Chapter 9: Problem 5
A branching process \(\left(X_{n}: n \geq 0\right.\) ) has \(\mathbb{P}\left(X_{0}=1\right)=1\). Let the total number of individuals in the first \(n\) generations of the process be \(Z_{n}\), with probability generating function \(Q_{n} .\) Prove that, for \(n \geq 2\), $$ Q_{n}(s)=s P_{1}\left(Q_{n-1}(s)\right) $$ where \(P_{1}\) is the probability generating function of the family-size distribution. (Oxford \(1974 \mathrm{~F}\) )
Short Answer
Step by step solution
Recall the Basics of a Branching Process
Define the Total Number of Individuals Function
Establish the Recursive Property of \(Z_n\)
Examine the Probability Generating Functions
Derive the Generating Function Relationship
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Probability Generating Function
Family-Size Distribution
Recursive Property
- The term \(s\) accounts for an individual present in the current generation.
- \(P_1(Q_{n-1}(s))\) incorporates the distribution of offspring from all individuals in the previous generations.