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A triathlon consisting of swimming, cycling, and running is one of the more strenuous amateur sporting events. The article "Cardiovascular and Thermal Response of Triathlon Performance" (Medicine and Science in Sports and Exercise, 1988: 385-389) reports on a research study involving nine male triathletes. Maximum heart rate (beats/min) was recorded during performance of each of the three events. For swimming, the sample mean and sample standard deviation were \(188.0\) and \(7.2\), respectively. Assuming that the heart-rate distribution is (approximately) normal, construct a \(98 \%\) CI for true mean heart rate of triathletes while swimming.

Short Answer

Expert verified
The 98% CI for the mean heart rate is 181.05 to 194.95 bpm.

Step by step solution

01

Identify the Known Values

We know that the sample mean \( \bar{x} \) is 188.0, the sample standard deviation \( s \) is 7.2, and the sample size \( n \) is 9. We are asked to construct a 98% confidence interval for the true mean heart rate while swimming.
02

Find the Critical Value

Since the sample size is small (\( n < 30 \)), we use the t-distribution. For a 98% confidence level and \( n - 1 = 8 \) degrees of freedom, we find the t-value (\( t^* \)) from the t-table. The critical value \( t^* \) is approximately 2.896.
03

Calculate the Standard Error

The standard error (SE) is calculated using the formula:\[ SE = \frac{s}{\sqrt{n}} \]Substituting the known values, we get:\[ SE = \frac{7.2}{\sqrt{9}} = 2.4 \]
04

Calculate the Margin of Error

The margin of error (ME) is determined using the formula:\[ ME = t^* \times SE \]Substituting the values, we have:\[ ME = 2.896 \times 2.4 = 6.9504 \]
05

Construct the Confidence Interval

The confidence interval (CI) is calculated as:\[ CI = \bar{x} \pm ME \]Substituting the values, we obtain:\[ CI = 188.0 \pm 6.9504 \]Thus, the interval is \( 181.0496 \) to \( 194.9504 \).
06

Interpret the Confidence Interval

We are 98% confident that the true mean heart rate of triathletes while swimming is between 181.05 and 194.95 beats per minute.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

t-distribution
When it comes to statistics, the t-distribution is essential, especially for small sample sizes. It resembles the normal distribution but with heavier tails. The t-distribution accounts for the increased variability expected in smaller samples. This property makes it suitable for estimating the mean of a population when the sample size is less than 30.

When constructing a confidence interval, if our sample size (n) is small, such as n=9 as in the exercise, the t-distribution becomes crucial. This is because we must rely on it to determine our critical value, denoted as \( t^* \). This value is required to calculate how far from our sample mean the true mean might lie. The degrees of freedom (-1) adjust the shape of the t-distribution to better fit our data.
  • In the exercise, the degrees of freedom is 8 (since there are 9 samples).
  • The critical value for a 98% confidence interval is approximately 2.896.
The heavier tails of the t-distribution allow for a higher probability of sample means at the extremes, making it a safety net for small samples with potential outliers.
sample mean
The sample mean, noted as \( \bar{x} \), is a fundamental concept. It represents the average value of a set of observations. In our exercise, the sample mean is 188.0 beats per minute, which was calculated from the heart rates of nine triathletes.

The sample mean gives us a point estimate of the population mean. It acts as the central point when constructing a confidence interval. While it's a reliable estimator in many scenarios, it only offers a single perspective of the dataset - hence the need for further statistical analysis.
  • The main role of the sample mean is to provide a central value around which measurements are made.
  • It forms the core of the confidence interval calculation, starting the process of estimating the true mean.
Calculating and understanding the sample mean is crucial because it represents the heart of most statistical evaluations and forecasts.
standard error
The standard error (SE) is a measure of the variability of the sample mean. It tells us how much dispersion we might expect in our sample means if we were to draw multiple samples from the population. In simpler terms, it's a way to quantify the precision of our sample mean as an estimate of the true population mean.

The formula for calculating the standard error is:\[ SE = \frac{s}{\sqrt{n}} \]Where \( s \) is the sample standard deviation, and \( n \) is the sample size. For the exercise given:
  • The sample standard deviation is 7.2, and the sample size is 9.
  • Therefore, the standard error is calculated as 2.4.
This small number indicates that our sample mean is relatively precise, giving us confidence in its ability to represent the true mean of heart rates.
Using the SE, we can also assess the reliability of the sample mean. A lower standard error suggests a more accurate reflection of the population mean, while a higher one indicates more variability and thus more uncertainty.
margin of error
The margin of error (ME) is a critical statistic in estimating the true population parameter. It tells us the range within which we expect our sample mean to vary when estimating the population mean. This range is determined through a confidence interval.

To find the margin of error, we use the formula:\[ ME = t^* \times SE \]Where \( t^* \) represents the critical value from the t-distribution, and SE is the standard error we've calculated. In the exercise, by substituting the values:
  • The critical value \( t^* \) is 2.896.
  • The standard error is 2.4.
The margin of error then calculates to 6.9504.

This value of the margin of error means that, at a 98% confidence level, the true mean heart rate could reasonably fall within 6.9504 beats of the observed sample mean. It's a quantitative way to express uncertainty and ensures that estimates account for potential variability in data.

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Most popular questions from this chapter

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