/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 The pmf of the amount of memory ... [FREE SOLUTION] | 91Ó°ÊÓ

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The pmf of the amount of memory \(X(G B)\) in a purchased flash drive was given in Example \(3.13\) as \begin{tabular}{l|lllll} \(x\) & 1 & 2 & 4 & 8 & 16 \\ \hline\(p(x)\) & \(.05\) & \(.10\) & \(.35\) & \(.40\) & \(.10\) \end{tabular} Compute the following: a. \(E(X)\) b. \(V(X)\) directly from the definition c. The standard deviation of \(X\) d. \(V(X)\) using the shortcut formula

Short Answer

Expert verified
a. 6.45; b. 15.6475; c. 3.95; d. 15.6475.

Step by step solution

01

Calculate Expected Value E(X)

To find the expected value, we use the formula \( E(X) = \sum x \, p(x) \). We substitute the provided values:\[E(X) = (1)(0.05) + (2)(0.10) + (4)(0.35) + (8)(0.40) + (16)(0.10)\]Calculate each term:* \(1 \times 0.05 = 0.05\)* \(2 \times 0.10 = 0.20\)* \(4 \times 0.35 = 1.40\)* \(8 \times 0.40 = 3.20\)* \(16 \times 0.10 = 1.60\)Now, sum these values:\[E(X) = 0.05 + 0.20 + 1.40 + 3.20 + 1.60 = 6.45\]
02

Calculate Variance V(X) using Definition

The variance is given by the formula \( V(X) = \sum (x - E(X))^2 \, p(x) \). First, find \((x - E(X))^2\) for each value of \(x\):* For \(x = 1\): \((1 - 6.45)^2 \, p(1) = 29.7025 \, (0.05) = 1.485125\)* For \(x = 2\): \((2 - 6.45)^2 \, p(2) = 19.8025 \, (0.10) = 1.98025\)* For \(x = 4\): \((4 - 6.45)^2 \, p(4) = 6.0025 \, (0.35) = 2.100875\)* For \(x = 8\): \((8 - 6.45)^2 \, p(8) = 2.4025 \, (0.40) = 0.961\)* For \(x = 16\): \((16 - 6.45)^2 \, p(16) = 91.2025 \, (0.10) = 9.12025\)Sum these contributions to obtain:\[V(X) = 1.485125 + 1.98025 + 2.100875 + 0.961 + 9.12025 = 15.6475\]
03

Compute Standard Deviation of X

The standard deviation is the square root of the variance:\[\sigma = \sqrt{V(X)} = \sqrt{15.6475} \approx 3.95\]
04

Calculate Variance V(X) using the Shortcut Formula

The shortcut formula for variance is \( V(X) = E(X^2) - (E(X))^2 \). First, calculate \(E(X^2)\):\[E(X^2) = \sum x^2 \, p(x) = (1^2)(0.05) + (2^2)(0.10) + (4^2)(0.35) + (8^2)(0.40) + (16^2)(0.10)\]Calculate each term:* \(1^2 \times 0.05 = 0.05\)* \(4 \times 0.10 = 0.40\)* \(16 \times 0.35 = 5.60\)* \(64 \times 0.40 = 25.60\)* \(256 \times 0.10 = 25.60\)Sum these values to find \(E(X^2)\):\[E(X^2) = 0.05 + 0.40 + 5.60 + 25.60 + 25.60 = 57.25\]Now use the shortcut formula:\[V(X) = 57.25 - (6.45)^2 = 57.25 - 41.6025 = 15.6475\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expected Value
Let's talk about the expected value, often symbolized as \( E(X) \), which can be thought of as the "average" outcome of a random variable when considering all possible outcomes and their probabilities. It's a fundamental concept in probability that helps you predict what to expect on average from a random process.
The expected value can be calculated using the probability mass function (PMF), which is a way of expressing the probabilities of discrete random variables.

To compute it, you apply the formula: \( E(X) = \sum x \, p(x) \), where \( x \) represents all the possible values the variable can take and \( p(x) \) is the probability associated with each value. You essentially multiply each value \( x \) by its respective probability \( p(x) \) and sum up all these products.
  • This gives you a singular, informative number that represents the central tendency of your random variable.
  • In practice, this helps in various fields from finance to engineering, providing guidance on what to expect in the long term.
The expected value in our exercise calculated as \( E(X) = 6.45 \) tells us that, on average, we could expect around 6.45 GB from a randomly purchased flash drive using the given PMF.
Variance
Variance, denoted as \( V(X) \), is a measure of the spread or dispersion of a set of values. It tells us how much the values of a random variable differ from the expected value. If the variance is large, the numbers are spread far from the mean, indicating volatility.

To get the variance, we use the formula \( V(X) = \sum (x - E(X))^2 \, p(x) \). This process involves:
  • Subtracting the expected value \( E(X) \) from each possible value \( x \),
  • Squaring these differences to remove any negative signs (and emphasize larger deviations),
  • Multiplying each squared difference by its respective probability \( p(x) \),
  • Then summing these products to yield the variance.
Variance tells you how "spread out" your data points are. For instance, a variance of \( 15.6475 \) as in our exercise indicates there is a noticeable dispersion in the storage sizes of the flash drives from the average.
Standard Deviation
Standard deviation is a statistical measure of how dispersed the values are in a data set, and it's the square root of the variance. Represented by the symbol \( \sigma \), the standard deviation is often easier to interpret because it shares the same units as the original data.

To find the standard deviation, you simply take the square root of the variance:
  • Use \( \sigma = \sqrt{V(X)} \).
  • This transforms the variance into a metric that often makes more intuitive sense than squared units.
For example, in our exercise, the variance was \( 15.6475 \), leading to a standard deviation of approximately \( 3.95 \). This means the memory sizes of purchased flash drives typically deviate by around 3.95 GB from the average of 6.45 GB, providing a clearer view of variability in terms you already understand - gigabytes.
Shortcut Formula
The shortcut formula for variance provides a quick way to compute variance without diving directly into the variance definition, saving time especially in more complex calculations.

The formula is \( V(X) = E(X^2) - (E(X))^2 \). Here's how it works:
  • First, calculate \( E(X^2) \) which is the expected value of the square of the random variable, using \( \sum x^2 \, p(x) \). You square each possible value \( x \) first, multiply by its probability \( p(x) \), and sum these products.
  • Next, subtract the square of the expected value \((E(X))^2\).
The elegance is in its efficiency, especially when computations grow complex.

In our exercise, \( E(X^2) = 57.25 \) and \( E(X) = 6.45 \) resulted in \( V(X) = 57.25 - 41.6025 = 15.6475 \). This efficiently confirms the variance, offering the same results as the direct calculation.

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Most popular questions from this chapter

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