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Again consider a Little League team that has 15 players on its roster. a. How many ways are there to select 9 players for the starting lineup? b. How many ways are there to select 9 players for the starting lineup and a batting order for the 9 starters? c. Suppose 5 of the 15 players are left-handed. How many ways are there to select 3 left-handed outfielders and have all 6 other positions occupied by right-handed players?

Short Answer

Expert verified
a. 5005 b. 1816214400 c. 2100

Step by step solution

01

Selecting 9 Players

To find how many ways there are to select 9 players from 15, we use the combination formula: \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \). Here, \( n = 15 \) and \( k = 9 \). Calculate \( \binom{15}{9} = \frac{15!}{9!6!} \).
02

Calculating Combination

Calculate \( 15! \), \( 9! \), and \( 6! \) separately, then substitute back into the combination formula to find the value of \( \binom{15}{9} \). It simplifies to \( \binom{15}{9} = 5005 \).
03

Selecting with Batting Order

Once the 9 players are selected, they can be arranged in a batting order (permutation) of 9. Use the permutation formula for 9 distinct players, which is \( 9! = 362880 \).
04

Calculate Total Batting Arrangements

Multiply the number of ways to select 9 players \( \binom{15}{9} \) with the permutations of 9 players \( 9! \). This is \( 5005 \times 362880 = 1816214400 \).
05

Selecting Left-Handed Outfielders

To select 3 outfielders from the 5 left-handed players, use the combination formula \( \binom{5}{3} = 10 \).
06

Selecting Right-Handed Players for Other Positions

To fill the remaining 6 positions with right-handed players (10 right-handed available), use \( \binom{10}{6} \). Calculate \( \binom{10}{6} = 210 \).
07

Calculate Total Ways for Left-Handed Outfielders and Right-Handed Players

Multiply the ways to choose left-handed outfielders and the ways to choose right-handed players: \( 10 \times 210 = 2100 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Permutations
In combinatorics, permutations are all about arranging a set of objects in a particular order. Imagine you have a certain number of distinct players and you want to decide in which order they should bat. This is a classic example of a permutation problem. When order matters in the arrangement, you use permutations.

### Example of Permutations
When you're figuring out a batting order for the starting players in a baseball game, each player has a unique spot in the lineup, making the problem a permutation. For 9 players, there are several arrangements or orders possible, calculated by the formula for permutations: - The number of permutations of a set of 9 players is given by the factorial of 9, noted as 9!.
### Calculation The expression 9! (pronounced "9 factorial") equals 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 362,880. This number represents all possible sequences in which 9 players can be arranged.

Understanding permutations helps in problems where the sequence or order is crucial, just like setting up a batting lineup in a sports team.
Combinations
Combinations are a fundamental concept in combinatorics, dealing with the selection of items from a larger set. The key difference from permutations is that with combinations, the order of items does not matter. It's all about selecting groups from a set.

### Real-World Example
Consider choosing 9 players for a starting lineup from a total of 15 players. Here, the order in which players are picked does not matter, just the selection itself. That's why you'll use combinations for this task.- The formula to calculate combinations is given by: \[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \] - Where \( n \) is the total number of items, and \( k \) is the number of items to choose.
### CalculationApplying this to the exercise: You have 15 players in total and need to select 9, so, \( \binom{15}{9} = \frac{15!}{9!6!} = 5005 \). This tells you there are 5005 different ways to pick those 9 players, regardless of their arrangement.

Combinations are all about finding how many possible groups or sets can be formed, without worrying about order.
Probability Theory
Probability theory is a branch of mathematics that deals with analyzing random events. When you hear about chances and risks, it's often linked to principles of probability. In sports, it governs the likelihood of different outcomes in team formation, batting orders, or even winning a game.

### Understanding Probability in Team Formation
When selecting and ordering players to maximize your team's strengths, probability theory comes into play. Using combinations and permutations helps in calculating the number of successful ways to form such a winning team.
  • The likelihood of forming a lineup with certain characteristics (like number of left-handed players) may depend on probability calculations.
  • Each selection or arrangement might serve as an event in a probability space, where you're interested in "successful" or "winning" outcomes.
Ultimately, every calculated way of forming and arranging a team gives us insight into strategic possibilities, tied to probability theory.
Factorials
Factorials are the building blocks in much of combinatorial mathematics. They play a crucial role in calculating permutations and combinations by influencing how we quantify arrangements or selections of items.

### What Is a Factorial?
A factorial, represented with an exclamation point (e.g., \( n! \)), is a product of all positive integers up to a certain number \( n \). For example, \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \).- Used in both permutations \( n! \) counts all distinct possible arrangements of \( n \) items.- In combinations, it helps simplify expressions such as \( \frac{n!}{k!(n-k)!} \).

