/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 An instructor has given a short ... [FREE SOLUTION] | 91Ó°ÊÓ

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An instructor has given a short quiz consisting of two parts. For a randomly selected student, let \(X=\) the number of points earned on the first part and \(Y=\) the number of points earned on the second part. Suppose that the joint pmf of \(X\) and \(Y\) is given in the accompanying table. \begin{tabular}{lr|rrrr} \(p(x, y)\) & & 0 & 5 & 10 & 15 \\ \hline & 0 & \(.02\) & \(.06\) & \(.02\) & \(.10\) \\ \(x\) & 5 & \(.04\) & \(.15\) & \(.20\) & \(.10\) \\ & 10 & \(.01\) & \(.15\) & \(.14\) & \(.01\) \end{tabular} a. If the score recorded in the grade book is the total number of points earned on the two parts, what is the expected recorded score \(E(X+Y)\) ? b. If the maximum of the two scores is recorded, what is the expected recorded score?

Short Answer

Expert verified
a) The expected score when recorded in total is 14.9; b) The expected score for the max is 9.7.

Step by step solution

01

Understand Expected Value

The expected value of a random variable is the sum of all possible values, each multiplied by their respective probabilities. In this case, we need to find the expected value for the total score, which is represented by the sum of two variables, \(X\) and \(Y\).
02

Calculate Sum Variable

The variable \(T = X + Y\) represents the total score. We need to compute the probability mass for each possible value of \(T\) by adding the joint probabilities for combinations that result in the same total score.
03

Compute Joint Probability of Each Total Score

Calculate the probability for each possible value of \(T\):- \(T = 0\): \(P(T=0) = P(X=0, Y=0) = 0.02\)- \(T = 5\): \(P(T=5) = P(X=0, Y=5) + P(X=5, Y=0) = 0.06 + 0.04 = 0.10\)- \(T = 10\): \(P(T=10) = P(X=0, Y=10) + P(X=5, Y=5) + P(X=10, Y=0) = 0.02 + 0.15 + 0.01 = 0.18\)- \(T = 15\): \(P(T=15) = P(X=0, Y=15) + P(X=5, Y=10) + P(X=10, Y=5) = 0.10 + 0.20 + 0.15 = 0.45\)- \(T = 20\): \(P(T=20) = P(X=5, Y=15) + P(X=10, Y=10) = 0.10 + 0.14 = 0.24\)- \(T = 25\): \(P(T=25) = P(X=10, Y=15) = 0.01\)
04

Calculate Expected Value of T

Using the probabilities calculated, we can determine \(E(T) = \sum (t \times P(T=t))\):\[E(T) = (0 \times 0.02) + (5 \times 0.10) + (10 \times 0.18) + (15 \times 0.45) + (20 \times 0.24) + (25 \times 0.01) = 14.9\]
05

Calculate Maximum Score Probabilities

Now compute the probabilities for the maximum score between \(X\) and \(Y\) by considering the greatest of the two values for each combination.Identify maximum values \(Z = \max(X, Y)\) for each \( (x, y) \) combination and calculate respective probabilities.
06

Expected Value of Maximum Score

Compute the expected value of \(Z = \max(X, Y)\) by considering the probabilities of obtaining each maximum score:\(E(Z) = \sum (z \times P(Z=z))\), after finding probabilities for each possible maximum score.
07

Probabilities for Maximum Score

Consider all combinations for \(Z\):- \(Z = 0\): \(P(Z=0) = P(X=0, Y=0) = 0.02\)- \(Z = 5\): \(P(Z=5) = P(X=0, Y=5) + P(X=5, Y=0) + P(X=5, Y=5) = 0.06 + 0.04 + 0.15 = 0.25\)- \(Z = 10\): \(P(Z=10) = P(X=0, Y=10) + P(X=5, Y=10) + P(X=10, Y=0) + P(X=10, Y=5) + P(X=10, Y=10) = 0.02 + 0.20 + 0.01 + 0.15 + 0.14 = 0.52\)- \(Z = 15\): \(P(Z=15) = P(X=0, Y=15) + P(X=5, Y=15) + P(X=10, Y=15) = 0.10 + 0.10 + 0.01 = 0.21\)
08

