiently explains the behavior of \(X\).
Beta Function
The beta function, \(B(\alpha, \beta)\), is a crucial component in understanding the beta distribution. Defined for positive \(\alpha\) and \(\beta\), it is given by the integral:- \[ B(\alpha, \beta) = \int_0^1 t^{\alpha-1} (1-t)^{\beta-1} \, dt. \]This function acts as a normalization constant in the beta probability density function (PDF), ensuring that the total probability integrates to 1.

The significance of the beta function extends beyond normalization; it also simplifies complex integrals involving terms like \(x^{\alpha-1}(1-x)^{\beta-1}\). In relation to the gamma function \(\Gamma\), it can be presented as:- \[ B(\alpha, \beta) = \frac{\Gamma(\alpha) \Gamma(\beta)}{\Gamma(\alpha+\beta)}. \]Understanding this relationship is beneficial as it allows the utilization of gamma function properties to solve problems involving beta functions.

This understanding is especially helpful when computing specific expectations, like \(E[(1-X)^m]\), where transformations and substitutions can leverage properties of the beta function.
Variance of Beta Distribution
Variance is a measure of the dispersion of a set of values around their mean. For a beta-distributed random variable \(X\) with parameters \(\alpha\) and \(\beta\), the variance is given by the formula:- \[ \text{Var}(X) = \frac{\alpha \beta}{(\alpha + \beta)^2 (\alpha + \beta + 1)}. \]This formula provides insight into how the spread of \(X\)'s distribution changes based on \(\alpha\) and \(\beta\).

A larger sum of \(\alpha + \beta\) typically results in a smaller variance, indicating that \(X\) is tightly clustered around its mean. Conversely, smaller values of \(\alpha + \beta\) indicate greater variability, meaning the proportion \(X\) can vary more widely between 0 and 1.

Understanding this concept is key when dealing with proportions or probabilities, as it informs predictions about how consistent a particular proportion might be. For instance, in a context where \(X\) represents the proportion of a specific ingredient, knowing the variance helps in assessing the certainty of that proportion in repeated observations or samples.

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Most popular questions from this chapter

The weight distribution of parcels sent in a certain manner is normal with mean value \(12 \mathrm{lb}\) and standard deviation \(3.5 \mathrm{lb}\). The parcel service wishes to establish a weight value \(c\) beyond which there will be a surcharge. What value of \(c\) is such that \(99 \%\) of all parcels are at least \(1 \mathrm{lb}\) under the surcharge weight?

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