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You stick pins in a Mercator projection of the Farth in the manner of a Poisson process with constant intensity \(\lambda\). What is the intensity function of the corresponding process on the globe? What would be the intensity function on the map if you formed a Poisson process of constant intensity \(\lambda\) of meteorite strikes on the surface of the Earth?

Short Answer

Expert verified
The globe's intensity: \( \lambda \cos \theta \); map's intensity for meteorites: \( \frac{\lambda}{\cos \theta} \).

Step by step solution

01

Understanding the Mercator Projection

A Mercator projection is a cylindrical map projection that distorts area, particularly near the poles. In this projection, if you plot points (like pin pricks) as a Poisson process with intensity \( \lambda \), the density is uniform on the map.
02

Relating Map to Globe

The main challenge is that the uniform intensity \( \lambda \) on the Mercator map doesn't translate to a uniform intensity on the sphere because the projection distorts areas. The Mercator projection stretches areas near the poles, meaning the same number of pins (or meteorite strikes) will cover more globe surface in those regions.
03

Finding the Intensity on the Globe

Since the Mercator projection stretching changes with latitude \( \theta \), the intensity on the globe is adjusted by a factor that reflects this stretching. The intensity function \( I(\theta) \) on the globe is given as \( I(\theta) = \lambda \cos(\theta) \). This accounts for the change in area by latitude, where \( \theta \) is the polar angle from the North Pole.
04

Modifying Intensity for Meteorite Strikes

If meteorite strikes are uniformly distributed with intensity \( \lambda \) on the sphere, the corresponding Mercator map intensity must be adjusted to account for distortion. The stretching factor is \( \frac{1}{\cos(\theta)} \), thus the map intensity becomes \( \lambda \sec(\theta) = \frac{\lambda}{\cos(\theta)} \). This modifies the uniform intensity from the sphere to reflect the area's change in the projection.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mercator Projection
The Mercator projection is one of the most recognized map projections. It represents the Earth on a flat surface using a cylindrical method. Imagine wrapping a cylinder around the Earth, touching it at the equator. Then, the Earth's features are projected onto this cylinder.
  • Advantages: It preserves angles and shapes of small objects, which is great for nautical navigation.
  • Disadvantages: As you move towards the poles, it distorts sizes. For instance, Greenland appears larger than Africa, despite being much smaller.
In the context of the Mercator map, when you distribute points (like pins) in a Poisson manner with constant intensity \( \lambda \), the distribution is even on the map even though it distorts Earth’s true area. This becomes critical to understand when transitioning from flat maps to the globe because this distortion can significantly affect area representation depending on latitude.
Intensity Function
The concept of an intensity function is critical in understanding how characteristics change across different mappings, such as from a map to a globe. In probability, the intensity function describes how likely events (like pin pricks or meteorite strikes) occur over an area.
On a Mercator projection, if the distribution is uniform with intensity \( \lambda \), this needs adjusting when translated to a sphere, due to the projection's distortive nature. Specifically,
  • Areas near the equator require less adjustment since projections are truest there.
  • Areas near the poles need more adjustment due to significant stretching.
To calculate this on the globe, the function becomes \( I(\theta) = \lambda \cos(\theta) \). Here,
  • \(\theta\) is the polar angle measured from the North Pole.
  • \( \cos(\theta) \) compensates for the stretching effect seen in the Mercator's polar regions.
In contrast, to reflect uniform meteorite strikes on the globe back to the map, the intensity becomes \( \lambda \sec(\theta) = \frac{\lambda}{\cos(\theta)} \). This adjustment ensures the map's intensity properly mirrors a uniform distribution across the Earth.
Spherical Coordinates
When working with projections, we often switch from Cartesian to spherical coordinates. Spherical coordinates are particularly useful for calculations involving spheres, like Earth.
In spherical coordinates, each point in 3D space is defined using
  • \( r \) - the radial distance from the center of the sphere (on Earth, this is the radius of the Earth).
  • \( \theta \) - the polar angle measured from the positive z-axis (the North Pole).
  • \( \phi \) - the azimuthal angle in the xy-plane from the positive x-axis.
This system is incredibly beneficial for accommodating changes in scale and position as seen with the Mercator projection. It allows for a seamless transition from a two-dimensional map to the three-dimensional globe, effectively addressing issues of distortion by identifying how much one must adjust based on these angles, especially in mapping distributions such as meteorite impacts or pin placements using Poisson processes. Understanding spherical coordinates thus becomes key to translating uniform distributions from map to globe and vice versa.

