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A company that produces fine crystal knows from experience that \(10 \%\) of its goblets have cosmetic flaws and must be classified as "seconds." a. Among six randomly selected goblets, how likely is it that only one is a second? b. Among six randomly selected goblets, what is the probability that at least two are seconds? c. If goblets are examined one by one, what is the probability that at most five must be selected to find four that are not seconds?

Short Answer

Expert verified
a) 0.3543, b) 0.1143, c) 0.91854

Step by step solution

01

Identify the Problem Variables

We are dealing with a binomial distribution problem where each goblet tested is independent, and the probability of it being a second (having a flaw) is 0.10. For the first part of the question, we need to find the probability that 1 goblet out of 6 is a second. Here, \( n=6 \) and \( p=0.10 \).
02

Calculate the Probability for Part a

Use the binomial probability formula: \( P(X=k) = \binom{n}{k} p^k (1-p)^{n-k} \). For this problem, \( n=6 \), \( k=1 \), \( p=0.10 \). - \( \binom{6}{1} \) is the number of ways to choose 1 flawed goblet.\[ P(X=1) = \binom{6}{1} (0.10)^1 (0.90)^{5} \approx 0.3543 \]
03

Solve Part b - At Least Two are Seconds

Calculate \( P(X \geq 2) \). Instead of directly calculating for \( X \geq 2 \), calculate the complement \( P(X < 2) = P(X=0) + P(X=1) \) and subtract from 1:- \( P(X=0) = \binom{6}{0} (0.10)^0 (0.90)^6 \approx 0.5314 \)- \( P(X=1) = 0.3543 \) (from Step 2)- \( P(X \geq 2) = 1 - (0.5314 + 0.3543) = 1 - 0.8857 = 0.1143 \)
04

Solve Part c - Probability for at Most Five to Select Four Non-Seconds

We look for the probability of finding 4 non-seconds among the first 5 goblets. We are interested in at most 1 being a second in 5 trials:- Find \( P(X=0) \) and \( P(X=1) \) for \( n=5 \), where \( p=0.10 \):- \( P(X=0) = \binom{5}{0} (0.10)^0 (0.90)^5 = 0.59049 \)- \( P(X=1) = \binom{5}{1} (0.10)^1 (0.90)^4 = 0.32805 \)- Therefore, the total probability is \( P(X \leq 1) = 0.59049 + 0.32805 = 0.91854 \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is a branch of mathematics that deals with the analysis and interpretation of random phenomena. In this exercise, we delve into the concept of binomial distribution, which is a fundamental part of probability theory. The scenario involves six goblets, each independently having a 10% chance of being flawed.
A binomial distribution is used when there are a fixed number of independent trials, each with two possible outcomes: success (a goblet is a second) or failure (a goblet is not). This distribution helps calculate the probabilities of obtaining a specific number of successes in those trials.
To find these probabilities, we use the binomial probability formula:
  • \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]
Where \( n \) is the number of trials, \( \binom{n}{k} \) is a binomial coefficient, \( p \) is the probability of success on a single trial, and \( k \) is the number of successes.
Understanding this theory is crucial as it underlies many practical applications in real-world scenarios where you need to predict the likelihood of a specific number of outcomes.
Statistics Problems
Statistics problems can help us make sense of data and random events through structured analysis. In this exercise, you are introduced to realistic scenarios where you must predict outcomes based on given probabilities. The goblet problem is a typical example in which real-world data is modeled using statistical methods.
In the given problem, we used a set of common statistical tasks:
  • Calculating the probability that a specific number of goblets have flaws.
  • Determining the likelihood of events involving multiple goblets.
  • Using complement rules to simplify calculations (like finding 'at least two' by subtracting from 1).
Such problems rely on your understanding of statistical tools, which enable you to form hypotheses and test them efficiently. Recognizing the importance of assumptions like independence and fixed trial numbers can significantly enhance your problem-solving skillset in statistics.
Step-by-Step Solutions
Step-by-step solutions are invaluable for solving statistics problems, especially when dealing with complex calculations like the binomial distribution. By breaking down the problem into manageable steps, you can methodically work through each part until you reach a solution.
Here's a simple approach used in the goblet problem:
  • **Identify Variables:** Determine all known values (e.g., \( n \) and \( p \)) and what you need to find.
  • **Apply Formulas:** Use the binomial probability formula by plugging in the values.
  • **Derive Results:** Perform the necessary arithmetic operations to find probabilities.
In our solution:- For part a, we calculated the probability of exactly one flawed goblet.
- In part b, calculating probabilities for '\( X \)' less than 2 and subtracting from 1 provided the complement technique.
- Part c involved adding probabilities for up to one flawed goblet among the first five.
This sequential approach not only aids in understanding but also ensures you do not overlook any crucial steps in the problem-solving process. As you practice more, these steps will become intuitive, enhancing your ability to tackle a variety of statistical problems.

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Most popular questions from this chapter

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