Calculate Expected Maximum Value

Use the probabilities from Step 7 to calculate \(E(Z)\):\[E(Z) = (0 \times 0.02) + (5 \times 0.25) + (10 \times 0.52) + (15 \times 0.21) = 9.7\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expected Value
The expected value is a fundamental concept in probability and statistics. It represents the average or mean value that we would expect to obtain over a large number of trials. In mathematical terms, the expected value of a random variable is the sum of all possible values it can take, each multiplied by their probabilities. For example, if you are rolling a die, the expected value can be thought of as the average outcome you would get if you rolled the die an infinite number of times.
The formula for the expected value of a discrete random variable X, represented as \( E(X) \), is given by:
  • \( E(X) = \sum x_i \cdot P(X = x_i) \)
In this notation, \( x_i \) are the possible values of the random variable, and \( P(X = x_i) \) are their corresponding probabilities.
In the quiz problem you have seen, the expected value is used to determine the average total score (sum of scores from two parts) and the average maximum score (the highest score from the two parts). Understanding how to calculate and interpret expected values can provide insights into different statistical outcomes and help make informed predictions.
Random Variables
Random variables are quantities that can take on different values based on the outcome of some random phenomenon. These variables are generally denoted by capital letters like X, Y, or Z. For instance, in our quiz example, \( X \) and \( Y \) represent scores on two separate parts of the quiz, respectively.
There are two main types of random variables:
  • Discrete random variables: These can take on a countable number of distinct values. The scores in our quiz example are discrete since a student can only score certain fixed point values.
  • Continuous random variables: These can take on any value within a given range, such as the height of students in a class.
Understanding random variables and how they operate is crucial for solving problems in probability and statistics. They serve as the foundation for more complex concepts like probability distributions and expected values.
Probability Mass Function
The probability mass function (pmf) is a function that provides the probabilities of a discrete random variable taking on certain values. It essentially gives us the probability distribution for a discrete random variable. The pmf is crucial because it tells us how the probabilities are distributed across different outcomes.
For a random variable \( X \) with a pmf \( p(x) \), the following conditions hold:
  • \( p(x) \geq 0 \) for all possible values \( x \)
  • \( \sum p(x) = 1 \)
In the exercise, the joint probability mass function of \( X \) and \( Y \) is given in a table. Each entry in the table represents \( p(x, y) \), the joint probability that \( X \) and \( Y \) take on values \( x \) and \( y \), respectively.
By examining these probabilities, we can compute important statistics like total scores and expected values, which provide deeper insights into the behavior of the random variables.
Maximum Score
The maximum score in any scenario involves finding the largest value possible from a set of numbers. In the context of the quiz problem, when comparing scores from two parts, the maximum score refers to the highest score achieved between the two parts for any given student.
To calculate the expected maximum score, we need to first identify all maximum scores from the joint probabilities of \( X \) and \( Y \). For each potential outcome of the quiz, determine which score is higher and assign this as the maximum score, \( Z = \max(X, Y) \).
Once you have these maximum values along with their associated probabilities, you apply the expected value formula:
  • \( E(Z) = \sum z_i \cdot P(Z = z_i) \)
This process yields the expected maximum score, providing an average measure of the highest scores students are likely to achieve over multiple quizzes.
Total Score
The total score is a straightforward yet significant concept, especially in evaluating combined assessments. For any combined tasks or quizzes, the total score is simply the sum of the individual scores from each task.
In the example exercise, the total score \( T = X + Y \) represents the sum of the scores from the two parts of the quiz. Each combination of \( X \) and \( Y \) results in a different possible total score.
To find the expected total score, you need to determine the probability of each possible total score outcome, \( P(T = t) \), by summing the joint probabilities for all \( (x, y) \) combinations that result in the same total \( t \).
Then apply the expected value formula:
  • \( E(T) = \sum t \cdot P(T = t) \)
This calculation will provide you with the average total score, reflecting the average number of points students are likely to earn across both parts of the quiz. This value is instrumental for instructors to gauge overall performance in a balanced way.

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Most popular questions from this chapter

Carry out a simulation experiment using a statistical computer package or other software to study the sampling distribution of \(\bar{X}\) when the population distribution is lognormal with \(E(\ln (X))=3\) and \(V(\ln (X))=1\). Consider the four sample sizes \(n=10,20,30\), and 50 , and in each case use 1000 replications. For which of these sample sizes does the \(\bar{X}\) sampling distribution appear to be approximately normal?

A binary communication channel transmits a sequence of "bits" ( 0 s and 1s). Suppose that for any particular bit transmitted, there is a \(10 \%\) chance of a transmission error (a 0 becoming a 1 or a 1 becoming a 0 ). Assume that bit errors occur independently of one another. a. Consider transmitting 1000 bits. What is the approximate probability that at most 125 transmission errors occur? b. Suppose the same 1000 -bit message is sent two different times independently of one another. What is the approximate probability that the number of errors in the first transmission is within 50 of the number of errors in the second?

a. Use the rules of expected value to show that \(\operatorname{Cov}(a X+\) \(b, c Y+d)=a c \operatorname{Cov}(X, Y)\). b. Use part (a) along with the rules of variance and standard deviation to show that \(\operatorname{Corr}(a X+b, c Y+d)=\operatorname{Corr}(X\), \(Y\) ) when \(a\) and \(c\) have the same sign. c. What happens if \(a\) and \(c\) have opposite signs?

Three different roads feed into a particular freeway entrance. Suppose that during a fixed time period, the number of cars coming from each road onto the freeway is a random variable, with expected value and standard deviation as given in the table. a. What is the expected total number of cars entering the freeway at this point during the period? [Hint: Let \(X_{b}=\) the number from road i.] b. What is the variance of the total number of entering cars? Have you made any assumptions about the relationship between the numbers of cars on the different roads? c. With \(X_{l}\) denoting the number of cars entering from road \(i\) during the period, suppose that \(\operatorname{Cov}\left(X_{1}, X_{2}\right)=80\), \(\operatorname{Cov}\left(X_{1}, X_{3}\right)=90\), and \(\operatorname{Cov}\left(X_{2}, X_{3}\right)=100\) (so that the three streams of traffic are not independent). Compute the expected total number of entering cars and the standard deviation of the total.

Five automobiles of the same type are to be driven on a 300 mile trip. The first two will use an economy brand of gasoline, and the other three will use a name brand. Let \(X_{1}, X_{2}\), \(X_{3}, X_{4}\), and \(X_{3}\) be the observed fuel efficiencies (mpg) for the five cars. Suppose these variables are independent and normally distributed with \(\mu_{1}=\mu_{2}=20, \mu_{3}=\mu_{4}=\mu_{5}=21\), and \(\sigma^{2}=4\) for the economy brand and \(3.5\) for the name brand. Define an rv \(Y\) by $$ Y=\frac{X_{1}+X_{2}}{2}-\frac{X_{3}+X_{4}+X_{5}}{3} $$ so that \(Y\) is a measure of the difference in efficiency between economy gas and name-brand gas. Compute \(P(0 \leq Y)\) and \(P(-1 \leq Y \leq 1)\). [Hint: \(Y=a_{1} X_{1}+\ldots+a_{5} X_{5}\), with \(\left.a_{1}=\frac{1}{2}, \ldots, a_{5}=-\frac{1}{3} .\right]\)

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