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In a sample of 1000 randomly selected consumers who had opportunities to send in a rebate claim form after purchasing a product, 250 of these people said they never did so ("Rebates: Get What You Deserve," Consumer Reports, May 2009: 7). Reasons cited for their behavior included too many steps in the process, amount too small, missed deadline, fear of being placed on a mailing list, lost receipt, and doubts about receiving the money. Calculate an upper confidence bound at the \(95 \%\) confidence level for the true proportion of such consumers who never apply for a rebate. Based on this bound, is there compelling evidence that the true proportion of such consumers is smaller than \(1 / 3\) ? Explain your reasoning.

Short Answer

Expert verified
Yes, the upper bound (0.2725) is less than \(1/3\).

Step by step solution

01

Identify the given information

In this exercise, we have a sample size of \( n = 1000 \) and the number of consumers who did not send in the rebate form is \( x = 250 \). We aim to find an upper confidence bound for the proportion \( p \) of all consumers who do not apply for a rebate.
02

Calculate the sample proportion

The sample proportion \( \hat{p} \) is calculated using the formula:\[ \hat{p} = \frac{x}{n} = \frac{250}{1000} = 0.25. \]
03

Determine the z-score for the confidence level

For a \(95\%\) confidence level, we use a standard normal distribution table to find the z-score. Since we want the upper bound, we find the z-score corresponding to \(0.95\), which is approximately \(z = 1.645\).
04

Calculate the standard error

The standard error (SE) of the sample proportion is given by:\[ \text{SE} = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} = \sqrt{\frac{0.25 \times 0.75}{1000}} \approx 0.0137. \]
05

Calculate the upper confidence bound

The upper confidence bound for the true proportion \( p \) is:\[ \hat{p} + z \times \text{SE} = 0.25 + 1.645 \times 0.0137 \approx 0.2725. \]
06

Compare the upper bound with \(\frac{1}{3}\)

We compare the upper bound, 0.2725, with \(\frac{1}{3} \approx 0.3333\). Since 0.2725 < 0.3333, there is compelling evidence that the true proportion of consumers who never apply for a rebate is smaller than \(\frac{1}{3}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sampling Distribution
Sampling distribution is a fundamental concept in statistics. It refers to the distribution of a statistic (like the sample proportion) across many samples drawn from the same population. Imagine you repeatedly sample groups of 1000 consumers and calculate the proportion who do not apply for a rebate in each group. Each sample would give you a slightly different proportion, and the collection of these proportions forms the sampling distribution.
This distribution helps us understand the variability of our sample proportion. It's key in making inferences about the true population proportion, as we use it to construct confidence intervals.
  • A sampling distribution is crucial for estimating parameters like proportion.
  • It accounts for the variation in samples and helps make statistical inferences.
Understanding this concept allows statisticians to generalize from a sample to a whole population.
Standard Error
The standard error (SE) measures the variability or dispersion of the sampling distribution of a statistic. It's essentially the standard deviation of the sampling distribution. In our case, the SE of the sample proportion provides insight into how much the sample proportion might fluctuate from the true population proportion.

For a sample proportion, the SE formula is: \[ \text{SE} = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} \]Where \( \hat{p} \) is the sample proportion, and \( n \) is the sample size.

This formula shows that as our sample size increases, the SE decreases, meaning our estimate of the population parameter becomes more precise.
  • Smaller SE indicates a more accurate estimate of the population proportion.
  • Larger samples lead to a smaller SE, indicating increased reliability.
The standard error helps assess the accuracy of sample estimates in relation to the population.
Proportion Estimation
Proportion estimation is about determining the proportion of a certain trait or characteristic in a population based on a sample. In our scenario, we want to estimate the proportion of all consumers who do not send in rebate forms.
Calculating the sample proportion is the first step. In our exercise, the number of consumers who did not send in forms is 250 out of 1000, giving us a sample proportion \( \hat{p} = 0.25 \).

To estimate the population proportion, we use this sample proportion to construct a confidence interval or bound.
  • Sample proportion provides a point estimate for the population proportion.
  • Confidence intervals give a range of plausible values for the population proportion.
Proportion estimation enables us to make educated guesses about the entire population from sample data.
Z-score Calculation
A z-score measures how many standard deviations an element is from the mean of the distribution. In confidence interval calculations, the z-score is used to determine the cutoff points for a specified confidence level in a standard normal distribution.

For a 95% confidence level, commonly used in statistical analysis, the z-score is approximately 1.645 when determining an upper bound. The choice of z-score directly influences the width of the confidence interval. The higher the confidence level, the larger the z-score, and thus the wider the interval.
  • Z-scores link the probability of a parameter lying within a specific range.
  • They are crucial for constructing confidence intervals, ensuring our estimates are reliable.
Understanding z-scores helps ensure accurate and meaningful statistical conclusions, such as proving whether a proportion is less than a specified value.

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