/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 The accompanying table gives sum... [FREE SOLUTION] | 91Ó°ÊÓ

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The accompanying table gives summary data on cube compressive strength \(\left(\mathrm{N} / \mathrm{mm}^{2}\right)\) for concrete specimens made with a pulverized fuel-ash mix ("A Study of Twenty-FiveYear-Old Pulverized Fuel Ash Concrete Used in Foundation Structures," Proc. Inst. Civ. Engrs., Mar. 1985: 149-165): \begin{tabular}{cccc} Age (days) & Sample Size & Sample Mean & Sample SD \\ \hline 7 & 68 & \(26.99\) & \(4.89\) \\ 28 & 74 & \(35.76\) & \(6.43\) \\ \hline \end{tabular} Calculate and interpret a \(99 \%\) CI for the difference between true average 7 -day strength and true average 28 -day strength.

Short Answer

Expert verified
The 99% CI does not include zero, indicating a significant difference in compressive strengths at 7 and 28 days.

Step by step solution

01

Step 1

Understand the given data and what needs to be calculated. We are asked to find a 99% Confidence Interval (CI) for the difference between the true average 7-day and 28-day cube compressive strength. This means we need to calculate the difference in mean compressive strengths with their standard deviations and use them to find the confidence interval.
02

Calculate the Standard Error

The standard error of the difference between two sample means is given by the formula: \[SE = \sqrt{\frac{{s_1^2}}{n_1} + \frac{{s_2^2}}{n_2}}\]where \(s_1 = 4.89\), \(n_1 = 68\), \(s_2 = 6.43\), and \(n_2 = 74\). Calculate the standard error using these values.
03

Determine the t-value

Since we are calculating a 99% CI, the confidence level is 99%. For degrees of freedom that approximate large samples, the t-value can be approximated using a t-distribution table or calculator. For high degrees of freedom, this value is approximately 2.626.
04

Calculate the Confidence Interval

The confidence interval for the difference in means \((\mu_1 - \mu_2)\) is calculated using:\[(\bar{x}_1 - \bar{x}_2) \pm t \times SE\]Where \(\bar{x}_1 = 26.99\), \(\bar{x}_2 = 35.76\), and the values from previous steps for \(t\) and \(SE\). Compute this to get the lower and upper bounds of the interval.
05

Interpret the Confidence Interval

If the calculated confidence interval for the difference does not include zero, it suggests that there is a statistically significant difference between the true average strengths for the 7-day and 28-day specimens at the 99% confidence level. State whether this is the case based on your calculations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Standard Error
The standard error is a crucial concept when estimating a confidence interval. It quantifies the variability or spread of the sample mean. In simpler terms, it tells us how much the sample mean is expected to differ from the true population mean. The standard error of the difference between two sample means is calculated using the formula: \[ SE = \sqrt{\frac{{s_1^2}}{n_1} + \frac{{s_2^2}}{n_2}} \]Here:
  • \(s_1\) and \(s_2\) are the standard deviations of the two samples.
  • \(n_1\) and \(n_2\) are the sample sizes.
This formula essentially combines the variability from both samples to give a single measure of how much the difference between sample means is expected to vary from the true difference in population means.
Understanding the standard error aids in gauging how precise our estimate is and forms the basis for constructing confidence intervals.
Exploring t-Distribution
When dealing with small sample sizes, or when the population standard deviation is unknown, the t-distribution is employed over the normal distribution. It is similar in shape to the normal distribution but has fatter tails. This implies that there is more probability in the extremities of the distribution.
The t-distribution accounts for the added uncertainty that comes with estimating the population standard deviation from a sample. The exact shape of the t-distribution depends on the degrees of freedom, a concept we will discuss later.
A t-value derived from a t-distribution helps us determine how many standard errors away from the sample mean our true population mean is likely to be. In our exercise, the t-value is used alongside the standard error to compute the confidence interval for the difference between two means.
The Role of Sample Mean
The sample mean is a fundamental statistic that represents the average of a sample dataset. It provides a single value that summarizes the data collected from a sample. The formula to calculate the sample mean is:\[ \bar{x} = \frac{\sum{x_i}}{n} \]Where:
  • \(\bar{x}\) is the sample mean.
  • \(\sum{x_i}\) is the sum of all observations in the sample.
  • \(n\) is the number of observations in the sample.
In the context of calculating a confidence interval, the sample means are used to estimate the difference in population means between two groups. This helps determine whether the observed differences are statistically significant.
The sample mean is a cornerstone in statistical analysis because it gives us a point estimate of what the population mean could be based on our sample. In the exercise, the given sample means for 7-day and 28-day strength are used to evaluate the likely range of difference in true average strengths.
Degrees of Freedom Explained
Degrees of freedom is a statistical concept that describes the number of values in a calculation that have the freedom to vary. It is used to ensure that statistical estimates have been standardized in some form.
In contexts such as using the t-distribution, degrees of freedom generally depend on the sample size. When calculating the standard error or when looking up critical values in a t-distribution table, degrees of freedom come into play.
For instance, when estimating the variance from a sample, degrees of freedom equal \(n - 1\), where \(n\) is the sample size. This adjustment accounts for the fact that we lose a degree of freedom when estimating the mean from the sample itself. Thus, the larger the degrees of freedom, the closer the t-distribution approximates the normal distribution. This is what makes the degree of freedom critical in choosing an accurate t-value for constructing our confidence interval.

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Most popular questions from this chapter

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