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Suppose that in a certain chemical process the reaction time \(y(\mathrm{hr})\) is related to the temperature \(\left({ }^{\circ} \mathrm{F}\right)\) in the chamber in which the reaction takes place according to the simple linear regression model with equation \(y=\) \(5.00-.01 x\) and \(\sigma=.075\). a. What is the expected change in reaction time for a \(1^{\circ} \mathrm{F}\) increase in temperature? For a \(10^{\circ} \mathrm{F}\) increase in temperature? b. What is the expected reaction time when temperature is \(200^{\circ} \mathrm{F}\) ? When temperature is \(250^{\circ} \mathrm{F}\) ? c. Suppose five observations are made independently on reaction time, each one for a temperature of \(250^{\circ} \mathrm{F}\). What is the probability that all five times are between \(2.4\) and \(2.6 \mathrm{hr}\) ? d. What is the probability that two independently observed reaction times for temperatures \(1^{\circ}\) apart are such that the time at the higher temperature exceeds the time at the lower temperature?

Short Answer

Expert verified
a. -0.01 hr for 1°F, -0.1 hr for 10°F. b. 3.00 hr at 200°F, 2.5 hr at 250°F. c. 0.368 d. 0.5

Step by step solution

01

Understanding the Model

The given linear regression model is \( y = 5.00 - 0.01x \). Here, \( y \) represents the reaction time in hours, \( x \) is the temperature in degrees Fahrenheit, and \( \sigma = 0.075 \) indicates the standard deviation of the reaction time.
02

Calculating Change in Reaction Time for Temperature Change

The coefficient of \( x \) in the equation \( y = 5.00 - 0.01x \) is \(-0.01\). This coefficient means that for every \( 1^{\circ} \mathrm{F} \) increase in temperature, the reaction time decreases by \( 0.01 \) hours.- For a \( 1^{\circ} \mathrm{F} \) increase: Change in time = \( -0.01 \) hours- For a \( 10^{\circ} \mathrm{F} \) increase: Change in time = \( -0.01 \times 10 = -0.1 \) hours.
03

Calculating Expected Reaction Time

Using the equation \( y = 5.00 - 0.01x \), we find the expected reaction time for given temperatures:- For \( x = 200^{\circ} \mathrm{F} \): \[ y = 5.00 - 0.01 \times 200 = 5.00 - 2 = 3.00 \] hours.- For \( x = 250^{\circ} \mathrm{F} \): \[ y = 5.00 - 0.01 \times 250 = 5.00 - 2.5 = 2.5 \] hours.
04

Calculating Probability for Reaction Time Interval

Since the reaction time is normally distributed with \( \sigma = 0.075 \), we find the probability that the reaction time is between 2.4 and 2.6 hours at \( x = 250^{\circ} \mathrm{F} \) (\( \mu = 2.5 \)). The probability for one observation is:\[ P(2.4 < y < 2.6) = P\left(\frac{2.4 - 2.5}{0.075} < Z < \frac{2.6 - 2.5}{0.075}\right) = P(-1.33 < Z < 1.33) \]Using standard normal distribution tables or calculators, \( P(-1.33 < Z < 1.33) \approx 0.8165 \).For five independent observations, the probability is \((0.8165)^5 \approx 0.368 \).
05

Probability Reaction Time at Higher Temperature Exceeds Lower

For temperatures \( 1^{\circ} \mathrm{F} \) apart, the difference in reaction time due to the coefficient \( -0.01 \) is \( y_1 - y_2 = 0.01 \times 1 = 0.01 \).The variance of the difference \( y_1 - y_2 \) is \( 2(\sigma^2) = 2(0.075^2) \).The probability \( P(y_1 > y_2) = P\left(\frac{y_1 - y_2}{\sqrt{2(0.075)^2}} < 0 \right) \) is a standard normal distribution problem for zero difference.The probability is \( P(Z < 0) = 0.5 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Regression
Linear regression is a statistical method used to model the relationship between two variables by fitting a linear equation to observed data. In our exercise, the linear regression model is represented by the equation \( y = 5.00 - 0.01x \). Here, \( y \) is the dependent variable, representing the reaction time in hours, while \( x \) is the independent variable, symbolizing the temperature in degrees Fahrenheit. The equation suggests a negative linear relationship between temperature and reaction time. For every 1-degree Fahrenheit increase in temperature, the reaction time decreases by 0.01 hours, as indicated by the coefficient \(-0.01\). This coefficient is crucial—it quantifies the rate at which the reaction time changes relative to temperature.

In linear regression, the intercept and slope play vital roles. The intercept here is 5.00, suggesting that if the temperature were zero (which might not be practical in this context), the expected reaction time would be five hours. The slope determines the direction and steepness of the line—indicating how much \( y \) increases or decreases as \( x \) changes. This model simplifies predicting changes in reaction time with temperature variations.
Normal Distribution
A normal distribution, also known as a Gaussian distribution, is a probability distribution characterized by its bell-shaped curve. It is defined by two parameters: the mean (\( \mu \)) and the standard deviation (\( \sigma \)). In this exercise, the reaction time is assumed to be normally distributed with mean \( \mu = 2.5 \) at a temperature of \( 250^{\circ} \mathrm{F} \). The standard deviation is given as 0.075 hours.

This distribution helps in determining the likelihood of various outcomes. A key feature of the normal distribution is that it is symmetrical around its mean, meaning the probability of observed values being a certain distance from the mean is the same in both directions. This trait allows us to calculate probabilities for different intervals of reaction time.

For example, calculating the probability that reaction times are between 2.4 and 2.6 hours involves standardizing these values to find where they fall on the normal curve, using the Z-score formula \( Z = \frac{x - \mu}{\sigma} \). This Z-score provides an easily interpretable standard measure that can be looked up in standard normal distribution tables or calculated using statistical software.
Standard Deviation
Standard deviation is a measure of dispersion in data from its mean, reflecting how much the values deviate from the average. In our model, the standard deviation \( \sigma \) is 0.075, suggesting that most of the reaction time data points are within 0.075 hours of the mean.

This value is essential for understanding the spread or variability of reaction times at a specific temperature. A smaller standard deviation implies that the data points are closer to the mean, indicating consistency and precision in the measured reaction times. Conversely, a larger standard deviation means the data points are more spread out, showing a higher variation in the reaction times.

Standard deviation is crucial in the context of statistical modeling and probability calculations. It is used not only to determine how spread out the data is but also to standardize data for the normal distribution. In the exercise, it helps us calculate the Z-scores, which tell us how many standard deviations an element is from the mean, allowing us to determine probabilities and percentiles effectively.
Statistical Modelling
Statistical modeling involves creating representations of complex real-world processes using mathematical formulas and algorithms. This exercise demonstrates statistical modeling through the use of linear regression to model the relationship between temperature and reaction time.

The model \( y = 5.00 - 0.01x \) is a simple linear regression model where the slope and intercept provide the essential parameters for prediction. Besides helping in making predictions, statistical models also allow for hypothesis testing, estimates of confidence intervals, and other inferential statistics.

In addition to constructing the model, understanding the variability and distribution of data is crucial. The normal distribution and standard deviation describe data behavior, aiding in probability calculations and predictions. These statistical tools support decision-making by providing quantitative predictions augmented by calculated uncertainties.

Overall, statistical modeling is an indispensable tool in scientific research and industry, enabling analysts to abstract complex systems into understandable and predictable models backed by statistical theory.

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Most popular questions from this chapter

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