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It is known that \(80 \%\) of all brand A zip drives work in a satisfactory manner throughout the warranty period (are "successes"). Suppose that \(n=10\) drives are randomly selected. Let \(X=\) the number of successes in the sample. The statistic \(X / n\) is the sample proportion (fraction) of successes. Obtain the sampling distribution of this statistic. [Hint: One possible value of \(X / n\) is \(.3\), corresponding to \(X=3\). What is the probability of this value (what kind of random variable is \(X\) )?]

Short Answer

Expert verified
The sampling distribution of \(X/n\) is based on a binomial distribution with parameters \(n = 10, p = 0.8\), yielding values from 0 to 1.

Step by step solution

01

Identify the Random Variable

In this problem, the random variable is \(X\), which represents the number of successes out of \(n = 10\) trials. Each trial is a brand A zip drive working successfully throughout the warranty period.
02

Recall the Binomial Distribution

Since each zip drive has an 80% chance of being successful (working throughout the warranty period), \(X\) follows a binomial distribution with parameters \(n = 10\) and \(p = 0.8\). The probability mass function for a binomial random variable is given by: \( P(X = k) = \binom{n}{k}p^k(1-p)^{n-k} \), where \(k\) is the number of successes.
03

Define the Sample Proportion

The sample proportion of successes is given by \(\frac{X}{n}\). The possible values of \(X\) range from 0 to 10, so the possible values of \(X/n\) range from 0 to 1, in increments of 0.1.
04

Determine the Probability of Each Proportion

For each possible value of \(X\), calculate \(\frac{X}{n}\) and the corresponding probability \(P(X = k)\) using the binomial probability formula. For instance, if \(X = 3\), then \(P(X = 3) = \binom{10}{3} (0.8)^3 (0.2)^{7}\). Repeat for all \(k = 0, 1, 2, \ldots, 10\).
05

Construct the Sampling Distribution

The sampling distribution of \(\frac{X}{n}\) consists of the possible values \(0, 0.1, 0.2, \ldots, 1\) and their respective probabilities calculated in the previous step. This distribution shows how likely each sample proportion value is when selecting 10 drives randomly.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sampling Distribution
The concept of a **sampling distribution** is fundamental in statistics and it represents the probability distribution of a given statistic based on a random sample. When we talk about the sampling distribution of the sample proportion \(X/n\), it means we want to examine how the sample proportion varies when we select many different random samples from the population.
In the given problem, we're interested in the sample proportion of "successful" zip drives in samples of size \(n=10\). Since each zip drive has an 80% chance of being successful, the sampling distribution tells us the probabilities of obtaining different sample proportions like 0.3, 0.4, etc.
By determining these probabilities, we can understand which sample proportions are more or less likely. This is especially useful for predicting outcomes and making informed decisions based on sample data. It is crucial to compute this distribution correctly to ensure that statistical inferences drawn from the sample are accurate.
The possible sample proportions in this problem range from 0 to 1, increasing in increments of 0.1 (e.g., 0, 0.1, 0.2, ... 1.0). For each of these proportions, there's an associated probability that reflects how frequently that proportion appears in a sampling of 10 drives.
Sample Proportion
The **sample proportion** is a vital metric used in statistics to represent the fraction of each category of interest within a sample. In this scenario, the sample proportion is denoted as \(X/n\), where \(X\) indicates the number of successful zip drives within a sample of size \(n=10\).
This proportion essentially converts counts (e.g., number of successes) into a comparative fraction of the whole. So, if 3 out of 10 zip drives are successful, \(3/10 = 0.3\), meaning that 30% of the sample is "successful." Recognizing this distinction between counts and proportions is key to evaluating how typical or atypical a particular sample result is.
Sample proportion is instrumental in probabilities and allows statisticians to make generalized conclusions about the larger population from which the sample was taken. Generally, the sample proportion \(\hat{p}\) provides an estimate of the true population proportion \(p\). It can fluctuate with different samples but on average, as the sample size increases, it tends to be a closer representation of the population proportion.
Binomial Random Variable
A **binomial random variable** applies well to scenarios where there are only two outcomes for a given experiment, such as success or failure. In our given problem, the random variable \(X\) denotes the number of successes (working zip drives) in the 10-trial sample.
When a random process follows a "binomial distribution," it means each trial is independent and has a constant probability of producing a success. This fits our scenario perfectly, as each drive has an initial 80% chance of success, independent of the outcomes of other drives. Hence, \(X\) is modeled as a binomial random variable with parameters \(n = 10\) and \(p = 0.8\).
The probability mass function for such a variable gives us the likelihood of obtaining exactly \(k\) successes out of \(n\) trials. It is given by: \[P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}\]Where \(\binom{n}{k}\) represents the binomial coefficient, and \(k\) is any integer from 0 to \(n\). In practice, identifying the Binomial Random Variable helps understand the variability and predictability of the outcomes in repeated trials, such as assessing several batches of zip drives.

