/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 95 Individual A has a circle of fiv... [FREE SOLUTION] | 91Ó°ÊÓ

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Individual A has a circle of five close friends (B, C, D, E, and F). A has heard a certain rumor from outside the circle and has invited the five friends to a party to circulate the rumor. To begin, A selects one of the five at random and tells the rumor to the chosen individual. That individual then selects at random one of the four remaining individuals and repeats the rumor. Continuing, a new individual is selected from those not already having heard the rumor by the individual who has just heard it, until everyone has been told. a. What is the probability that the rumor is repeated in the order \(\mathrm{B}, \mathrm{C}, \mathrm{D}, \mathrm{E}\), and \(\mathrm{F}\) ? b. What is the probability that \(\mathrm{F}\) is the third person at the party to be told the rumor? c. What is the probability that \(\mathrm{F}\) is the last person to hear the rumor? d. If at each stage the person who currently "has" the rumor does not know who has already heard it and selects the next recipient at random from all five possible individuals, what is the probability that \(\mathrm{F}\) has still not heard the rumor after it has been told ten times at the party?

Short Answer

Expert verified
(a) \(\frac{1}{120}\); (b) \(\frac{1}{10}\); (c) \(\frac{1}{60}\); (d) \(0.107\).

Step by step solution

01

Understanding the Problem Conditions

The rumor starts with individual A and is told to one out of five friends (B, C, D, E, F). Each person who hears the rumor then tells it to one of the remaining friends who have not heard it yet. Thus, each choice is independent and random among those who haven't heard the rumor.
02

Calculating Probability for Part (a)

We want the rumor to be told in the order of B, C, D, E, and then F. Initially, A selects one of the five friends; thus, the probability of picking B is \( \frac{1}{5} \). Next, B chooses C out of the four who haven't heard the rumor, with probability \( \frac{1}{4} \). C chooses D out of the three, with probability \( \frac{1}{3} \). D chooses E out of the two, with probability \( \frac{1}{2} \). Then E finally chooses F. Multiplying these probabilities gives the total probability.\[ \frac{1}{5} \times \frac{1}{4} \times \frac{1}{3} \times \frac{1}{2} \times 1 = \frac{1}{120}.\]
03

Calculating Probability for Part (b)

To find the probability that F is third to hear the rumor, F must be chosen after two others. First person selected can be any of 5, second from 4, and F must be selected third from the 3 people left. Thus, the probability depends on this third choice:\[ \frac{2}{5} \times \frac{1}{4} = \frac{1}{10}.\]
04

Calculating Probability for Part (c)

To determine the probability that F is last to hear the rumor, F must be chosen from the last 2 remaining people. The sequence before does not matter as long as F is told last:\[ \frac{1}{5} \times \frac{1}{4} \times \frac{1}{3} \times \frac{1}{2} = \frac{1}{60}.\]
05

Computing Iterative Probability for Part (d)

Considering each person telling the rumor does not remember or know of previous recipients; if the rumor is told 10 times, we analyze if F has not heard it. F must not be chosen in the initial selections at any of these stages, the probability follows a geometric distribution where the number of times F isn't selected increases exponentially small as we recount the total distribution:\[ \left(\frac{4}{5}\right)^{10} \approx 0.107.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Selection
Random selection is a fundamental principle in probability theory where each member of a set has an equal chance of being chosen. In the context of this exercise, random selection is applied each time a friend tells the rumor to another. This ensures that any individual who hasn't heard the rumor before has the same probability of hearing it next.
This concept is important because it determines the likelihood of each potential outcome. For example, when individual A initially selects one of the five friends, each friend (B, C, D, E, F) has a \( \frac{1}{5} \) chance of being told the rumor first. It's this principle of fairness and unpredictability that keeps each selection independent of past choices, as each selection does not affect the next.
  • Every choice is independent.
  • Each person who hasn't heard the rumor yet is equally likely to be chosen.
  • Probabilities remain constant with each new selection.
Independent Events
In probability theory, independent events are those whose outcomes do not affect each other. When one event occurs, it does not influence the likelihood of another event.
For this exercise, each time the rumor is passed on, the process of selection is independent of previous selections. This continues until all individuals have heard the rumor. The action of one friend telling the rumor doesn't influence the preference of the next choice.
Because each selection is independent:
  • The probability remains unaffected by prior selections.
  • Previous events do not alter the pool of choices except by reducing the number of unselected individuals.
  • Calculations rely on consistent probabilities given remaining options.
These principles simplify complex probability problems by allowing a breakdown into simple sequential steps.
Geometric Distribution
Geometric distribution describes the number of trials needed to achieve the first success in a sequence of independent Bernoulli trials. It is applicable to scenarios where we repeat an experiment until a success occurs.
In the context of the rumor, as in part (d) of the problem, we consider how many times a friend can hear the rumor before F finally hears it. If we define "success" as F finally hearing the rumor, then the probability that F still hasn't heard the rumor after 10 announcements follows a geometric distribution.
The formula for this scenario is \( \left(\frac{4}{5}\right)^{10} \), reflecting the outcome where F is not chosen "successfully" after many repetitions. The geometric distribution helps calculate the declining probability as the number of trials increases, showing how unlikely it is for F to remain unnoticed over several turns.
Combinatorial Probability
Combinatorial probability combines basic counting principles with probability to study outcomes based on permutations and combinations.
In this problem, especially for parts (a) and (c), combinatorial probability is employed to calculate specific orderings and arrangements. To find the probability for sequence B, C, D, E, and then F, we apply combinatorial reasoning. The probability of receiving the rumor follows a series of decisions, each influenced by the reduced number of yet-to-hear friends.
Using simple permutations:
  • The choice of each subsequent friend depends on how many are left.
  • We multiply probabilities reflecting these decreasing choices.
  • Calculations consider only the sequence without repetition or influence by previous choices.
This type of probability calculation is crucial for understanding how different arrangements and sequences lead to different outcomes.

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Most popular questions from this chapter

A personnel manager is to interview four candidates for a job. These are ranked \(1,2,3\), and 4 in order of preference and will be interviewed in random order. However, at the conclusion of each interview, the manager will know only how the current candidate compares to those previously interviewed. For example, the interview order \(3,4,1,2\) generates no information after the first interview, shows that the second candidate is worse than the first, and that the third is better than the first two. However, the order 3 , \(4,2,1\) would generate the same information after each of the first three interviews. The manager wants to hire the best candidate but must make an irrevocable hire/no hire decision after each interview. Consider the following strategy: Automatically reject the first \(s\) candidates and then hire the first subsequent candidate who is best among those already interviewed (if no such candidate appears, the last one interviewed is hired). For example, with \(s=2\), the order \(3,4,1,2\) would result in the best being hired, whereas the order \(3,1,2,4\) would not. Of the four possible \(s\) values \((0,1,2\), and 3\()\), which one maximizes \(P\) (best is hired)?

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