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The article "Expectation Analysis of the Probability of Failure for Water Supply Pipes" (J. of Pipeline Systems Engr. and Practice, May 2012: 36-46) proposed using the Poisson distribution to model the number of failures in pipelines of various types. Suppose that for cast-iron pipe of a particular length, the expected number of failures is 1 (very close to one of the cases considered in the article). Then \(X\), the number of failures, has a Poisson distribution with \(\mu=1\). a. Obtain \(P(X \leq 5)\) by using Appendix Table A.2. b. Determine \(P(X=2)\) first from the pmf formula and then from Appendix Table A.2. c. Determine \(P(2 \leq X \leq 4)\). d. What is the probability that \(X\) exceeds its mean value by more than one standard deviation?

Short Answer

Expert verified
a: Use CDF to find \(P(X \leq 5)\); b: Use PMF and table to confirm \(P(X = 2)\); c: Sum of \(P(X = 2, 3, 4)\); d: Calculate \(P(X \geq 3)\).

Step by step solution

01

Understanding the Poisson Distribution

The Poisson distribution is defined for the number of events in a fixed interval of time or space if these events occur with a known constant mean rate and independently of the time since the last event. Here, the expected number of failures, \(\mu = 1\). Thus, the random variable \(X\) follows a Poisson distribution with \(\lambda = 1\).
02

Obtain \(P(X \leq 5)\) using the Poisson CDF

Use the cumulative distribution function (CDF) for a Poisson random variable with the parameter \(\lambda = 1\) from statistical tables (Appendix Table A.2).\[P(X \leq 5) = \sum_{x=0}^{5} e^{-1} \frac{1^x}{x!}\]Calculate terms individually and sum them up to obtain the probability.
03

Calculate \(P(X=2)\) using the PMF

The probability mass function (PMF) for a Poisson distribution is given by:\[P(X = k) = e^{-\lambda} \frac{\lambda^k}{k!}\]Substituting \(\lambda = 1\) and \(k = 2\):\[P(X = 2) = e^{-1} \frac{1^2}{2!} = \frac{e^{-1}}{2}\]Perform the calculation to find the probability.
04

Validate \(P(X=2)\) using Appendix Table A.2

Check Appendix Table A.2 for the Poisson distribution with \(\lambda = 1\) and \(X = 2\) to confirm the result from Step 2.
05

Calculate \(P(2 \leq X \leq 4)\)

To find \(P(2 \leq X \leq 4)\), calculate the probabilities of each value in the range and sum them:\[P(2 \leq X \leq 4) = P(X=2) + P(X=3) + P(X=4)\]Calculate each term using the PMF formula and sum the results.
06

