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Give as much information as you can about the \(P\)-value of a \(t\) test in each of the following situations: a. Upper-tailed test, df \(=8, t=2.0\) b. Lower-tailed test, \(\mathrm{df}=11, t=-2.4\) c. Two-tailed test, df \(=15, t=-1.6\) d. Upper-tailed test, df \(=19, t=-.4\) e. Upper-tailed test, \(\mathrm{df}=5, t=5.0\) f. Two-tailed test, \(\mathrm{df}=40, t=-4.8\)

Short Answer

Expert verified
P-values are approximate: a) 0.05, b) 0.02, c) 0.13, d) >0.65, e) <0.001, f) <0.0002.

Step by step solution

01

Understanding P-value and t-distribution

The P-value in a t-test measures the probability of observing a test statistic at least as extreme as the sample result, under the null hypothesis. We refer to a t-distribution table to find the P-value based on the degrees of freedom (df) and t-statistic (t). Different t-tests (upper-tailed, lower-tailed, two-tailed) require distinct interpretations of P-values.
02

a. Finding P-value for Upper-tailed Test, df = 8, t = 2.0

For an upper-tailed test with df = 8 and t = 2.0, consult the t-distribution table. The table often provides P-values for positive t-statistics. Look for the row corresponding to df = 8 and find the column range where t = 2.0 falls. For df = 8 and t = 2.0, the P-value is approximately 0.05. This level indicates the probability of observing a t-statistic of 2.0 or greater under the null hypothesis.
03

b. Finding P-value for Lower-tailed Test, df = 11, t = -2.4

For a lower-tailed test with df = 11 and t = -2.4, locate the P-value for t = 2.4 (ignoring the sign, as the table lists positive values). Use the symmetry of the t-distribution to find the P-value. For t = -2.4, df = 11, the P-value is approximately 0.02. This represents the probability of observing a t-statistic less than -2.4 under the null hypothesis.
04

c. Finding P-value for Two-tailed Test, df = 15, t = -1.6

In a two-tailed test, check the P-value for |t| = 1.6 with df = 15. Find the probability for one tail and multiply it by two to account for both tails. With df = 15 and |t| = 1.6, the one-tailed P-value is about 0.065, so the two-tailed P-value is approximately 0.13.
05

d. Finding P-value for Upper-tailed Test, df = 19, t = -0.4

For an upper-tailed test with a negative t-statistic (t = -0.4), the P-value is equivalent to 1 minus the cumulative probability of t = 0.4. With df = 19, the P-value is large (near 0.65 or more), implying that such a t-value is not extreme in the upper tail.
06

e. Estimating P-value for Upper-tailed Test, df = 5, t = 5.0

For an upper-tailed test with df = 5 and a large t-statistic of 5.0, the t-distribution table typically indicates that the P-value is very small, notably if t exceeds the values listed for common significance levels. Here, the P-value is less than 0.001, reflecting a very low probability for a t-statistic of 5 or higher.
07

f. Calculating P-value for Two-tailed Test, df = 40, t = -4.8

In a two-tailed context with df = 40 and a t-statistic of -4.8, find the P-value for |t| = 4.8, since tables provide positive values. The probability for one tail is less than 0.0001 given the large magnitude of t. Therefore, the two-tailed P-value is less than 0.0002, indicating a very small probability for observing such extremes under the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

