/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q10E The uniform distribution on the ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The uniform distribution on the interval [a, b], where the value of a is known and the value of b is unknown\(\left( {b > a} \right)\):\(T = \min \left\{ {{X_1},...{X_n}} \right\}\)

Short Answer

Expert verified

Statistic T is sufficient statistic.

Step by step solution

01

Given information

\({X_1},{X_2}...{X_n}\)denote iid random variables from the uniform distribution with parameter\(\left[ {a,b} \right]\)where b is known and the value of a is unknown.

\(\left( {b > a} \right)\),\(T = \min \left\{ {{X_1},...{X_n}} \right\}\)

02

Computing the pdf of x

The pdf of X is given as

\({f_x} = \left\{ \begin{array}{l}\frac{1}{{b - a}}\;\;\;\;\;\;\;b > a\\0\;\;\;\;\;\;\;\;\;\;\;\;otherwise\end{array} \right.\)

03

verifying T is the sufficient statistic.

Let us consider the statistic\(T = \min \left\{ {{X_1},...{X_n}} \right\}\)

The estimator T is sufficient for a if

\(f\left( {{x_1}...{x_n}|T = t} \right) = \frac{{f\left( {{x_1}} \right)f\left( {{x_1}} \right)...f\left( {{x_1}} \right)}}{{{g_1}\left( {a,t} \right)}}\) is independent of a

Defining a function\(g\left( {a,t} \right)\)

\(g\left( {a,t} \right) = \left\{ \begin{array}{l}\frac{1}{{{{\left( {b - a} \right)}^n}}}\;\;\;if\;a \le \min \left\{ {{X_1}...{X_n}} \right\}\\0\;\;\;\;\;\;\;\;\;\;\;if\;a > \min \left\{ {{X_1}...{X_n}} \right\}\end{array} \right.\)

On rearranging the joint function as

\(\begin{array}{c}f\left( {{x_1}...{x_n}|T = t} \right) = \frac{{f\left( {{x_1}} \right)f\left( {{x_1}} \right)...f\left( {{x_1}} \right)}}{{{g_1}\left( {a,t} \right)}}\\ = \frac{{\frac{1}{{b - a}} \times ...\frac{1}{{b - a}}n\;times}}{{\frac{1}{{{{\left( {b - a} \right)}^n}}}}}\end{array}\)

\(\begin{array}{c}f\left( {{x_1}...{x_n}|T = t} \right) = \frac{1}{{{{\left( {b - a} \right)}^n}}} \times \frac{{{{\left( {b - a} \right)}^n}}}{1}\\ = 1\end{array}\)

Hence we observe the conditional joint distribution gives the estimator T is independent of unknown paramenter a.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Show that each of the following families of distributions is an exponential family, as defined in Exercise 23:

a. The family of Bernoulli distributions with an unknown value of the parameter p

b. The family of Poisson distributions with an unknown mean.

c. The family of negative binomial distributions for which the value of r is known and the value of p is unknown

d. The family of normal distributions with an unknown mean and a known variance

e. The family of normal distributions with an unknown variance and a known mean

f. The family of gamma distributions for which the value of α is unknown and the value of β is known

g. The family of gamma distributions for which the value of α is known and the value of β is unknown

h. The family of beta distributions for which the value of α is unknown and the value of β is known

i. The family of beta distributions for which the value of α is known and the value of β is unknown.

Question: Suppose that \({{\bf{X}}_{\bf{1}}}{\bf{,}}...{\bf{,}}{{\bf{X}}_{\bf{n}}}\) form a random sample from a distribution for which the p.d.f. f (x|θ ) is as follows:

\(\begin{array}{c}{\bf{f}}\left( {{\bf{x|\theta }}} \right){\bf{ = \theta }}{{\bf{x}}^{{\bf{\theta - 1}}\,\,\,}}{\bf{,0 < \theta < 1}}\\{\bf{ = 0}}\,\,\,\,{\bf{otherwise}}\end{array}\)

Also, suppose that the value of θ is unknown (θ > 0). Find the M.L.E. of θ

In Example 7.1.6, identify any statistical inference mentioned.

Question: Consider the conditions of Exercise 2 again. Suppose that the prior distribution of θ is as given in Exercise 2, and suppose again that 20 items are selected at random from the shipment.

a. For what number of defective items in the sample will the mean squared error of the Bayes estimate be a maximum?

b. For what number the mean squared error of the Bayes estimate will be a minimum?

Identify the components of the statistical model (as defined in Definition 7.1.1) in Example 7.1.3.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.