/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 Let \(\left\\{X_{r}: r \geq 1 /\... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(\left\\{X_{r}: r \geq 1 /\right.\) be independent Poisson variables with respective parameters \(\left\\{\lambda_{r}: r \geq 1\right]\). Show that \(\sum_{r=1}^{\infty} X_{r}\) converges or diverges almost surely according as \(\sum_{r=1}^{\infty} \lambda_{r}\) converges or diverges.

Short Answer

Expert verified
The series \\( \sum_{r=1}^{\infty} X_r \\\) converges almost surely if and only if \\( \sum_{r=1}^{\infty} \lambda_r \\\) converges.

Step by step solution

01

Understand Poisson Distribution

A Poisson random variable represents the number of events occurring in a fixed interval with an average rate of \( \lambda_r \). Each \( X_r \) being independent with parameter \( \lambda_r \) means they individually follow this distribution.
02

Consider Convergence of Poisson Distribution

For the sum \( \sum_{r=1}^{\infty} X_r \) to converge almost surely, the expected value, \( E\left[\sum_{r=1}^{\infty} X_r\right] \), must converge. The expected value is \( \sum_{r=1}^{\infty} \lambda_r \) as expectation of a Poisson \( X_r \) is \( \lambda_r \).
03

Apply Kolmogorov's Zero-One Law

Since \( X_r \) are independent, we can use Kolmogorov's zero-one law. This law states that for independent variables, if a series converges almost surely, then its series of expected values also converges, and vice versa.
04

Evaluate Based on Series Convergence

If \( \sum_{r=1}^{\infty} \lambda_r \) converges, it directly implies \( \sum_{r=1}^{\infty} X_r \) converges with probability 1 by Kolmogorov's law. Conversely, if \( \sum_{r=1}^{\infty} \lambda_r \) diverges, then \( \sum_{r=1}^{\infty} X_r \) diverges almost surely.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Poisson Distribution
The Poisson distribution is a fundamental concept in probability theory, used to model the number of times an event occurs within a fixed interval of time or space. The event should be rare, but frequent enough to have an average number of occurrences, denoted by \( \lambda \). In essence, the Poisson distribution gives us a way to predict how likely it is that an event will happen a specific number of times over a defined duration.

The defining characteristic of a Poisson distribution is its parameter \( \lambda \), which is both the mean and the variance of the distribution. For a Poisson random variable \( X_r \), the mean is the expected value \( E[X_r] = \lambda_r \) and the probability of observing \( k \) events is given by:
\[ P(X_r = k) = \frac{{e^{-\lambda_r} \lambda_r^k}}{{k!}} \]
This equation indicates that with a larger \( \lambda_r \), events are more likely to occur, while fewer events are likely with a smaller \( \lambda_r \). Each \( X_r \) in our context, represents independent Poisson variables, illustrating how the distribution is versatile and widely applicable in different fields.
Convergence of Series
Series convergence is a crucial topic in calculus and probability that deals with determining whether a given infinite series sums up to a finite value. When working with series of random variables such as \( \sum_{r=1}^{\infty} X_r \), determining convergence based on expectations is essential.

For a series \( \sum_{r=1}^{\infty} X_r \) of Poisson random variables to converge almost surely (with probability 1), the corresponding expected series \( \sum_{r=1}^{\infty} \lambda_r \) must converge. This means that the sum of the expectations (or means) of the individual Poisson variables \( X_r \) must lean towards a finite value.

Convergence can be tested using various criteria, such as the comparison test, ratio test, or integral test. However, in this scenario, the convergence of the series \( \sum_{r=1}^{\infty} \lambda_r \) gives a straightforward determining factor for the convergence of the series of Poisson random variables.
Kolmogorov's Zero-One Law
Kolmogorov's Zero-One Law is a profound concept in the field of probability theory and provides an elegant solution to determine the almost sure convergence of a series of independent random variables. According to this principle, certain events either happen with probability 1 or probability 0, leaving no room for intermediate probabilities.

In the context of our problem, the law implies that for the series \( \sum_{r=1}^{\infty} X_r \) to converge almost surely, it is necessary that the expected values \( \sum_{r=1}^{\infty} \lambda_r \) converge. This criterion is particularly potent as it simplifies the process of checking convergence: instead of assessing random variances of \( X_r \), you can focus on \( \lambda_r \) values.

When \( \sum_{r=1}^{\infty} \lambda_r \) converges, Kolmogorov's Zero-One Law guarantees that \( \sum_{r=1}^{\infty} X_r \) converges almost surely; if it diverges, so does the series of \( X_r \). This connection between the convergence of series of expected values and random variables highlights the robustness and utility of this law in probability.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose that \(\left(X_{n}\right)\) is a sequence of uncorrelated variables with zero means and uniformly bounded variances. Show that \(n^{-1} \sum_{i=1}^{n} X_{i} \stackrel{\mathrm{ms} .}{\longrightarrow} 0\).

Let \(X_{0}, X_{1}, X_{2} \ldots\) be a sequence of random variables with finite means and satisfying \(\mathbb{B}\left(X_{n+1} \mid\right.\) \(\left.X_{0}, X_{1}, \ldots, X_{n}\right)=a X_{n}+b X_{n-1}\) for \(n \geq 1\), where \(0

A bag contains red and green balls. A ball is drawn from the bag, its colour noted, and then it is returned to the bag together with a new ball of the same colour. Initially the bag contained one ball of each colour. If \(R_{n}\) denotes the number of red balls in the bag after \(n\) additions, show that \(S_{n}=R_{n} /(n+2)\) is a martingale. Deduce that the ratio of red to green balls converges almost surely to some limit as \(n \rightarrow \infty\).

Kolmogorov's inequality. Let \(X_{1}, X_{2}, \ldots\) be independent random variables with zero means and finite variances, and let \(S_{n}=X_{1}+X_{2}+\cdots+X_{n}\). Use the Doob-Kolmogorov inequality to show that $$ \mathrm{P}\left(\max _{1 \leq j \leq n}\left|S_{j}\right|>\epsilon\right) \leq \frac{1}{\epsilon^{2}} \sum_{j=1}^{n} \operatorname{var}\left(X_{j}\right) \quad \text { for } \epsilon>0 $$ .

3\. Random walk. Let \(X_{1}, X_{2}, \ldots\), be independent identically distributed random variables taking, values in the integers \(\mathrm{Z}\) and having a finite mean. Show that the Markov chain \(S=\left\\{S_{n} \mid\right.\) given by \(S_{n}=\sum_{1}^{n} X_{i}\) is transient if \(\mathbb{E}\left(X_{1}\right) \neq 0\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.