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Suppose thatXis a random variable for whichE(X)=1, \(E\left( {{X^2}} \right) = 2\), and \(E\left( {{X^3}} \right) = 5\). Find the value of the thirdcentral moment ofX.

Short Answer

Expert verified

The third central moment of X is 1.

Step by step solution

01

Given information

X is a random variable.

\(\begin{array}{l}E\left( X \right) = 1\\E\left( {{X^2}} \right) = 2\\E\left( {{X^3}} \right) = 5\end{array}\)

02

Computing the central moment

The third central moment of X is

\(\begin{array}{c}E\left[ {{{\left( {X - \mu } \right)}^3}} \right] = E\left[ {{{\left( {X - 1} \right)}^3}} \right]\\ = E\left( {{X^3} - 3{X^2} + 3X - 1} \right)\\ = E\left( {{X^3}} \right) - 3E\left( {{X^2}} \right) + 3E\left( X \right) - 1\\ = 5 - \left( {3 \times 2} \right) + \left( {3 \times 1} \right) - 1\\ = 5 - 6 + 3 - 1\\ = 1\end{array}\)

Therefore, the third central moment of X is 1.

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Most popular questions from this chapter

Prove the following extension of Theorem 4.4.1: If \(E\left( {{{\left| X \right|}^a}} \right) < \infty \) for some positive number a, then \(E\left( {{{\left| X \right|}^b}} \right) < \infty \) for every positive number \(b < a\). Give the proof for the case in which X has a discrete distribution.

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