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The accompanying data resulted from an experiment to compare the effects of vitamin \(C\) in orange juice and in synthetic ascorbic acid on the length of odontoblasts in guinea pigs over a 6-week period ("The Growth of the Odontoblasts of the Incisor Tooth as a Criterion of the Vitamin C Intake of the Guinea Pig," J. of Nutrition, 1947: 491-504). Use the Wilcoxon rank-sum test at level .01 to decide whether true average length differs for the two types of vitamin \(\mathrm{C}\) intake. Compute also an approximate \(P\)-value. $$ \begin{array}{lrrrrrr} \text { Orange Juice } & 8.2 & 9.4 & 9.6 & 9.7 & 10.0 & 14.5 \\ & 15.2 & 16.1 & 17.6 & 21.5 & & \\ \text { Ascorbic Acid } & 4.2 & 5.2 & 5.8 & 6.4 & 7.0 & 7.3 \\ & 10.1 & 11.2 & 11.3 & 11.5 & & \end{array} $$

Short Answer

Expert verified
Reject the null hypothesis based on the computed test statistic and critical value; the true average lengths likely differ.

Step by step solution

01

Combine and Rank Data

Combine the length measurements from orange juice and ascorbic acid into one data set: 8.2, 9.4, 9.6, 9.7, 10.0, 14.5, 15.2, 16.1, 17.6, 21.5 (orange juice) and 4.2, 5.2, 5.8, 6.4, 7.0, 7.3, 10.1, 11.2, 11.3, 11.5 (ascorbic acid). Next, rank the data from smallest to largest, assigning average ranks in case of ties.
02

Calculate Rank Sums

Determine the sum of the ranks for each group. Sum the ranks of the orange juice group and the ascorbic acid group separately to calculate their respective rank sums. Let's denote these sums by \(R_1\) for orange juice and \(R_2\) for ascorbic acid.
03

Determine Critical Value

For \( n_1 = 10 \) (orange juice) and \( n_2 = 10 \) (ascorbic acid) at \( \alpha = 0.01 \), refer to the Wilcoxon rank-sum test table to find the critical value of the test statistic. This will be used to evaluate if the difference is statistically significant.
04

Calculate Test Statistic

Calculate the test statistic \( U \) using the formula \( U = n_1 n_2 + \frac{n_1(n_1+1)}{2} - R_1 \), where \( n_1 \) and \( n_2 \) are the numbers of observations in each group, and \( R_1 \) is the rank sum of the orange juice group.
05

Determine Result of Hypothesis Test

Compare the calculated value of the test statistic \( U \) with the critical value obtained previously. If \( U \) is less than or equal to the critical value, reject the null hypothesis that there is no difference in the true average lengths for the two groups. Otherwise, do not reject the null hypothesis.
06

Approximate P-value

To approximate the \( P \)-value, determine the probability of observing a test statistic as extreme as, or more extreme than, the observed statistic under the null hypothesis. Use a normal approximation or software to calculate this value, referring to the distribution of \( U \) for comparisons.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Hypothesis Testing
Statistical hypothesis testing is a critical component of data analysis, providing a method to make informed decisions based on data samples. The primary objective is to determine whether there is sufficient evidence to reject a null hypothesis, which typically represents a statement of no effect or difference.

The process involves setting up two opposing hypotheses:
  • Null Hypothesis (H0): Assumes no difference or effect.
  • Alternative Hypothesis (Ha): Indicates the presence of a difference or effect.
In our exercise, the null hypothesis posits that there is no difference in the true average length of odontoblasts due to vitamin C intake from orange juice versus synthetic ascorbic acid. The alternative suggests a significant difference exists.

To test these hypotheses, we use statistical tests to calculate a test statistic and compare it to a critical value derived under the null hypothesis. If our test statistic is extreme, relative to what we would expect under the null hypothesis, we may reject the null in favor of the alternative.
Vitamin C Comparison
The context of this study is centered around the comparison between two sources of Vitamin C—orange juice and synthetic ascorbic acid. Vitamin C is essential for various bodily functions, including the synthesis of collagen, which is crucial for maintaining the structure of teeth and bones.

In this exercise, researchers aim to understand if the natural form of Vitamin C found in orange juice impacts the growth of odontoblasts (cells responsible for forming dentin in teeth) differently than its synthetic counterpart. This comparison is important because it can influence dietary recommendations and vitamin supplementation choices.

The researchers collect data on odontoblast lengths after feeding guinea pigs with each type of vitamin C. The critical observation is whether the form of Vitamin C results in a significant variation in growth, potentially leading to changes in how Vitamin C is consumed in diets.
Odontoblast Length
Odontoblasts are specialized cells involved in tooth development and dentin formation. Understanding odontoblast length is important to gauge the effects of various dietary components on tooth growth and health.

In the described study, odontoblast length is used as an indicator of vitamin C's efficacy. If odontoblasts are longer with one type of vitamin C intake, it suggests better efficacy in promoting cell growth. This indicator can shed light on the relative benefits of natural versus synthetic vitamin C sources.

When evaluating the results, scientists look not only for measurable differences in odontoblast length but also for statistical significance. This ensures that any observed differences are not due to random chance but rather a genuine effect of the vitamin source being studied.
Non-Parametric Statistics
Non-parametric statistics are especially useful when data does not meet certain assumptions required by parametric tests, such as normal distribution. These methods are robust and versatile, often used for ordinal data or when sample sizes are small.

The Wilcoxon rank-sum test, as used in this study, is a common non-parametric test. It compares the medians of two groups to assess if they are statistically different. This test ranks all data without assuming a normal distribution, making it ideal for the odontoblast length data in guinea pigs, which might not follow a normal distribution.

Using non-parametric tests allows conclusions to be drawn about the data without the constraints of stricter statistical assumptions. It is particularly beneficial when working with non-normally distributed or ordinal data, ensuring reliable and accurate results that reflect the true differences between groups.

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Most popular questions from this chapter

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