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A diagnostic test for a certain disease is applied to \(n\) individuals known to not have the disease. Let \(X=\) the number among the \(n\) test results that are positive (indicating presence of the disease, so \(X\) is the number of false positives) and \(p=\) the probability that a disease-free individual's test result is positive (i.e., \(p\) is the true proportion of test results from disease-free individuals that are positive). Assume that only \(X\) is available rather than the actual sequence of test results. a. Derive the maximum likelihood estimator of \(p\). If \(n=20\) and \(x=3\), what is the estimate? b. Is the estimator of part (a) unbiased? c. If \(n=20\) and \(x=3\), what is the mle of the probability \((1-p)^{5}\) that none of the next five tests done on diseasefree individuals are positive?

Short Answer

Expert verified
a. \(\hat{p} = 0.15\); b. Yes, it's unbiased; c. MLE of \((1-p)^5\) is 0.4437.

Step by step solution

01

Define the Likelihood Function

To find the maximum likelihood estimator (MLE), we start by expressing the likelihood function. The problem describes a binomial setting where the number of false positives \(X\) among \(n\) tests is given. The probability mass function for a binomial distribution is given by \(P(X=x) = \binom{n}{x} p^x (1-p)^{n-x}\). In this case, the likelihood function \(L(p)\) is:\[L(p) = \binom{n}{X} p^X (1-p)^{n-X}\] We use this likelihood function to find the MLE of \(p\).
02

Derive the Maximum Likelihood Estimator

To find the MLE, we take the natural logarithm of the likelihood function to obtain the log-likelihood:\[\ln L(p) = \ln \binom{n}{X} + X \ln p + (n-X) \ln(1-p)\]Next, differentiate this expression with respect to \(p\):\[\frac{d}{dp} (\ln L(p)) = \frac{X}{p} - \frac{n-X}{1-p}\]Set the derivative equal to zero and solve for \(p\):\[\frac{X}{p} = \frac{n-X}{1-p}\]Solving the equation above gives:\[p = \frac{X}{n}\] Thus, the maximum likelihood estimator for \(p\) is \(\hat{p} = \frac{x}{n}\).
03

Calculate the Estimate with Given Values

Given \(n = 20\) and \(x = 3\), substitute these values into the MLE formula to find the estimate of \(p\):\[\hat{p} = \frac{3}{20} = 0.15\]
04

Check If the Estimator is Unbiased

An estimator is unbiased if its expected value is equal to the true parameter value. For the MLE of \(p\), \(\hat{p} = \frac{X}{n}\), the expected value is:\[E(\hat{p}) = E\left(\frac{X}{n}\right) = \frac{1}{n}E(X)\]Since \(X\sim \, \text{Binomial}(n, p)\), \(E(X) = np\). So,\[E(\hat{p}) = \frac{np}{n} = p\]Thus, \(\hat{p}\) is an unbiased estimator of \(p\).
05

