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Describe how to convert a random sample \({{\bf{U}}_{\bf{1}}}{\bf{, \ldots ,}}{{\bf{U}}_{\bf{n}}}\) from the uniform distribution on the interval \({\bf{[0,1]}}\) to a random sample of size \({\bf{n}}\) from the uniform distribution on the interval\({\bf{[a,b]}}\).

Short Answer

Expert verified

The Variable is \({V_i} = a + (b - a){U_i}.\)

Step by step solution

01

Definition for uniform random sample:

The samples are distributed uniformly across the half-open interval [low, high] (includes low, but excludes high). In other words, uniform is equally likely to draw any value within the given interval.

02

Find a random variable from uniform distribution:

The\(cdf\)of a random variable from uniform distribution on interval\([a,b]\)is

\(F(x) = \frac{{x - a}}{{b - a}},\;\;\;a \le x \le b\)

Zero for\(x < a\)and\(1\)for\(x > b\)

Define random variables\({V_i},i = 1,2, \ldots ,n\)as

\({V_i} = a + (b - a){U_i},\;\;\;i = 1,2, \ldots ,n,\)

Where\({U_i}\)are as defined in the exercise.

Obviously, such random variable has uniform distribution with pdf

\(f(v) = \frac{1}{{b - a}},\;\;\;a \le v \le b\)

Or equally, it has uniform distribution on interval\([a,b]\).

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Most popular questions from this chapter

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