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Consider the multivariable linear function $$y=78.1+0.83 x_{1}-0.09 x_{2}+1.19 x_{3}$$ Evaluate this function for the given explanatory values. $$x_{1}=63, x_{2}=21, x_{3}=17$$

Short Answer

Expert verified
The value of \(y\) is 148.73.

Step by step solution

01

Substitute Values into the Function

First, we need to substitute the given values of \(x_1\), \(x_2\), and \(x_3\) into the function. The values are \(x_1 = 63\), \(x_2 = 21\), and \(x_3 = 17\). The original function is \(y = 78.1 + 0.83x_1 - 0.09x_2 + 1.19x_3\). Substituting the values, we get:\[y = 78.1 + 0.83(63) - 0.09(21) + 1.19(17)\]
02

Calculate Each Term

Now, calculate each term separately:- The first term is \(78.1\).- The second term is \(0.83 \times 63 = 52.29\).- The third term is \(-0.09 \times 21 = -1.89\).- The fourth term is \(1.19 \times 17 = 20.23\).
03

Sum All the Terms

Add all the calculated terms together to obtain the value of \(y\):\[y = 78.1 + 52.29 - 1.89 + 20.23\]
04

Final Calculation

Compute the sum from the previous step to find the value of \(y\).\[y = 148.73\]Thus, the value of \(y\) when \(x_1 = 63\), \(x_2 = 21\), and \(x_3 = 17\) is 148.73.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Explanatory Variables
In the realm of multivariable linear functions, explanatory variables are those variables that help to explain variations or patterns we observe in the dependent variable, often denoted as \(y\). Simply put, they are inputs that influence the output, and in this case, they are represented by \(x_1\), \(x_2\), and \(x_3\) in the function.
Let's break it down:
  • \(x_1\), \(x_2\), and \(x_3\) are distinct characteristics or metrics that have some impact on the result \(y\).
  • Each explanatory variable is multiplied by a coefficient, representing its magnitude of influence.
  • These coefficients can be positive or negative, indicating whether an increase in the explanatory variable increases or decreases \(y\).
Therefore, understanding these variables is crucial to understand how changes in inputs affect outcomes, as shown in our function: \(y = 78.1 + 0.83x_1 - 0.09x_2 + 1.19x_3\).
Each term in the function reveals the potential change in \(y\) given a unit change in the corresponding explanatory variable.
Linear Equations in Statistics
Linear equations in statistics are foundational in explaining relationships between variables. They serve as a predictive tool, allowing us to anticipate the behavior of one variable based on known changes in another. This particularly applies to our function, where
  • The function format \(y = \beta_0 + \beta_1x_1 + \beta_2x_2 + \beta_3x_3\) is typical in linear models.
  • The term \(\beta_0\) is the intercept, signifying where the line crosses the y-axis. It's the value of \(y\) when all \(x\) terms are zero.
  • Each \(\beta\) associated with \(x\) is a slope, showing how much \(y\) changes for a one-unit increase in the explanatory variable.
These equations model real-world data, making it easier to understand trends and make predictions.
By fitting a linear equation to data, we can identify relationships and potential causal effects, providing insights grounded in statistical reality. This is key in fields widespread, from economics to engineering.
Calculating Function Values
Calculating function values is a practical process of plugging values into the equation and solving to find the outcome—the dependent variable \(y\). To calculate it accurately, follow these steps:
  • Start with the function equation, given by \(y = 78.1 + 0.83x_1 - 0.09x_2 + 1.19x_3\).
  • Substitute the provided values: \(x_1 = 63\), \(x_2 = 21\), \(x_3 = 17\).
  • Perform multiplication for each explanatory variable: calculate \(0.83 \times 63\), \(-0.09 \times 21\), \(1.19 \times 17\).
  • Add the results, starting with a constant, \(78.1\), modified by the outcomes of these multiplications.
This step-by-step calculation leads us to find \(y = 148.73\), providing a specific value for \(y\) based on given input values.
Understanding this process helps demystify how changes in inputs trigger changes in output—a fundamental aspect of analyzing linear functions.

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