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Show that the sum of two independent binomial variables, \(\operatorname{bin}(m, p)\) and bin \((n, p)\) respectively, is bin \((m+n, p)\)

Short Answer

Expert verified
The sum of two independent binomial variables with the same probability is a binomial variable with parameters \(m+n\) and \(p\).

Step by step solution

01

Understand the Binomial Distribution

A binomial distribution with parameters \(m\) and \(p\) is denoted as \( \operatorname{bin}(m, p) \), where \(m\) is the number of trials and \(p\) is the probability of success on each trial. The random variable represents the number of successes in \(m\) trials.
02

Define the Random Variables

Let \(X\) represent the number of successes in the \( \operatorname{bin}(m, p) \) distribution and \(Y\) represent the number of successes in the \( \operatorname{bin}(n, p) \) distribution. Thus, \(X \sim \operatorname{bin}(m, p)\) and \(Y \sim \operatorname{bin}(n, p)\), and both are independent random variables.
03

Define the Sum of Random Variables

Consider the sum of the two variables: \(Z = X + Y\). This new variable \(Z\) represents the sum of two independent binomial random variables.
04

Determine the Distribution of the Sum

Since \(X\) and \(Y\) are independent, the sum \(Z = X + Y\) can be shown to have a binomial distribution itself. Specifically, \(Z\) is binomial with the number of trials equal to the sum of the trials of \(X\) and \(Y\), that is \(m + n\), and having the same probability \(p\). Thus, \(Z \sim \operatorname{bin}(m+n, p)\).
05

Conclusion

We have shown that adding two independent binomial random variables \( \operatorname{bin}(m, p) \) and \( \operatorname{bin}(n, p) \) results in another binomial variable with parameters \(m + n\) and \(p\), confirming \(Z \sim \operatorname{bin}(m+n, p)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Random Variables
When we talk about independent random variables, we're referring to random variables that do not influence one another. This means that the result of one variable does not affect the outcome of the other, and their joint probability distribution can be represented as the product of their individual distributions. In other words, knowing the outcome of one variable gives us no information about the other.

In the context of the exercise where we have two binomial variables, \(X \sim \operatorname{bin}(m, p)\) and \(Y \sim \operatorname{bin}(n, p)\), independence is crucial. It implies that the trials in variable \(X\) do not affect the trials in variable \(Y\). Since they are independent, the occurrence or non-occurrence of success in one group's trials does not influence the other.

  • Independent random variables have no correlation, meaning they move without any relation to each other.
  • They are central to many statistical concepts and ensure simplicity in calculating joint probabilities.
Understanding the independence of random variables allows us to work with each variable separately and combine their effects cleanly.
Sum of Random Variables
Adding random variables is a common operation in statistics. When two independent random variables are added, the resultant variable represents their sum.

In the exercise provided, we're looking at the sum of two independent binomial random variables \(X\) and \(Y\). The new variable formed by this sum is \(Z = X + Y\).

Since both \(X\) and \(Y\) are binomial variables and independent, the distribution of their sum \(Z\) becomes a binomial distribution as well, but with the number of trials equal to the sum of their trials: \(m + n\).
  • The resulting distribution from the sum retains the same probability of success \(p\) since both variables share this probability.
  • The principle that allows the distribution to remain binomial after addition hinges on the independence and the nature of identical trial probabilities.
This concept is critical as it simplifies analysis and allows us to assess the combined effect of two or more processes consistently.
Probability of Success
The probability of success \(p\) in a binomial distribution refers to the chance of achieving a successful outcome in a single trial. It remains constant across all trials in the binomial process, contributing to the binomial nature of the distribution itself.

In our provided exercise, both binomial variables \(X\) and \(Y\) share the same probability of success \(p\) for each individual trial in their respective distributions. This shared probability is what enables the maintenance of a consistent probability structure when their sum is taken.
  • A constant \(p\) ensures that each trial is independent and identically distributed, an essence of a binomial variable.
  • Having the same \(p\) when summing binomial variables simplifies the computation of the resulting distribution's properties.
Thus, the notion of a fixed probability of success \(p\) not only defines a binomial setting but also smooths the process of analyzing the sum of such variables.

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Most popular questions from this chapter

A biased coin is tossed \(n\) times, and heads shows with probability \(p\) on each toss. A run is a sequence of throws which result in the same outcome, so that, for example, the sequence HHTHTTH contains five runs. Show that the expected number of runs is \(1+2(n-1) p(1-p)\). Find the variance of the number of runs.

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