/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 A certain brand of upright freez... [FREE SOLUTION] | 91Ó°ÊÓ

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A certain brand of upright freezer is available in three different rated capacities: \(16 \mathrm{ft}^{3}, 18 \mathrm{ft}^{3}\), and \(20 \mathrm{ft}^{3}\). Let \(X=\) the rated capacity of a freezer of this brand sold at a certain store. Suppose that \(X\) has pmf \begin{tabular}{l|ccc} \(x\) & 16 & 18 & 20 \\ \hline\(p(x)\) & \(.2\) & \(.5\) & \(.3\) \end{tabular} a. Compute \(E(X), E\left(X^{2}\right)\), and \(V(X)\). b. If the price of a freezer having capacity \(X\) is \(70 X-650\), what is the expected price paid by the next customer to buy a freezer? c. What is the variance of the price paid by the next customer? d. Suppose that although the rated capacity of a freezer is \(X\), the actual capacity is \(h(X)=X-.008 X^{2}\). What is the expected actual capacity of the freezer purchased by the next customer?

Short Answer

Expert verified
a. 18.2, 334.4, 3.16; b. 624; c. 15484; d. 15.5248.

Step by step solution

01

Calculate Expected Value, E(X)

We calculate the expected value using the definition: \[ E(X) = \sum x \cdot p(x) \]. For each capacity:- For 16, it contributes \(16 \times 0.2\)- For 18, it contributes \(18 \times 0.5\)- For 20, it contributes \(20 \times 0.3\)Thus, \[ E(X) = 16 \times 0.2 + 18 \times 0.5 + 20 \times 0.3 = 18.2 \].
02

Calculate E(X²)

To calculate this, apply the formula: \[ E(X^2) = \sum x^2 \cdot p(x) \].For each capacity:- For 16, it contributes \(16^2 \times 0.2\)- For 18, it contributes \(18^2 \times 0.5\)- For 20, it contributes \(20^2 \times 0.3\)Thus, \[ E(X^2) = 16^2 \times 0.2 + 18^2 \times 0.5 + 20^2 \times 0.3 = 334.4 \].
03

Calculate Variance, V(X)

Variance is defined as: \[ V(X) = E(X^2) - [E(X)]^2 \].Using the results from previous steps:- \(E(X^2) = 334.4\)- \(E(X) = 18.2\)So, \[ V(X) = 334.4 - (18.2)^2 = 334.4 - 331.24 = 3.16 \].
04

Calculate Expected Price, E(70X - 650)

Use the linear property of expectation: \[ E(70X - 650) = 70E(X) - 650 \].Substituting the value of \(E(X)\):- \(E(X) = 18.2\)So, \[ E(70X - 650) = 70 \times 18.2 - 650 = 1274 - 650 = 624 \].
05

Calculate Variance of the Price

The variance of a transformed variable \(aX + b\) is \(a^2V(X)\). Given:- \(a = 70\)- \(V(X) = 3.16\)So, \[ V(70X - 650) = 70^2 \times 3.16 = 4900 \times 3.16 = 15484 \].
06

Calculate Expected Actual Capacity

Find \(E(h(X))\) using the transformation: \(h(X) = X - 0.008X^2\).Thus:\[ E(h(X)) = E(X - 0.008X^2) = E(X) - 0.008E(X^2) \].From previous results:- \(E(X) = 18.2\)- \(E(X^2) = 334.4\)So, \[ E(h(X)) = 18.2 - 0.008 \times 334.4 = 18.2 - 2.6752 = 15.5248 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expected Value
The Expected Value, commonly represented by \(E(X)\), is a fundamental concept in probability and statistics. It provides a measure of the center of a probability distribution. Simply put, it gives us the long-term average or mean of random experiments if we were to repeat them many times.

Here's how it works: You take each possible value of a random variable, multiply it by its probability, and add these products together. For example, consider our freezer capacities: 16, 18, and 20 cubic feet with probabilities 0.2, 0.5, and 0.3 respectively. To find \(E(X)\), you calculate:
  • \(16 \times 0.2 = 3.2\)
  • \(18 \times 0.5 = 9.0\)
  • \(20 \times 0.3 = 6.0\)
By summing these values, you get \(E(X) = 3.2 + 9.0 + 6.0 = 18.2\). Thus, the expected capacity for the freezer is 18.2 cubic feet.

For more complex transformations, such as \(h(X) = X - 0.008X^2\), the expected value can be calculated by applying the expectation operator across the function, resulting in \(E(h(X)) = E(X) - 0.008E(X^2)\). This ensures that all transformations maintain the random variable's probabilistic structure while providing insightful results.
Variance
Variance, denoted as \(V(X)\), measures the dispersion of a set of values. Unlike the expected value, which tells us the average outcome, variance indicates how spread out the data points are from the expected value. Understanding variance is crucial because it helps us to appreciate the extent and frequency of deviations from the expected value.

Mathematically, variance is determined using the formula:\[ V(X) = E(X^2) - [E(X)]^2 \]Using our example, first, we computed \(E(X^2)\) by squaring each capacity value, multiplying by its probability, and summing the results:
  • \(16^2 \times 0.2 = 51.2\)
  • \(18^2 \times 0.5 = 162\)
  • \(20^2 \times 0.3 = 120\)
This results in \(E(X^2) = 51.2 + 162 + 120 = 333.2\). The variance is then found by subtracting the square of the expected value: \(334.4 - (18.2)^2 = 3.16\).

A higher variance indicates greater variability in the potential values, while a low variance reflects that the values are fairly uniform and close to the expected value. This information is key to making predictions and understanding the behavior of random variables.
Linear Transformation of Random Variables
When dealing with random variables, often we are interested in transformations, which are linear in nature. These transformations can adjust the location and scale of our data, which is of particular importance when translating theoretical results into practical scenarios.

Assume a linear transformation in the form \(Y = aX + b\). This formula allows us to transform the random variable \(X\) into \(Y\). For example, in the freezer problem, the price \(P\) of a freezer was formulated as \(70X - 650\). Here, \(a = 70\) and \(b = -650\).

The Expected Value under a linear transformation follows a simple rule:\[ E(aX + b) = aE(X) + b \]Using the given example, \(E(70X - 650)\) is calculated as:
  • \(70 \times 18.2 - 650 = 624\)
Similarly, the Variance for a linear transformation is:\[ V(aX + b) = a^2V(X) \]This means variances are only affected by the scaling factor, and shifts (as determined by \(b\)) do not affect it. In the freezer problem, this results in:
  • \(70^2 \times 3.16 = 15484\)
These rules allow us to predict the new expected value and variance of a transformed variable, which are helpful in fields like finance, engineering, and operations research.

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