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You are told that a \(95 \%\) CI for expected lead content when traffic flow is 15 , based on a sample of \(n=10\) observations, is \((462.1,597.7)\). Calculate a CI with confidence level \(99 \%\) for expected lead content when traffic flow is 15 .

Short Answer

Expert verified
99% CI is wider than 95%: \((432.5, 627.3)\)

Step by step solution

01

Understand the Confidence Interval

The provided information gives us a 95% confidence interval (CI) for the population mean, which is based on the sample mean (\(\bar{x}\)) and standard error (SE). The 95% CI is (462.1, 597.7).
02

Calculate the Sample Mean

The sample mean (\(\bar{x}\)) is the midpoint of the 95% CI. Calculate it by averaging the endpoints: \(\bar{x} = \frac{462.1 + 597.7}{2}\).
03

Calculate the Margin of Error for the 95% CI

The margin of error (ME) at 95% is half the width of the confidence interval: \(\text{ME}_{95\%} = \frac{597.7 - 462.1}{2}\).
04

Convert Margin of Error to Standard Error

The standard error (SE) is derived from the margin of error and the critical value for the 95% CI, which is often 1.96 for large samples. Since \(n=10\), the t-distribution is appropriate, and we determine the appropriate t-value. However, since the ME was not specified in terms of t, utilize the ME formula \(\text{ME}_{95\%} = t_{0.025,9} \cdot \text{SE}\).
05

Calculate Standard Error

From Step 3, compute the standard error using the margin of error and t-value for 95% (\(t_{0.025,9}\)) which is approximately 2.262: \(\text{SE} = \frac{\text{ME}_{95\%}}{t_{0.025,9}}\).
06

Adjust Confidence Level to 99%

For a 99% confidence interval, the critical t-value (\(t_{0.005,9}\)) increases due to higher confidence; approximately 3.250 for \(n=10\).
07

Calculate the 99% Margin of Error

Multiply the standard error calculated in Step 5 by the t-value for 99% CI: \(\text{ME}_{99\%} = t_{0.005,9} \times \text{SE}\).
08

Construct the 99% Confidence Interval

Using the sample mean calculated in Step 2 and the 99% margin of error calculated in Step 7, construct the 99% CI: \((\bar{x} - \text{ME}_{99\%}, \bar{x} + \text{ME}_{99\%})\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
The sample mean, denoted as \( \bar{x} \), represents the average value of a given set of data points. It serves as an estimate of the true population mean, especially when the complete population data is unavailable. In a confidence interval, the sample mean is a pivotal point around which the interval is centered. To compute the sample mean from a two-endpoint confidence interval, you simply calculate the midpoint:
  • Add the lower and upper bounds of the interval together.
  • Divide the sum by 2.
For example, given a 95% confidence interval of (462.1, 597.7), the sample mean \( \bar{x} \) is calculated as:\[\bar{x} = \frac{462.1 + 597.7}{2} = 529.9\] Understanding the sample mean's role will help further comprehend how the entire distribution of potential sample means behaves.
Margin of Error
The margin of error (ME) quantifies the extent of random sampling error in a survey's results. Within a confidence interval, the margin of error defines the range within which we can be reasonably sure the true population parameter lies.
  • It is essentially half the width of the confidence interval.
  • Reflects variability and potential error, offering a cushion of certainty around the sample mean.
To calculate it for a 95% confidence interval such as (462.1, 597.7):\[\text{ME}_{95\%} = \frac{597.7 - 462.1}{2} = 67.8\] This numerical representation aids students in recognizing how much uncertainty exists in their estimation, so they can predict the range of values confidently.
Standard Error
The standard error (SE) is a critical metric for gauging the extent of variation within a sample, reflecting the standard deviation of its sampling distribution. In simpler terms, it indicates how much the sample mean deviates from the actual population mean.
  • SE is lower when there is less data variability.
  • Increases with smaller sample sizes, as it implies more variability in the estimates.
When using a t-distribution, the standard error can be calculated from the margin of error and the t-value associated with specific confidence levels. Using:\[\text{SE} = \frac{\text{ME}_{95\%}}{t_{0.025,9}} = \frac{67.8}{2.262} \approx 29.98\] The SE helps to fine-tune the accuracy of the confidence interval by factoring in the sample size and its inherent variation.
t-distribution
The t-distribution is a probabilistic model used primarily when dealing with small sample sizes (\( n < 30 \)) or unknown population standard deviations. It's a variation of the normal distribution but accommodates more variability at the tails, granting accurate critical values for forming confidence intervals.
  • The shape adjusts based on the sample size, being wider with smaller samples.
  • Used to derive the critical t-value necessary for calculating margins of error in confidence intervals.
For instance, when transitioning from a 95% to a 99% confidence level, you'll use a larger t-value because more certainty is required. The critical t-value for 99% confidence with \( n=10 \) (degrees of freedom = 9) is about 3.250:\[\text{ME}_{99\%} = t_{0.005,9} \times \text{SE} = 3.250 \times 29.98\] It forms the foundation for calculating confidence intervals, offering a means to adjust the width to match the specified confidence level. Understanding how and when to employ the t-distribution is vital for any analysis involving small samples.

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