/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 Let \(X\) have a binomial distri... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(X\) have a binomial distribution with parameters \(n=25\) and \(p\). Calculate each of the following probabilities using the normal approximation (with the continuity correction) for the cases \(p=.5, .6\), and \(.8\) and compare to the exact probabilities calculated from Appendix Table A.1. a. \(P(15 \leq X \leq 20)\) b. \(P(X \leq 15)\) c. \(P(20 \leq X)\)

Short Answer

Expert verified
Use normal approximation with continuity correction and compare results with exact values from Table A.1 for each probability case with \( p = 0.5, 0.6, \text{ and } 0.8 \).

Step by step solution

01

Calculate Mean and Standard Deviation

For a binomial distribution, the mean (\( \mu \)) and standard deviation (\( \sigma \)) are calculated as follows: \( \mu = n \times p \) and \( \sigma = \sqrt{n \times p \times (1-p)} \). We'll calculate these for each \( p \) value.
02

Normal Approximation with Continuity Correction for (a)

For event \( P(15 \leq X \leq 20) \), use continuity correction: \( P(14.5 < X < 20.5) \). Convert to the normal distribution using \( Z \) scores: \( Z = \frac{X - \mu}{\sigma} \). Calculate probabilities for each \( p \), using the cumulative standard normal distribution tables or a calculator.
03

Normal Approximation with Continuity Correction for (b)

For event \( P(X \leq 15) \), use continuity correction: \( P(X < 15.5) \). Convert \( X = 15.5 \) to \( Z \) score using \( Z = \frac{X - \mu}{\sigma} \) for each \( p \), and find the probability using standard normal tables.
04

Normal Approximation with Continuity Correction for (c)

For event \( P(20 \leq X) \), use continuity correction: \( P(X > 19.5) \). Calculate \( Z \) score for \( X = 19.5 \) using \( Z = \frac{X - \mu}{\sigma} \) for each \( p \), and find the probability using 1 minus the cumulative standard normal distribution value.
05

Compare with Exact Probabilities

Look up exact probabilities in Appendix Table A.1 for each case with \( p = 0.5, 0.6, \text{ and } 0.8 \) and compare with the approximated probabilities to see the accuracy of the normal approximation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Distribution
A binomial distribution is a specific probability distribution that applies to discrete random events. It models situations where there are two possible outcomes, often referred to as "success" and "failure." The key parameters are:
  • The number of trials (\( n \)). This is how many times the experiment is conducted.
  • The probability of success in each trial (\( p \)). This value should be constant for each trial.
In the exercise case, we have 25 trials, meaning \( n = 25 \). You also have different probabilities of success for each scenario: \( p = 0.5 \), \( p = 0.6 \), and \( p = 0.8 \). The random variable \( X \) represents the number of successes in these 25 trials. Binomial distributions are often used to model real-world phenomena like the flipping of a coin or true/false assessments in statistics tests.
It's important to note that when working with binomial distributions, each trial is independent, and the probability for success remains unchanged throughout the process.
Continuity Correction
When using a continuous distribution like the normal distribution to approximate a discrete one like the binomial distribution, a continuity correction is applied. This adjustment accounts for the fact that discrete values are being approximated by a smooth, continuous curve.To carry out the continuity correction, you adjust your range by 0.5 units. For example:
  • For an inequality like \( P(15 \leq X \leq 20) \), you modify it to \( P(14.5 < X < 20.5) \).
  • For \( P(X \leq 15) \), it changes to \( P(X < 15.5) \).
  • And for \( P(20 \leq X) \), it becomes \( P(X > 19.5) \).
This small adjustment improves the accuracy of the normal approximation by better aligning the area under the curve to match the discrete probabilities of the binomial distribution. It plays a critical role when making the approximation more precise, especially when the number of trials, \( n \), isn't extremely large.
Standard Deviation
Standard deviation, a fundamental concept in statistics, measures the amount of variation or dispersion of a set of values. When dealing with a binomial distribution, standard deviation helps us understand the spread of possible outcomes based on given parameters.The formula for the standard deviation of a binomial distribution is:
  • \( \sigma = \sqrt{n \times p \times (1-p)} \)
Where:
  • \( n \) is the number of trials.
  • \( p \) is the probability of success on each trial.
  • \( 1-p \) represents the probability of failure on each trial.
The standard deviation tells us how much the results can deviate from the expected number of successes, \( \mu \). A larger standard deviation indicates more variability in the number of successes across multiple trials, while a smaller value points to more consistency.
Cumulative Standard Normal Distribution
The cumulative standard normal distribution is a way to calculate probabilities for the normal distribution, which is a continuous probability distribution. This cumulative form gives the probability that a standard normal random variable is less than or equal to a specified value.For a binomial distribution approximated as a normal distribution, you first convert the original values into Z-scores using the formula:
  • \( Z = \frac{X - \mu}{\sigma} \)
Here:
  • \( X \) is the value you're considering.
  • \( \mu \) is the mean of the distribution.
  • \( \sigma \) is the standard deviation.
Once you have the Z-score, you refer to Z-tables (or use technology like calculators) to find the probability that a normally-distributed variable is less than this Z-value. This helps us understand chances of results staying within a particular range in a standard, bell-shaped curve context. Using these cumulative tables is crucial for deriving probabilities when approximating binomial distributions with a normal distribution and applying continuity corrections.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose the proportion \(X\) of surface area in a randomly selected quadrat that is covered by a certain plant has a standard beta distribution with \(\alpha=5\) and \(\beta=2\). a. Compute \(E(X)\) and \(V(X)\). b. Compute \(P(X \leq .2)\). c. Compute \(P(.2 \leq X \leq .4)\). d. What is the expected proportion of the sampling region not covered by the plant?