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Most popular questions from this chapter

Let \(\mathrm{P}\) be the transition matrix of a Markov chain with finite state space. Let \(\mathrm{I}\) be the identity matrix, \(\mathbf{U}\) the \(|S| \times|S|\) matrix with all entries unity, and 1 the row \(|S|\)-vector with all entries unity. Let \(\pi\) be a non-negative vector with \(\sum_{i} \pi_{i}=1\). Show that \(\pi \mathbf{P}=\pi\) if and only if \(\pi(\mathbf{I}-\mathbf{P}+\mathbf{U})=1\). Deduce that if \(\mathbf{P}\) is irreducible then \(\boldsymbol{\pi}=\mathbf{1}(\mathbf{I}-\mathbf{P}+\mathbf{U})^{-1} .\)

Let \(X\) be an irreducible continuous-time Markov chain on the state space \(S\) with transition probabilities \(p_{j k}(t)\) and unique stationary distribution \(\pi\), and write \(\mathrm{P}(X(t)=j)=a_{j}(t)\). If \(c(x)\) is a concave function, show that \(d(t)=\sum_{i \in S} \pi_{j} c\left(a_{j}(t) / \pi_{j}\right)\) increases to \(c(1)\) as \(t \rightarrow \infty\)

Consider the symmetric random walk in three dimensions on the set of points \((x, y, z): x, y, z=\) \(0, \pm 1, \pm 2, \ldots, 1 ;\) this process is a sequence \(\left[\mathbf{X}_{n}: n \geq 0\right]\) of points such that \(\mathbb{P}\left(\mathbf{X}_{n+1}=\mathbf{X}_{n}+\epsilon\right)=\frac{1}{6}\) for \(\epsilon=(\pm 1,0,0),(0, \pm 1,0),(0,0, \pm 1)\). Suppose that \(\mathbf{X}_{0}=(0,0,0)\). Show that $$ \mathrm{P}\left(\mathbf{X}_{2 n}=(0,0,0)\right)=\left(\frac{1}{6}\right)^{2 n} \sum_{i+j+k=n} \frac{(2 n) !}{(i) j ! k !)^{2}}=\left(\frac{1}{2}\right)^{2 n}\left(\begin{array}{c} 2 n \\ n \end{array}\right) \sum_{i+j+h=n}\left(\frac{n !}{3^{n} i 1 j ! k !}\right)^{2} $$ and deduce by Stirling's formula that the origin is a transient state.

Let \(s\) be a state of an irreducible Markov chain on the non-negative integers. Show that the chain is persistent if there exists a solution \(y\) to the equations \(y_{i} \geq \sum_{j: j \neq_{x}} p_{i j} y_{j}, i \neq s\), satisfying \(y_{i} \rightarrow \infty\).

Let \(B\) be a simple birth process \((6.8 .11 \mathrm{~b})\) with \(B(0)=I ;\) the birth rates are \(\lambda_{n}=n \lambda\). Write down the forward system of equations for the process and deduce that $$ \mathrm{P}(\boldsymbol{B}(t)=k)=\left(\begin{array}{c} k-1 \\ I-1 \end{array}\right) e^{-I \lambda t}\left(1-e^{-\lambda t}\right)^{k-1}, \quad k \geq 1 $$ Show also that \(\mathbb{E}(B(t))=I e^{\lambda t}\) and \(\operatorname{var}(B(t))=1 e^{2 \lambda t}\left(1-e^{-\lambda t}\right) .\)

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