Factorials allow efficient computation of complex arrangement and selection problems in probability and statistics. They break down large tasks into manageable calculations, making complex scenarios easy to analyze.

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Most popular questions from this chapter

The three most popular options on a certain type of new car are a built-in GPS \((A)\), a sunroof \((B)\), and an automatic transmission \((C)\). If \(40 \%\) of all purchasers request \(A, 55 \%\) request \(B, 70 \%\) request \(C, 63 \%\) request \(A\) or \(B\), \(77 \%\) request \(A\) or \(C, 80 \%\) request \(B\) or \(C\), and \(85 \%\) request \(A\) or \(B\) or \(C\), determine the probabilities of the following events. [Hint: " \(A\) or \(B\) " is the event that at least one of the two options is requested; try drawing a Venn diagram and labeling all regions.] a. The next purchaser will request at least one of the three options. b. The next purchaser will select none of the three options. c. The next purchaser will request only an automatic transmission and not either of the other two options. d. The next purchaser will select exactly one of these three options.

Show that \(\left(\begin{array}{c}n \\\ k\end{array}\right)=\left(\begin{array}{c}n \\ n-k\end{array}\right)\). Give an interpretation involving subsets.

An insurance company offers four different deductible levels-none, low, medium, and high-for its homeowner's policyholders and three different levels- low, medium, and high-for its automobile policyholders. The accompanying table gives proportions for the various categories of policyholders who have both types of insurance. For example, the proportion of individuals with both low homeowner's deductible and low auto deductible is \(.06\) (6\% of all such individuals). $$ \begin{array}{lcccc} && {\text { Homeowner's }} \\ \text { Auto } & \mathbf{N} & \mathbf{L} & \mathbf{M} & \mathbf{H} \\ \hline \mathbf{L} & .04 & .06 & .05 & .03 \\ \mathbf{M} & .07 & .10 & .20 & .10 \\ \mathbf{H} & .02 & .03 & .15 & .15 \\ \hline \end{array} $$ Suppose an individual having both types of policies is randomly selected. a. What is the probability that the individual has a medium auto deductible and a high homeowner's deductible? b. What is the probability that the individual has a low auto deductible? A low homeowner's deductible? c. What is the probability that the individual is in the same category for both auto and homeowner's deductibles? d. Based on your answer in part (c), what is the probability that the two categories are different? e. What is the probability that the individual has at least one low deductible level? f. Using the answer in part (e), what is the probability that neither deductible level is low?

A friend of mine is giving a dinner party. His current wine supply includes 8 bottles of zinfandel, 10 of merlot, and 12 of cabernet (he only drinks red wine), all from different wineries. a. If he wants to serve 3 bottles of zinfandel and serving order is important, how many ways are there to do this? b. If 6 bottles of wine are to be randomly selected from the 30 for serving, how many ways are there to do this? c. If 6 bottles are randomly selected, how many ways are there to obtain two bottles of each variety? d. If 6 bottles are randomly selected, what is the probability that this results in two bottles of each variety being chosen? e. If 6 bottles are randomly selected, what is the probability that all of them are the same variety?

A department store sells sport shirts in three sizes (small, medium, and large), three patterns (plaid, print, and stripe), and two sleeve lengths (long and short). The accompanying tables give the proportions of shirts sold in the various category combinations. $$ \begin{aligned} &\text { Short-sleeved }\\\ &\begin{array}{lccc} \hline & {\text { Pattern }} \\ \text { Size } & \text { Pl } & \text { Pr } & \text { St } \\ \hline \mathbf{S} & .04 & .02 & .05 \\ \mathbf{M} & .08 & .07 & .12 \\ \mathbf{L} & .03 & .07 & .08 \\ \hline \end{array} \end{aligned} $$ $$ \begin{aligned} &\text { Long-sleeved }\\\ &\begin{array}{lccc} \hline & {c}{\text { Pattern }} \\ \text { Size } & \text { Pl } & \text { Pr } & \text { St } \\ \hline \mathbf{S} & .03 & .02 & .03 \\ \mathbf{M} & .10 & .05 & .07 \\ \mathrm{~L} & .04 & .02 & .08 \\ \hline \end{array} \end{aligned} $$ a. What is the probability that the next shirt sold is a medium, long-sleeved, print shirt? b. What is the probability that the next shirt sold is a medium print shirt? c. What is the probability that the next shirt sold is a short-sleeved shirt? A long-sleeved shirt? d. What is the probability that the size of the next shirt sold is medium? That the pattern of the next shirt sold is a print? e. Given that the shirt just sold was a short-sleeved plaid, what is the probability that its size was medium? f. Given that the shirt just sold was a medium plaid, what is the probability that it was short-sleeved? Long-sleeved?

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