/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 A sample of \(n=10\) automobiles... [FREE SOLUTION] | 91Ó°ÊÓ

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A sample of \(n=10\) automobiles was selected, and each was subjected to a \(5-m p h\) crash test. Denoting a car with no visible damage by \(\mathrm{S}\) (for success) and a car with such damage by \(\mathrm{F}\), results were as follows: S \(S \quad F \quad S \quad S \quad S \quad F \quad F \quad S \quad S\) a. What is the value of the sample proportion of successes \(x / n ?\) b. Replace each S with a 1 and each \(\mathrm{F}\) with a 0 . Then calculate \(\bar{x}\) for this numerically coded sample. How does \(\bar{x}\) compare to \(x / n\) ? c. Suppose it is decided to include 15 more cars in the experiment. How many of these would have to be \(S\) 's to give \(x / n=.80\) for the entire sample of 25 cars?

Short Answer

Expert verified
a. 0.7, b. \(\bar{x}\) is 0.7, same as \(x/n\), c. 13 additional \(S\)'s needed.

Step by step solution

01

Identify the Total Number of Trials and Successes

Given that we have a sample of 10 automobiles, each denoted as either a 'Success' (\(S\)) or a 'Failure' (\(F\)), we need to calculate the number of successes. From the results: \(S, S, F, S, S, S, F, F, S, S\), we count the number of \(S\)'s. There are 7 \(S\)'s.
02

Calculate the Sample Proportion of Successes

The sample proportion of successes (\(x/n\)) is calculated by dividing the number of successes (\(x\)) by the total number of trials (\(n\)). Here, \(x = 7\) and \(n = 10\). Thus, the proportion is \(x/n = 7/10 = 0.7\).
03

Replace S and F with Numerical Values

Here we replace each \(S\) with 1 and each \(F\) with 0. The sequence becomes: 1, 1, 0, 1, 1, 1, 0, 0, 1, 1.
04

Calculate the Mean (\(\bar{x}\)) of the Numerical Sample

Calculate \(\bar{x}\) by finding the mean of the numeric sequence. Sum the values: \(1 + 1 + 0 + 1 + 1 + 1 + 0 + 0 + 1 + 1 = 7\). Divide by the number of data points (10): \(\bar{x} = 7/10 = 0.7\).
05

Compare \(\bar{x}\) to \(x/n\)

We see that \(\bar{x} = 0.7\) is the same as the sample proportion of successes \(x/n = 0.7\). Both are identical.
06

Determine Additional Successes for a Larger Sample

Now including 15 more cars for a total of 25, we need to find out how many of these additional cars should be \(S\) to achieve \(x/n = 0.8\). Let \(y\) be the number of \(S\)'s among these 15. To achieve an overall proportion of 0.8, we have:\[\frac{7 + y}{25} = 0.8\]Multiply both sides by 25:\[7 + y = 20\]Solving for \(y\), we get \(y = 13\). So, 13 of the 15 additional cars need to be \(S\)'s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Crash Test Statistics
Crash test statistics are crucial for evaluating the safety levels of automobiles. By analyzing the data from crash tests, researchers can draw conclusions about a vehicle's performance. In this exercise, we focus on determining the probability of no visible damage, indicated as 'Success' (S), in a sample of automobiles that underwent a fixed-speed crash test. By considering a sample of 10 cars, where each test result is either a success or a failure, we can assess how well the cars withstand crashes. This experiment highlights how statistical methods can be conducted to make meaningful predictions about general vehicle safety. Understanding these statistics helps manufacturers improve vehicle designs for better crash resistance.
Mean Calculation
The mean, often described as the average, is a central tendency measure that provides an insight into the data's overall performance. In our exercise, the task involves converting qualitative results ('Success' or 'Failure') into a quantitative format (1 or 0) to allow for numeric calculations.
This transformation helps in calculating the mean, which in this case is referred to as \( \bar{x} \). By summing all the numerical values from the sequence (such as 1+1+0+1+1+1+0+0+1+1) and dividing by the number of cars (10), we derive the mean value. With this numeric representation, comparison with the proportion of successes obtained directly from the observed data becomes straightforward.
In our example, both calculations resulted in the same mean of 0.7, showing that the numeric mean is equivalent to the proportion of successes when simplified.
Numerical Coding
Numerical coding is a technique employed to convert categorical data into a numerical format to facilitate calculations. In our exercise, the results of a crash test—either 'Success' (S) or 'Failure' (F)—are converted into two numerical values, 1 for 'Success' and 0 for 'Failure'.
This conversion allows for easy analysis of the sample, feeding directly into calculations such as the mean. Coding non-numeric data into numbers is particularly useful in statistics because it allows for direct computation and analysis using mathematical operations.
In practical terms, this process simplifies complex datasets and lets researchers quickly extract insights, such as average performance, which might not be easily discernible in written or categorical form.
Proportion Calculation
Proportion calculation is fundamental in understanding the fraction of a total that exhibits a certain characteristic. In the context of this exercise, we're interested in the proportion of automobiles that made it through the crash test without damage, also known as 'Successes'.
To determine this, we divide the number of successes \(x\) by the total number of vehicles tested \(n\). This ratio, known as the sample proportion (\(x/n\)), provides a simple yet powerful insight into the dataset.
Additionally, adjusting the sample size or number of successes allows researchers to manipulate the statistics as per the larger sample requirements. For instance, including 15 more cars in our sample and calculating how many should be successful to achieve a target proportion showcases the practical application of these calculations in planning and prediction. Through such nuanced analysis, proportion calculations become instrumental in guiding both experimental design and real-world decision-making.

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