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Let the initial probability vector in Example 3.10.6 be\(v = \left( {\frac{1}{{16}},\frac{1}{4},\frac{1}{8},\frac{1}{4},\frac{1}{4},\frac{1}{{16}}} \right)\)Find the probabilities of the six states after one generation.

Short Answer

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Probabilities of the six states after one generation.

Step by step solution

01

Given information

A botanist is studying a certain variety of plants that is monoecious.

She begins with two plants1 and 2 and cross-pollinates them by crossing male 1 with female 2 and female 1 with male 2. producing two offspring for the next generation.

02

Computing the transition probability matrix.

Suppose that gene has two alleles, A and a.

An individual's genotype will result in any of the three combinations. AA, Aa, or aa.

When a new individual takes birth, it receives one of the two alleles from the other parent. the two offspring get their genotypes independently of each other.

Let the states of this population be the set of genotypes of the two members of the current population. We will not distinguish the set\(\left\{ {AA,Aa} \right\}\).

There are six states:

\(\left\{ {AA,AA} \right\},\left\{ {AA,Aa} \right\},\left\{ {AA,aa} \right\},\left\{ {Aa,Aa} \right\},\left\{ {Aa,aa} \right\},\left\{ {aa,aa} \right\}\)

For each state, we can compute the values for the probabilities that the next generation will be in each of the six states.

Therefore computing the probability matrix as

\(TP = \left[ {\begin{array}{*{20}{c}}1&0&0&0&0&0\\{0.25}&{0.5}&0&{0.25}&0&0\\0&0&0&1&0&0\\{0.0625}&{0.25}&{0.125}&{0.25}&{0.25}&{0.0625}\\0&0&0&{0.25}&{0.5}&{0.25}\\0&0&0&0&0&1\end{array}} \right]\)

The rows and columns are represented in the order

\(\left\{ {AA,AA} \right\},\left\{ {AA,Aa} \right\},\left\{ {AA,aa} \right\},\left\{ {Aa,Aa} \right\},\left\{ {Aa,aa} \right\},\left\{ {aa,aa} \right\}\)

03

Computing the probabilities of the six states after one generation

The initial probability matrix be

\(v = \left( {\frac{1}{{16}},\frac{1}{4},\frac{1}{8},\frac{1}{4},\frac{1}{4},\frac{1}{{16}}} \right)\)

To calculate the probability of the six states after one generation.

This is equal to the multiplication of the matrix TP and v, as shown below:

\(\left[ {v \times TP} \right]\)

\( = \left( {\frac{1}{{16}},\frac{1}{4},\frac{1}{8},\frac{1}{4},\frac{1}{4},\frac{1}{{16}}} \right) \times \left[ {\begin{array}{*{20}{c}}1&0&0&0&0&0\\{0.25}&{0.5}&0&{0.25}&0&0\\0&0&0&1&0&0\\{0.0625}&{0.25}&{0.125}&{0.25}&{0.25}&{0.0625}\\0&0&0&{0.25}&{0.5}&{0.25}\\0&0&0&0&0&1\end{array}} \right]\)

\(\left[ {v \times TP} \right] = \left[ {0.1406\;\;0.1875\;\;0.03125\;\;0.1875\;\;0.1406} \right]\)

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Most popular questions from this chapter

Question:Suppose that two random variables X and Y have the joint p.d.f.\(f\left( {x,y} \right) = \left\{ \begin{array}{l}k{x^2}{y^2}\,\,\,\,\,\,\,\,\,\,\,\,for\,{x^2} + {y^2} \le 1\\0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,otherwise\end{array} \right.\). Compute the conditional p.d.f. of X given

Y = y for each y.

Question:Suppose thatXandYare random variables such that(X, Y)must belong to the rectangle in thexy-plane containing all points(x, y)for which 0≤x≤3 and 0≤y≤4. Suppose also that the joint c.d.f. ofXandYat every point

(x,y) in this rectangle is specified as follows:

\({\bf{F}}\left( {{\bf{x,y}}} \right){\bf{ = }}\frac{{\bf{1}}}{{{\bf{156}}}}{\bf{xy}}\left( {{{\bf{x}}^{\bf{2}}}{\bf{ + y}}} \right)\)

Determine

(a) Pr(1≤X≤2 and 1≤Y≤2);

(b) Pr(2≤X≤4 and 2≤Y≤4);

(c) the c.d.f. ofY;

(d) the joint p.d.f. ofXandY;

(e) Pr(Y≤X).

Suppose that a Markov chain has four states 1, 2, 3, 4, and stationary transition probabilities as specified by the following transition matrix

\(p = \left[ {\begin{array}{*{20}{c}}{\frac{1}{4}}&{\frac{1}{4}}&0&{\frac{1}{2}}\\0&1&0&0\\{\frac{1}{2}}&0&{\frac{1}{2}}&0\\{\frac{1}{4}}&{\frac{1}{4}}&{\frac{1}{4}}&{\frac{1}{4}}\end{array}} \right]\):

a.If the chain is in state 3 at a given timen, what is the probability that it will be in state 2 at timen+2?

b.If the chain is in state 1 at a given timen, what is the probability it will be in state 3 at timen+3?

A civil engineer is studying a left-turn lane that is long enough to hold seven cars. LetXbe the number of cars in the lane at the end of a randomly chosen red light. The engineer believes that the probability thatX=xis proportional to(x+1)(8−x)forx=0, . . . ,7 (the possible values ofX).

a. Find the p.f. ofX.

b. Find the probability thatXwill be at least 5.

In Example 3.8.4, the p.d.f. of \({\bf{Y = }}{{\bf{X}}^{\bf{2}}}\) is much larger for values of y near 0 than for values of y near 1 despite the fact that the p.d.f. of X is flat. Give an intuitive reason why this occurs in this example.

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