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A box contains 24 light bulbs, of which four are defective. If a person selects four bulbs from the box at random, without replacement, what is the probability that all four bulbs will be defective?

Short Answer

Expert verified

The probability of getting all four defective bulbs will be \(\frac{1}{{10626}}\) .

Step by step solution

01

Given information

A box has 24 bulbs out of which 4 bulbs are defective.

The bulbs are selected without replacement.

02

Compute the counts 

The total number of bulbs in a box is 24.

Number of defective bulbs is 4.

Thus, total working bulbs are\(\left( {24 - 4} \right) = 20\)

Formula for selecting r items from total N items is\(^N{C_r} = \frac{{N!}}{{r!\left( {N - r} \right)!}}\)

Number of ways of selecting any 4 defective bulbs from 24 bulbs is\(^{24}{C_4} = \frac{{24!}}{{4!\left( {24 - 4} \right)!}}\).

Number of ways of selecting 4 defective bulb is \(^4{C_4} = \frac{{4!}}{{4!\left( {4 - 4} \right)!}}\).

03

Compute the probability

Probability of selecting all 4 defective bulbs is expressed as,

\(\begin{aligned}{c}\frac{{^4{C_4}}}{{^{24}{C_4}}} &= \frac{{\frac{{4!}}{{4!\left( {4 - 4} \right)!}}}}{{\frac{{24!}}{{4!\left( {24 - 4} \right)!}}}}\\ &= \frac{1}{{10626}}\end{aligned}\)

Therefore, the probability of selecting all 4 defective bulbs is\(\frac{1}{{10626}}\).

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