T-distribution
The t-distribution is a key component in conducting a t-test. It resembles the standard normal distribution but has heavier tails, meaning it is more prone to producing values that fall further from the mean. This makes it especially useful when dealing with smaller sample sizes or unknown population variance.
The shape of the t-distribution depends on the degrees of freedom (df). As the degrees of freedom increase, the t-distribution approaches a normal distribution. When performing a t-test, the t-distribution helps in calculating the probability of obtaining a t-statistic for a given sample under the null hypothesis.
Degrees of Freedom
Degrees of freedom, often abbreviated as df, are crucial in statistical tests, as they are used to determine which t-distribution to reference. Basically, degrees of freedom often refer to the number of values in the final calculation of a statistic that are free to vary.
For example, in a t-test, the degrees of freedom usually equal the sample size minus one ( -1). This concept is essential because it influences the shape of the t-distribution, hence affecting the determination of P-values. A lower df indicates heavier tails, which emphasizes variability. Understanding how df impacts the distribution aids in accurately interpreting tests results.
Statistical Significance
Statistical significance is a determination made when the P-value of a test falls below a specified threshold, usually 0.05. It indicates that the observed results are unlikely to have occurred by chance under the null hypothesis.
When performing a t-test, achieving statistical significance suggests strong evidence against the null hypothesis, favoring the alternative hypothesis instead. However, it's important to remember that significance does not measure the size or importance of an effect, only the evidence against random chance.
  • P-value less than 0.05: Significant
  • P-value greater than 0.05: Not significant
Upper-tailed Test
An upper-tailed test is a type of hypothesis test where the region of rejection is located in the right tail of the probability distribution. It tests if a parameter is greater than the null hypothesis value.
In an upper-tailed t-test, one looks for evidence of a mean being greater than a specified value. This is done by calculating the P-value with reference to the right tail of the t-distribution and then comparing it against the significance level. A small P-value (typically less than 0.05) would indicate evidence against the null hypothesis in favor of the alternative, suggesting that the mean is probably greater than the hypothesized mean.
Two-tailed Test
A two-tailed test is used when we are interested in deviations in both directions away from the hypothesized parameter. It is useful when testing whether a sample mean differs from a known value, in either direction.
In a two-tailed t-test, we calculate the P-value for both the upper and lower tails of the t-distribution. Therefore, we often take the P-value for one tail and multiply it by two to consider both directions. A two-tailed test does not assume directionality and tests for the possibility of deviation without preference for higher or lower values. The conclusion will depend on whether your computed P-value is lower than your significance level, indicating evidence against the null hypothesis that the observed mean difference is due to random chance.

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Most popular questions from this chapter

A random sample of soil specimens was obtained, and the amount of organic matter \((\%)\) in the soil was determined for each specimen, resulting in the accompanying data (from "Engineering Properties of Soil," Soil Science, 1998: 93-102). $$ \begin{array}{llllllll} 1.10 & 5.09 & 0.97 & 1.59 & 4.60 & 0.32 & 0.55 & 1.45 \\ 0.14 & 4.47 & 1.20 & 3.50 & 5.02 & 4.67 & 5.22 & 2.69 \\ 3.98 & 3.17 & 3.03 & 2.21 & 0.69 & 4.47 & 3.31 & 1.17 \\ 0.76 & 1.17 & 1.57 & 2.62 & 1.66 & 2.05 & & \end{array} $$ The values of the sample mean, sample standard deviation, and (estimated) standard error of the mean are \(2.481,1.616\), and \(.295\), respectively. Does this data suggest that the true average percentage of organic matter in such soil is something other than \(3 \%\) ? Carry out a test of the appropriate hypotheses at significance level 10 by first determining the \(P\)-value. Would your conclusion be different if \(\alpha=.05\) had been used? [Note: A normal probability plot of the data shows an acceptable pattern in light of the reasonably large sample size.]

A sample of 12 radon detectors of a certain type was selected, and each was exposed to \(100 \mathrm{pCi} / \mathrm{L}\) of radon. The resulting readings were as follows: \(\begin{array}{rrrrrr}105.6 & 90.9 & 91.2 & 96.9 & 96.5 & 91.3 \\ 100.1 & 105.0 & 99.6 & 107.7 & 103.3 & 92.4\end{array}\) a. Does this data suggest that the population mean reading under these conditions differs from 100 ? State and test the appropriate hypotheses using \(\alpha=.05\). b. Suppose that prior to the experiment a value of \(\sigma=7.5\) had been assumed. How many determinations would then have been appropriate to obtain \(\beta=.10\) for the alternative \(\mu=95\) ?

For each of the following assertions, state whether it is a legitimate statistical hypothesis and why: a. \(H: \sigma>100\) b. \(H: \tilde{x}=45\) c. \(H: s \leq .20\) d. \(H: \sigma_{1} / \sigma_{2}<1\) e. \(H: \bar{X}-\bar{Y}=5\) f. \(H: \lambda \leq .01\), where \(\lambda\) is the parameter of an exponential distribution used to model component lifetime

To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil for a 2-year period. The maximum penetration (in mils) for each specimen is then measured, yielding a sample average penetration of \(\bar{x}=52.7\) and a sample standard deviation of \(s=4.8\). The conduits were manufactured with the specification that true average penetration be at most 50 mils. They will be used unless it can be demonstrated conclusively that the specification has not been met. What would you conclude?

The article "Heavy Drinking and Polydrug Use Among College Students" (J. of Drug Issues, 2008: 445-466) stated that 51 of the 462 college students in a sample had a lifetime abstinence from alcohol. Does this provide strong evidence for concluding that more than \(10 \%\) of the population sampled had completely abstained from alcohol use? Test the appropriate hypotheses using the \(P\)-value method. [Note: The article used more advanced statistical methods to study the use of various drugs among students characterized as light, moderate, and heavy drinkers.]

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