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Suppose that a random variable X can have each of the seven values −3, −2, −1, 0, 1, 2, 3 with equal probability. Determine the p f. Of \(Y = {X^2} - X\)

Short Answer

Expert verified

The p f of \(Y = {X^2} - X = \frac{1}{7}\)

Step by step solution

01

given information

Random variable X can have each seven values -3,-2,-1,0,1,2,3

02

Compute the probability

Possible values for Y are 0, 2, 6,12.

\(\begin{aligned}{\rm P}\left( {Y = 0} \right) &= {\rm P}\left( {X = 1{\rm{ }}or{\rm{ }}X = 0} \right)\\ &= \frac{2}{7}\end{aligned}\)

\(\begin{aligned}{\rm P}\left( {Y = 2} \right) &= {\rm P}\left( {X = - 1{\rm{ }}or{\rm{ }}X = 2} \right)\\ &= \frac{2}{7}\end{aligned}\)

\(\begin{aligned}{\rm P}\left( {Y = 6} \right) &= {\rm P}\left( {X = - 2{\rm{ }}or{\rm{ }}X = 3} \right)\\ &= \frac{2}{7}\end{aligned}\)

\(\begin{aligned}{\rm P}\left( {Y = 12} \right) &= {\rm P}\left( {{\rm{ }}X = - 3} \right)\\ &= \frac{1}{7}\end{aligned}\)

Therefore the p f of\(Y = {X^2} - X = \frac{1}{7}\)

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