Determine \(P(X > 2)\) for the Standard Deviation Check

Calculate the standard deviation \(\sigma\) for the Poisson distribution:\[\sigma = \sqrt{\lambda} = \sqrt{1} = 1\]Find \(P(X > 2)\), meaning \(X\) exceeds the mean by more than one standard deviation. This is equivalent to calculating:\[P(X \geq 3)\]Use the complement rule \(1 - P(X \leq 2)\) to calculate it.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Mass Function
The Probability Mass Function (PMF) is a key concept when dealing with discrete probability distributions, such as the Poisson distribution. The PMF provides the probability that a discrete random variable is exactly equal to a specific value. In the context of the Poisson distribution, the PMF can be written as:\[P(X = k) = e^{-\lambda} \frac{\lambda^k}{k!}\]where:
  • \(e\) is the base of the natural logarithm
  • \(\lambda\) is the average rate at which events occur
  • \(k\) is the specific number of events
  • \(k!\) is the factorial of \(k\)
For instance, if \(\lambda = 1\) (where the mean number of pipeline failures is 1), the probability of exactly 2 failures, \(P(X = 2)\), can be found using this formula. Calculating the PMF involves substituting the values into the formula and computing the result. It helps in determining the likelihood of observing a certain number of failures and is crucial for assessing specific scenarios, such as a given number of pipeline failures over a fixed interval.
Cumulative Distribution Function
The Cumulative Distribution Function (CDF) for discrete variables like those in a Poisson distribution represents the probability that a random variable \(X\) is less than or equal to a certain value. The CDF is an aggregation of the PMF values over a range of interest. When you want to know, for example, \(P(X \leq 5)\), you're using the CDF.For the Poisson distribution:\[P(X \leq k) = \sum_{x=0}^{k} e^{-\lambda} \frac{\lambda^x}{x!}\]This formula sums the probabilities of \(X = 0\) up to \(X = k\). By using the CDF, instead of calculating the probability for each individual point and adding them up manually, one can look up these values in statistical tables or compute them from the formula. The CDF thus simplifies finding the probability over a range of values, streamlining calculations for scenarios such as determining pipeline failure rates up to a certain number.
Pipeline Failure Analysis
Pipeline failure analysis involves using statistical models to predict and understand various failure scenarios over time or space. The Poisson distribution is especially suited for events that occur independently with a constant mean rate, making it perfect for modeling pipeline failures.In pipeline management, understanding the expected number of failures can inform maintenance decisions and risk assessments. The Poisson distribution, with its single parameter \(\lambda\), where \(\lambda\) is the expected number of occurrences (failures) within a given period or length, provides a practical approach.Benefits of using the Poisson distribution in pipeline failure analysis include:
  • Predictive insights into potential problem areas
  • Cost-saving strategies by preventive maintenance based on failure probabilities
  • Risk management by preparing for likely failure scenarios
These analyses are crucial for ensuring the reliability and safety of infrastructure like water supply systems.
Standard Deviation in Poisson Distribution
The standard deviation in a Poisson distribution shows the spread or variability of the distribution around the mean. For a Poisson distribution, the standard deviation \(\sigma\) is simply the square root of the mean \(\lambda\). This relationship is expressed as:\[\sigma = \sqrt{\lambda}\]In scenarios like the exercise provided, where \(\lambda = 1\), the standard deviation is also 1. The standard deviation helps determine how much data points are likely to deviate from the mean and is useful for checking probabilities that involve deviations from the mean, such as determining the probability that the number of failures will exceed the mean by more than one standard deviation.Key roles of standard deviation in Poisson analysis include:
  • Assessing the variability compared to the mean, aiding in statistical significance assessments
  • Enabling decision-makers to understand and predict the amount of scatter in failure data
  • Facilitating the establishment of thresholds for anomaly detection in pipeline management

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Most popular questions from this chapter

Eighteen individuals are scheduled to take a driving test at a particular DMV office on a certain day, eight of whom will be taking the test for the first time. Suppose that six of these individuals are randomly assigned to a particular examiner, and let \(X\) be the number among the six who are taking the test for the first time. a. What kind of a distribution does \(X\) have (name and values of all parameters)? b. Compute \(P(X=2), P(X \leq 2)\), and \(P(X \geq 2)\). c. Calculate the mean value and standard deviation of \(X\).

Each time a component is tested, the trial is a success ( \(S\) ) or failure \((F)\). Suppose the component is tested repeatedly until a success occurs on three consecutive trials. Let \(Y\) denote the number of trials necessary to achieve this. List all outcomes corresponding to the five smallest possible values of \(Y\), and state which \(Y\) value is associated with each one.

A certain type of flashlight requires two type-D batteries, and the flashlight will work only if both its batteries have acceptable voltages. Suppose that \(90 \%\) of all batteries from a certain supplier have acceptable voltages. Among ten randomly selected flashlights, what is the probability that at least nine will work? What assumptions did you make in the course of answering the question posed?

An article in the Los Angeles Times (Dec. 3, 1993) reports that 1 in 200 people carry the defective gene that causes inherited colon cancer. In a sample of 1000 individuals, what is the approximate distribution of the number who carry this gene? Use this distribution to calculate the approximate probability that a. Between 5 and 8 (inclusive) carry the gene. b. At least 8 carry the gene.

The article 'Should You Report That FenderBender?" (Consumer Reports, Sept. 2013: 15) reported that 7 in 10 auto accidents involve a single vehicle (the article recommended always reporting to the insurance company an accident involving multiple vehicles). Suppose 15 accidents are randomly selected. Use Appendix Table A.l to answer each of the following questions. a. What is the probability that at most 4 involve a single vehicle? b. What is the probability that exactly 4 involve a single vehicle? c. What is the probability that exactly 6 involve multiple vehicles? d. What is the probability that between 2 and 4 , inclusive, involve a single vehicle? e. What is the probability that at least 2 involve a single vehicle? f. What is the probability that exactly 4 involve a single vehicle and the other 11 involve multiple vehicles?

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