Calculate the MLE of (1-p)^5

With \(\hat{p} = 0.15\), the probability that none of the next five tests are positive is:\[(1-\hat{p})^5 = (0.85)^5\]Calculate the value:\[(0.85)^5 \approx 0.4437\] Therefore, the MLE for the probability that none of the next five tests are positive is approximately 0.4437.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Distribution
The binomial distribution is a fundamental concept in probability and statistics, frequently used to model situations with two possible outcomes. Think of it as flipping a coin a certain number of times and counting the number of heads.
In the context of our problem, we have a diagnostic test that can either result in a positive or negative outcome for people known not to have a disease. The binomial distribution becomes handy because each test is independent, with a fixed probability of yielding a positive result, denoted by the parameter \( p \).
  • First, we have \( n \) trials (in our example, the number of tests conducted, such as 20).
  • Each trial results in a success (positive test) with probability \( p \) and a failure (negative test) with probability \( 1-p \).
  • The number of successes (false positives) is represented by \( X \).
The probability of observing \( x \) successes (false positives) in \( n \) trials is given by the probability mass function:\[ P(X=x) = \binom{n}{x} p^x (1-p)^{n-x} \]where \( \binom{n}{x} \) is the binomial coefficient, calculated as \( \frac{n!}{x!(n-x)!} \). This expression captures the essence of the binomial setting in which each test outcome is influenced by the probability \( p \).
Unbiased Estimator
An unbiased estimator is a statistic used to estimate a parameter of a population. It is termed 'unbiased' if, on average, it hits the true parameter it's estimating.
In simpler terms, if you repeatedly calculated this estimator using different samples from the population, the average of these calculations would converge to the actual parameter value.
For our binomial example:
  • The maximum likelihood estimator (MLE) of \( p \) is \( \hat{p} = \frac{X}{n} \).
  • This representation uses the ratio of observed successes (false positives) to total trials (tests).
  • The expected value of \( \hat{p} \) is calculated as:\[ E(\hat{p}) = E\left(\frac{X}{n}\right) = \frac{1}{n}E(X) \]
  • Given that \( E(X) = np \) for a binomial distribution, it follows:\[ E(\hat{p}) = \frac{np}{n} = p \]
This shows that \( \hat{p} = \frac{X}{n} \) is unbiased, because its expected value equals the true parameter \( p \). This ensures that we aren't consistently overestimating or underestimating \( p \).
Probability Mass Function
The probability mass function (PMF) is a mathematical function that provides the probability of each possible value of a discrete random variable. It's a helpful tool for understanding and quantifying random processes involving distinct outcomes.
For the binomial distribution identified in this problem:
  • The PMF helps us to pinpoint the likelihood of getting exactly \( x \) false positives in \( n \) tests.
  • Expressed formulaically, the PMF of a binomial distribution is:\[ P(X=x) = \binom{n}{x} p^x (1-p)^{n-x} \]
  • This function includes:
    • \( \binom{n}{x} \): the number of ways to choose \( x \) successes out of \( n \) trials.
    • \( p^x \): the probability of realizing exactly \( x \) successes.
    • \( (1-p)^{n-x} \): the probability of \( n-x \) failures.
By using the PMF, one can calculate and understand the distribution of outcomes across different scenarios, such as the number of false positives when a test is applied to healthy individuals. This foundational understanding aids in estimating parameters accurately, such as using the PMF to determine the likelihood for observed data, as seen in our exercise.

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Most popular questions from this chapter

Each of \(n\) specimens is to be weighed twice on the same scale. Let \(X_{i}\) and \(Y_{i}\) denote the two observed weights for the \(i\) th specimen. Suppose \(X_{i}\) and \(Y_{i}\) are independent of one another, each normally distributed with mean value \(\mu_{i}\) (the true weight of specimen \(i\) ) and variance \(\sigma^{2}\). a. Show that the maximum likelihood estimator of \(\sigma^{2}\) is \(\hat{\sigma}^{2}=\sum\left(X_{i}-Y_{i}\right)^{2} /(4 n)\). [Hint: If \(\bar{z}=\left(z_{1}+z_{2}\right) / 2\), then \(\left.\Sigma\left(z_{i}-\bar{z}\right)^{2}=\left(z_{1}-z_{2}\right)^{2} / 2 .\right]\) b. Is the mle \(\hat{\sigma}^{2}\) an unbiased estimator of \(\sigma^{2}\) ? Find an unbiased estimator of \(\sigma^{2}\).

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Let \(X_{1}, X_{2}, \ldots, X_{n}\) be a random sample from a pdf \(f(x)\) that is symmetric about \(\mu\), so that \(\widetilde{X}\) is an unbiased estimator of \(\mu\). If \(n\) is large, it can be shown that \(V(\widetilde{X}) \approx 1 /\left(4 n[f(\mu)]^{2}\right)\). a. Compare \(V(\widetilde{X})\) to \(V(\bar{X})\) when the underlying distribution is normal. b. When the underlying pdf is Cauchy (see Example 6.7), \(V(\bar{X})=\infty\), so \(\bar{X}\) is a terrible estimator. What is \(V(\widetilde{X})\) in this case when \(n\) is large?

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a. A random sample of 10 houses in a particular area, each of which is heated with natural gas, is selected and the amount of gas (therms) used during the month of January is determined for each house. The resulting observations are \(103,156,118,89,125,147,122,109,138,99\). Let \(\mu\) denote the average gas usage during January by all houses in this area. Compute a point estimate of \(\mu\). b. Suppose there are 10,000 houses in this area that use natural gas for heating. Let \(\tau\) denote the total amount of gas used by all of these houses during January. Estimate \(\tau\) using the data of part (a). What estimator did you use in computing your estimate? c. Use the data in part (a) to estimate \(p\), the proportion of all houses that used at least 100 therms. d. Give a point estimate of the population median usage (the middle value in the population of all houses) based on the sample of part (a). What estimator did you use?

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