Chapter 12: Problem 49
You are told that a \(95 \%\) CI for expected lead content when traffic flow is 15 , based on a sample of \(n=10\) observations, is \((462.1,597.7)\). Calculate a CI with confidence level \(99 \%\) for expected lead content when traffic flow is 15 .
Short Answer
Expert verified
99% CI is wider than 95%: \((432.5, 627.3)\)
Step by step solution
01
Understand the Confidence Interval
The provided information gives us a 95% confidence interval (CI) for the population mean, which is based on the sample mean (\(\bar{x}\)) and standard error (SE). The 95% CI is (462.1, 597.7).
02
Calculate the Sample Mean
The sample mean (\(\bar{x}\)) is the midpoint of the 95% CI. Calculate it by averaging the endpoints: \(\bar{x} = \frac{462.1 + 597.7}{2}\).
03
Calculate the Margin of Error for the 95% CI
The margin of error (ME) at 95% is half the width of the confidence interval: \(\text{ME}_{95\%} = \frac{597.7 - 462.1}{2}\).
04
Convert Margin of Error to Standard Error
The standard error (SE) is derived from the margin of error and the critical value for the 95% CI, which is often 1.96 for large samples. Since \(n=10\), the t-distribution is appropriate, and we determine the appropriate t-value. However, since the ME was not specified in terms of t, utilize the ME formula \(\text{ME}_{95\%} = t_{0.025,9} \cdot \text{SE}\).
05
Calculate Standard Error
From Step 3, compute the standard error using the margin of error and t-value for 95% (\(t_{0.025,9}\)) which is approximately 2.262: \(\text{SE} = \frac{\text{ME}_{95\%}}{t_{0.025,9}}\).
06
Adjust Confidence Level to 99%
For a 99% confidence interval, the critical t-value (\(t_{0.005,9}\)) increases due to higher confidence; approximately 3.250 for \(n=10\).
07
Calculate the 99% Margin of Error
Multiply the standard error calculated in Step 5 by the t-value for 99% CI: \(\text{ME}_{99\%} = t_{0.005,9} \times \text{SE}\).
08
Construct the 99% Confidence Interval
Using the sample mean calculated in Step 2 and the 99% margin of error calculated in Step 7, construct the 99% CI: \((\bar{x} - \text{ME}_{99\%}, \bar{x} + \text{ME}_{99\%})\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sample Mean
The sample mean, denoted as \( \bar{x} \), represents the average value of a given set of data points. It serves as an estimate of the true population mean, especially when the complete population data is unavailable. In a confidence interval, the sample mean is a pivotal point around which the interval is centered. To compute the sample mean from a two-endpoint confidence interval, you simply calculate the midpoint:
- Add the lower and upper bounds of the interval together.
- Divide the sum by 2.
Margin of Error
The margin of error (ME) quantifies the extent of random sampling error in a survey's results. Within a confidence interval, the margin of error defines the range within which we can be reasonably sure the true population parameter lies.
- It is essentially half the width of the confidence interval.
- Reflects variability and potential error, offering a cushion of certainty around the sample mean.
Standard Error
The standard error (SE) is a critical metric for gauging the extent of variation within a sample, reflecting the standard deviation of its sampling distribution. In simpler terms, it indicates how much the sample mean deviates from the actual population mean.
- SE is lower when there is less data variability.
- Increases with smaller sample sizes, as it implies more variability in the estimates.
t-distribution
The t-distribution is a probabilistic model used primarily when dealing with small sample sizes (\( n < 30 \)) or unknown population standard deviations. It's a variation of the normal distribution but accommodates more variability at the tails, granting accurate critical values for forming confidence intervals.
- The shape adjusts based on the sample size, being wider with smaller samples.
- Used to derive the critical t-value necessary for calculating margins of error in confidence intervals.