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Suppose that a point is chosen at random on a stick of unit length and that the stick is broken into two pieces at that point. Find the expected value of the size of the longer piece.

Short Answer

Expert verified

The expected value of the length of the longer piece is \(\frac{3}{4}\)

Step by step solution

01

Given information

A stick follows a unit length. So, It is from a uniform distribution on the interval [0,1]. The stick is broken into two pieces at a randomly selected point.

02

State the events

Let us consider X, the broken piece of the stick. So\(X \sim Unif\left( {0,1} \right)\), Y is the length of the longer part of the broken post.\(Y = \max \left( {X,1 - X} \right)\).

Therefore,

\(Y = \left\{ \begin{array}{l}1 - X\;if\;X < \frac{1}{2}\\X\;if\;X \ge \frac{1}{2}\end{array} \right.\)

03

Calculate the expected value

The expected length of the longer piece is,

\(\begin{array}{c}E\left( Y \right) = \int_0^{\frac{1}{2}} {\left( {1 - X} \right)dx + \int_{\frac{1}{2}}^1 {xdx} } \\ = \frac{3}{8} + \frac{3}{8}\\ = \frac{3}{4}\end{array}\)

Thus, the required expected value is \(\frac{3}{4}\).

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Prove that if\({\bf{Var}}\left( {\bf{X}} \right){\bf{ < }}\infty \)and\({\bf{Var}}\left( {\bf{Y}} \right){\bf{ < }}\infty \), then\({\bf{Cov}}\left( {{\bf{X,Y}}} \right)\)is finite. Hint:By considering the relation

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