Let \(X\) represent the number of individuals who respond to a particular online coupon offer. Suppose that \(X\) has approximately a Weibull distribution with \(\alpha=10\) and \(\beta=20\). Calculate the best possible approximation to the probability that \(X\) is between 15 and 20 , inclusive.

Let \(X\) be the temperature in \({ }^{\circ} \mathrm{C}\) at which a certain chemical reaction takes place, and let \(Y\) be the temperature in \({ }^{\circ} \mathrm{F}\) (so \(Y=1.8 X+32\) ). a. If the median of the \(X\) distribution is \(\tilde{\mu}\), show that \(1.8 \tilde{\mu}+32\) is the median of the \(Y\) distribution. b. How is the 90 th percentile of the \(Y\) distribution related to the 90 th percentile of the \(X\) distribution? Verify your conjecture. c. More generally, if \(Y=a X+b\), how is any particular percentile of the \(Y\) distribution related to the corresponding percentile of the \(X\) distribution?

In a road-paving process, asphalt mix is delivered to the hopper of the paver by trucks that haul the material from the batching plant. The article "'Modeling of Simultaneously Continuous and Stochastic Construction Activities for Simulation" (J. of Construction Engr: and Mgmnt., 2013: 1037-1045) proposed a normal distribution with mean value \(8.46 \mathrm{~min}\) and standard deviation \(.913 \mathrm{~min}\) for the rv \(X=\) truck haul time. a. What is the probability that haul time will be at least 10 min? Will exceed \(10 \min\) ? b. What is the probability that haul time will exceed \(15 \mathrm{~min}\) ? c. What is the probability that haul time will be between 8 and \(10 \mathrm{~min}\) ? d. What value \(c\) is such that \(98 \%\) of all haul times are in the interval from \(8.46-c\) to \(8.46+c\) ? e. If four haul times are independently selected, what is the probability that at least one of them exceeds \(10 \mathrm{~min}\) ?

Let \(X=\) the time it takes a read/write head to locate a desired record on a computer disk memory device once the head has been positioned over the correct track. If the disks rotate once every 25 millisec, a reasonable assumption is that \(X\) is uniformly distributed on the interval \([0,25]\). a. Compute \(P(10 \leq X \leq 20)\). b. Compute \(P(X \geq 10)\). c. Obtain the cdf \(F(X)\). d. Compute \(E(X)\) and \(\sigma_{X}\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.