/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 A certain shop repairs both audi... [FREE SOLUTION] | 91Ó°ÊÓ

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A certain shop repairs both audio and video components. Let \(A\) denote the event that the next component brought in for repair is an audio component, and let \(B\) be the event that the next component is a compact disc player (so the event \(B\) is contained in \(A)\). Suppose that \(P(A)=.6\) and \(P(B)=.05\). What is \(P(B \mid A)\) ?

Short Answer

Expert verified
\(P(B \mid A) \approx 0.0833\)

Step by step solution

01

Identify the Given Information

The problem provides the probabilities of events: \(P(A) = 0.6\) and \(P(B) = 0.05\), where event \(B\) is contained within event \(A\). This means that all outcomes of \(B\) are also outcomes of \(A\).
02

Recall the Conditional Probability Formula

Conditional probability \(P(B \mid A)\) is calculated using the formula \[P(B \mid A) = \frac{P(A \cap B)}{P(A)}\]where \(P(A \cap B)\) represents the probability that both events \(A\) and \(B\) occur.
03

Determine the Probability of Intersection

Since event \(B\) is contained in event \(A\), the intersection \(A \cap B\) is simply event \(B\). So, \(P(A \cap B) = P(B) = 0.05\).
04

Apply the Conditional Probability Formula

Substitute the known values into the conditional probability formula:\[P(B \mid A) = \frac{0.05}{0.6}\] Calculate this value.
05

Perform the Calculation

Calculate \(P(B \mid A)\) by performing the division:\[P(B \mid A) = \frac{0.05}{0.6} \approx 0.0833\]Thus, the conditional probability is approximately 0.0833.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Intersection of Events
Understanding the concept of the intersection of events is key in probability. In probability theory, the **intersection of events** refers to situations where multiple events occur simultaneously. Let's consider an example from our exercise. If event \(A\) is that a repaired component is an audio component, and event \(B\) shows that the component is a compact disc player, the intersection \(A \cap B\) implies that the component is both an audio component and a compact disc player.
This idea is crucial because it helps us figure out combined probabilities. In our scenario, since every compact disc player (event \(B\)) is undoubtedly an audio component (event \(A\)), the probability of the intersection \(A \cap B\) is simply the probability of \(B\).
Thus, when someone talks about the intersection \(A \cap B\), they mean the simultaneous occurrence of \(A\) and \(B\). It simplifies the process of determining certain probabilities specially when one event is wholly contained within another.
Probability Formulas
Probability formulas are mathematical expressions used to describe and calculate probabilities of events. One of the most important formulas in probability theory is the **Conditional Probability Formula**. This formula allows us to calculate the probability of an event occurring, given that another event has already occurred.

It is written as:
  • \(P(B \mid A) = \frac{P(A \cap B)}{P(A)}\)
This formula states that the probability of \(B\) occurring given \(A\) has occurred is found by dividing the probability of both \(A\) and \(B\) occurring by the probability of \(A\).
In the exercise, we use this formula to find \(P(B \mid A)\), the chance that the repaired component is a compact disc player given that it is an audio component. By applying the proper probability formula, we can accurately determine probabilities in complex situations.
Calculation of Probabilities
Calculating probabilities often involves methodically breaking down the problem using known probabilities and mathematical expressions. In our context, we calculate the conditional probability \(P(B \mid A)\). This probability helps tell us the likelihood of one event when another is a given, which adds clarity to situational forecasts.

For this calculation, we use the intersection probability identified earlier as \(P(A \cap B) = 0.05\) and the given probability of an audio repair \(P(A) = 0.6\). By plugging these values into our conditional probability formula, we perform the division:
  • \(P(B \mid A) = \frac{0.05}{0.6}\)
After performing the math, we find:
  • \(P(B \mid A) \approx 0.0833\)
This calculation shows us that there is approximately an 8.33% chance that the next repaired audio component is specifically a compact disc player. Understanding these calculations improves our competence in analyzing probabilities and can be extended to a variety of similar problems.

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