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The first four deviations from the mean in a sample of \(n=5\) reaction times were \(.3, .9,1.0\), and \(1.3\). What is the fifth deviation from the mean? Give a sample for which these are the five deviations from the mean.

Short Answer

Expert verified
The fifth deviation is -3.5 and a sample set is 0.3, 0.9, 1.0, 1.3, -3.5.

Step by step solution

01

Understand Deviations

In a sample, deviations from the mean are calculated by subtracting each data point from the mean. The sum of all these deviations equals zero. This is an important property we will use to find the unknown fifth deviation.
02

Set Up the Equation

Let the fifth deviation be represented by \(x\). We know the sum of deviations must be zero. Therefore, \(0.3 + 0.9 + 1.0 + 1.3 + x = 0\).
03

Calculate the Fifth Deviation

Simplify the equation from Step 2: \(3.5 + x = 0\). To solve for \(x\), subtract 3.5 from both sides to get \(x = -3.5\). Thus, the fifth deviation is \(-3.5\).
04

Provide a Sample with Given Deviations

If the deviations from the mean for the sample are \(0.3, 0.9, 1.0, 1.3, -3.5\), we can create a sample as follows: subtract each deviation from the mean (let's assume the mean is zero for simplicity). The deviations can be considered data points \(x_1\), \(x_2\), \(x_3\), \(x_4\), and \(x_5\) such that \(x_1 = 0 + 0.3, x_2 = 0 + 0.9, x_3 = 0 + 1.0, x_4 = 0 + 1.3, x_5 = 0 - 3.5\). This results in the sample: \(0.3, 0.9, 1.0, 1.3, -3.5\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Deviation
Mean deviation is a useful statistical concept that helps us understand how much data points differ from their average (the mean). To find the mean deviation, each data point in a set is subtracted from the average. This shows us the individual differences between the data points and their mean.
The mean deviation provides insights into the variability within a dataset. The larger the mean deviation, the more spread out the data points are from the mean. Conversely, a smaller mean deviation indicates that the data points are closely packed around the mean.
It’s calculated by taking the absolute values of deviations. While it might seem complex at first, it’s essentially about assessing how distributed the values are around their center. This can be particularly helpful for identifying patterns or anomalies in data.
Sample Data Points
Sample data points are the individual values that constitute a data set. In the context of deviations from the mean, each sample data point can be seen as a building block that defines the dataset’s overall characteristics.
When dealing with sample data points, the deviations from the mean for each of these points can tell us a lot about their arrangement. For example, in our given exercise, the deviations tell us how far each reaction time is from their calculated average.
By looking at these deviations, one can infer whether most data points are similar to each other or vary greatly. Understanding each data point's deviation helps identify any outliers or irregular patterns in the dataset. This is crucial for detailed data analysis and making accurate predictions.
Sum of Deviations Equals Zero
A fundamental property in statistics is that the sum of deviations from the mean in any dataset equals zero. This happens because the mean is the balance point of the data, meaning all positive deviations are perfectly counterbalanced by negative ones.
In mathematical terms, for a sample with data points \(x_1, x_2, \ldots, x_n\) and a mean \( \bar{x} \), the sum of deviations can be expressed as \( (x_1 - \bar{x}) + (x_2 - \bar{x}) + \ldots + (x_n - \bar{x}) = 0 \). Hence, any deviation missing from the calculation can easily be deduced by ensuring the sum is zero.
This property is essential in our exercise because it allows us to figure out the missing fifth deviation by ensuring the total sum of deviations is zero. Understanding this principle aids in various data analyses, confirming that datasets are centered around their calculated mean.

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Most popular questions from this chapter

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