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Most popular questions from this chapter

Two components of a minicomputer have the following joint pdf for their useful lifetimes \(X\) and \(Y\) : $$ f(x, y)=\left\\{\begin{array}{cc} x e^{-x(1+y)} & x \geq 0 \text { and } y \geq 0 \\ 0 & \text { otherwise } \end{array}\right. $$ a. What is the probability that the lifetime \(X\) of the first component exceeds 3 ? b. What are the marginal pdf's of \(X\) and \(Y\) ? Are the two lifetimes independent? Explain. c. What is the probability that the lifetime of at least one component exceeds 3 ?

Five automobiles of the same type are to be driven on a 300 mile trip. The first two will use an economy brand of gasoline, and the other three will use a name brand. Let \(X_{1}, X_{2}\), \(X_{3}, X_{4}\), and \(X_{3}\) be the observed fuel efficiencies (mpg) for the five cars. Suppose these variables are independent and normally distributed with \(\mu_{1}=\mu_{2}=20, \mu_{3}=\mu_{4}=\mu_{5}=21\), and \(\sigma^{2}=4\) for the economy brand and \(3.5\) for the name brand. Define an rv \(Y\) by $$ Y=\frac{X_{1}+X_{2}}{2}-\frac{X_{3}+X_{4}+X_{5}}{3} $$ so that \(Y\) is a measure of the difference in efficiency between economy gas and name-brand gas. Compute \(P(0 \leq Y)\) and \(P(-1 \leq Y \leq 1)\). [Hint: \(Y=a_{1} X_{1}+\ldots+a_{5} X_{5}\), with \(\left.a_{1}=\frac{1}{2}, \ldots, a_{5}=-\frac{1}{3} .\right]\)

Carry out a simulation experiment using a statistical computer package or other software to study the sampling distribution of \(\bar{X}\) when the population distribution is lognormal with \(E(\ln (X))=3\) and \(V(\ln (X))=1\). Consider the four sample sizes \(n=10,20,30\), and 50 , and in each case use 1000 replications. For which of these sample sizes does the \(\bar{X}\) sampling distribution appear to be approximately normal?

A service station has both self-service and full-service islands. On each island, there is a single regular unleaded pump with two hoses. Let \(X\) denote the number of hoses being used on the self-service island at a particular time, and let \(Y\) denote the number of hoses on the full-service island in use at that time. The joint pmf of \(X\) and \(Y\) appears in the accompanying tabulation. \begin{tabular}{ll|ccc} \(p(x, y)\) & & 0 & 1 & 2 \\ \hline & 0 & \(.10\) & 04 & \(.02\) \\ \(x\) & 1 & \(.08\) & \(.20\) & \(.06\) \\ & 2 & \(.06\) & \(.14\) & \(.30\) \end{tabular} a. What is \(P(X=1\) and \(Y=1)\) ? b. Compute \(P(X \leq 1\) and \(Y \leq 1)\). c. Give a word description of the event \(\\{X \neq 0\) and \(Y \neq 0\\}\), and compute the probability of this event. d. Compute the marginal pmf of \(X\) and of \(Y\). Using \(p_{X}(x)\), what is \(P(X \leq 1)\) ? e. Are \(X\) and \(Y\) independent rv's? Explain.

Consider a random sample of size \(n\) from a continuous distribution having median 0 so that the probability of any one observation being positive is \(.5\). Disregarding the signs of the observations, rank them from smallest to largest in absolute value, and let \(W=\) the sum of the ranks of the observations having positive signs. For example, if the observations are \(-.3,+.7,+2.1\), and \(-2.5\), then the ranks of positive observations are 2 and 3 , so \(W=5\). In Chapter \(15, W\) will be called Wilcoxon's signed-rank statistic. \(W\) can be represented as follows: where the \(Y_{i}\) 's are independent Bernoulli rv's, each with \(p=.5\left(Y_{l}=1\right.\) corresponds to the observation with rank \(i\) being positive). a. Determine \(E\left(Y_{i}\right)\) and then \(E(W)\) using the equation for \(W\). [Hint: The first \(n\) positive integers sum to \(n(n+1) / 2\).] b. Determine \(V\left(Y_{j}\right)\) and then \(V(W)\). [Hint: The sum of the squares of the first \(n\) positive integers can be expressed as \(n(n+1)(2 n+1) / 6 .]\)

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